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AP® Biology · Unit 6 · Topic 6.1

DNA and RNA Structure: Revision Notes (Biology 6.1)

One-page recap of how genetic material is stored and organised: circular and linear chromosomes, histones, plasmids, purines and pyrimidines, and the pairing rules.

Short on time? This page is the recap. For explanations, figures and worked examples, use the full study guide.

Recap

  • Genetic information is stored in, and passed on through, DNA. Some viruses (for example influenza viruses and HIV) use RNA instead.
  • Prokaryotes typically have one circular chromosome in the nucleoid region, with no nuclear envelope. It is packed by supercoiling.
  • Eukaryotes typically have several linear chromosomes in the nucleus. DNA wraps around histone proteins (nucleosomes, “beads on a string”) and is folded further.
  • Histones are positively charged; the DNA backbone is negatively charged. The attraction holds DNA on the histones.
  • Plasmids are small, circular, extra-chromosomal DNA molecules. They are common in bacteria and also occur in some eukaryotes, such as yeasts. They often carry genes such as antibiotic resistance and can pass between cells.
  • Pairing rules are the same in all known cellular life: evidence of common ancestry.

Key relationships

Feature Prokaryote Eukaryote
Chromosome shape typically circular typically linear
Number of chromosomes typically one several
Location nucleoid (cytoplasm) nucleus
Packing supercoiling and proteins histones (nucleosomes) and further folding
Plasmids common in some (for example yeasts)
Base group Rings Bases Pairs with
Purines double A, G a pyrimidine
Pyrimidines single C, T (DNA), U (RNA) a purine

Pairs: A–T (DNA), A–U (RNA), G–C. One purine + one pyrimidine = three rings = constant helix width.

Assumptions behind the numbers

  • “Purines = pyrimidines = 50%” applies only to double-stranded molecules, where every base is paired.
  • Length calculations use a model value of about 0.34 nm per base pair.

Mistakes to avoid

  1. Saying prokaryotes have no chromosome.
  2. Saying all genetic material is DNA.
  3. Swapping purines and pyrimidines: purines are the double-ringed A and G.
  4. Pairing two purines (A–G) or two pyrimidines (C–T).
  5. Calling histones DNA; they are proteins.
  6. Applying the 50% purine rule to a single strand.

Quick self-check

  1. A double-stranded DNA molecule has 2 000 base pairs. How many purines does it contain? (4 000 nucleotides, half are purines: 2 000)
  2. Double-stranded DNA is 22% C. What are G, A and T? (G = 22%; purines total 50%, so A = 50 − 22 = 28% and T = 28%)
  3. Give two ways a bacterial chromosome differs from a human chromosome. (circular, not linear; in the cytoplasm, not a nucleus; not wound around histones; usually only one)

Next: practice questions.

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