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AP® Biology · Unit 8 · Topic 8.7

Disruptions in Ecosystems: Revision Notes (Biology 8.7)

One-page recap of selection on existing variation, heterozygote advantage, invasive species, biomagnification, eutrophication and geological events, with the chi-square steps and common mistakes.

Short on time? This page is the recap. For explanations, figures and worked examples, use the full study guide.

Recap

  • An adaptation is a heritable variation that gives an advantage in a particular environment. Mutations arise at random; a changed environment favours variants that already exist.
  • Heterozygote advantage: the heterozygote has a higher relative fitness than either homozygote, so both alleles persist (for example, sickle-cell trait where falciparum malaria is common).
  • Invasive species spread by escaping their predators and diseases, using an open niche, or outcompeting natives (kudzu, zebra mussels).
  • Human activity accelerates change: habitat loss (logging, urbanisation), monocropping (potato blight), introduced diseases (Dutch elm disease), climate change, biomagnification and eutrophication. Fast change can cause extinctions.
  • Geological and meteorological events (El Niño, continental drift, the meteor impact about 66 million years ago) change habitats and species distributions.

Key relationships

Disruption Mechanism Typical outcome
New selective pressure existing variants survive and reproduce more allele frequencies shift
Invasive species few enemies, open niche or better competitor natives decline; food web shifts
Biomagnification persistent, fat-soluble toxin kept as biomass is passed up top predators most contaminated
Eutrophication nutrients → algal bloom → death → decomposers use O₂ low-oxygen dead zone, fish deaths
Monocropping one genetically uniform crop whole crop vulnerable to one pathogen
El Niño warm surface water, weak upwelling, fewer nutrients plankton, fish and seabirds decline
Chi-square step What to write
Null hypothesis “No difference / no effect”, with the expected ratio
Expected counts total × expected proportion
χ² = Σ (o − e)² ÷ e one term per category
Degrees of freedom categories − 1
Compare (p = 0.05) 3.84 (1 df), 5.99 (2), 7.81 (3)

Assumptions behind the numbers

  • Chi-square uses counts, not percentages or means, and each expected count should be reasonably large.
  • Concentration factors in a food chain vary: transfer is not exactly 10% per level.
  • Rejecting the null shows an association; a controlled comparison is needed to identify the cause.

Mistakes to avoid

  1. Saying the environment “causes” helpful mutations.
  2. Blaming living algae, not decomposers, for the oxygen crash.
  3. Calling every introduced species invasive.
  4. Using percentages instead of counts in χ².
  5. Writing “accept the null hypothesis” or “prove”. Use “fail to reject” and “support”.
  6. Forgetting to state the direction of the difference after rejecting the null.

Quick self-check

  1. A toxin at 0.02 ppm in algae increases 10 times at each of three steps. Concentration in the top consumer? (0.02 × 10 × 10 × 10 = 20 ppm)
  2. Equal numbers of seedlings are planted in soils A and B. Of the 80 that survive, 30 are in soil A and 50 in soil B. The null predicts 40 and 40. Conclusion? (χ² = 2.5 + 2.5 = 5.0 > 3.84 with 1 df, so reject the null.)
  3. Why does oxygen fall after an algal bloom ends? (Dead algae are broken down by aerobic decomposers, whose respiration uses oxygen.)

Next: practice questions.

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