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Flashcards · AP® Biology · Unit 5
Unit 5: Heredity flashcards
38 cards on topics 5.1 to 5.5. Pick a topic or study the whole unit.
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5.1 Meiosis
- What does meiosis produce?
- One diploid (2n) cell becomes four haploid (n), genetically different cells. In animals these become gametes; fertilization restores 2n. DNA replicates once, before meiosis; there is no S phase between meiosis I and II.
- How do homologous chromosomes differ from sister chromatids?
- Homologues come one from each parent, carry the same genes in the same order, but may have different alleles. Sister chromatids are identical copies made in S phase, joined at the centromere.
- What separates in anaphase I and in anaphase II?
- Anaphase I: homologous chromosomes separate while sister chromatids stay joined. Anaphase II: centromere proteins break down and sister chromatids separate.
- Which stage of meiosis halves the chromosome number, and why?
- Anaphase I with telophase I: homologues go to different cells, so each cell gets one of each pair. Cells at the end of meiosis I are haploid even though their chromosomes still have two chromatids.
- How do chromosome and chromatid numbers change in meiosis?
- Start 2n. Prophase I to metaphase I: 2n chromosomes, 4n chromatids. End of meiosis I: n chromosomes, 2n chromatids. End of meiosis II: n chromosomes, n chromatids. For 2n = 16, metaphase I has 16 chromosomes and 32 chromatids.
- How do chromosomes line up in metaphase I and metaphase II?
- Metaphase I: homologous pairs line up at the plate. Metaphase II: chromosomes line up in single file, with the kinetochores of the two sister chromatids attached to microtubules from opposite poles.
- How does meiosis compare with mitosis?
- Mitosis: 1 division, 2 cells, 2n, genetically identical. Meiosis: 2 divisions, 4 cells, n, genetically different. Both use a spindle, the same stage names, and cytokinesis by furrow or cell plate.
5.2 Meiosis and Genetic Diversity
- What is crossing over, and what does it do?
- In prophase I, non-sister chromatids of a homologous pair swap matching segments at chiasmata. This makes recombinant chromatids with new combinations of existing alleles; it does not create new alleles.
- What is independent assortment?
- Each homologous pair lines up at metaphase I independently of the others, so whole chromosomes are shuffled into gametes. It happens in metaphase I, not metaphase II.
- How many chromosome combinations can gametes have?
- 2ⁿ, ignoring crossing over. Humans (n = 23): 2²³ ≈ 8.4 million. For 2n = 12, n = 6 gives 2⁶ = 64. Do not use 2n or n².
- How does random fertilization add variation?
- Any gamete from one parent can fuse with any gamete from the other. For one human couple that gives 2²³ × 2²³ = 2⁴⁶ ≈ 7.0 × 10¹³ combinations, before crossing over.
- What is nondisjunction and what does it cause?
- Failure of homologues (meiosis I) or sister chromatids (meiosis II) to separate, giving gametes that are not haploid. Fertilization then gives 2n + 1 (trisomy) or 2n − 1 (monosomy) zygotes.
- How do gametes differ after nondisjunction in meiosis I versus meiosis II?
- Meiosis I: n + 1, n + 1, n − 1, n − 1 (all abnormal). Meiosis II in one cell: n, n, n + 1, n − 1. For n = 6, meiosis II nondisjunction gives 6, 6, 7, 5.
- Why can all four products of one meiosis differ genetically?
- Crossing over makes sister chromatids non-identical, so the two cells of meiosis II receive different chromatids.
5.3 Mendelian Genetics
- What is the law of segregation?
- Each gamete gets one allele of each gene, because homologous chromosomes separate in meiosis I.
- What is the law of independent assortment?
- Genes on different chromosomes are sorted independently because each homologous pair lines up at metaphase I independently. Linked genes on the same chromosome are the exception.
- What are the standard Mendelian cross ratios?
- Aa × Aa: 1 AA : 2 Aa : 1 aa, phenotypes 3 : 1. Aa × aa: 1 : 1. AaBb × AaBb: 9 : 3 : 3 : 1. AaBb × aabb: 1 : 1 : 1 : 1. Check whether the question asks for genotypic or phenotypic ratio.
- When do you multiply and when do you add probabilities in genetics?
- Multiply for independent events (separate genes, separate children): P(A and B) = P(A) × P(B). Add for mutually exclusive routes to one outcome: P(Aa) = 1/4 + 1/4 = 1/2.
- What is the probability that an unaffected child of two carriers is a carrier?
- 2/3, not 1/2. Of the unaffected outcomes (AA, Aa, Aa), two of three are carriers.
- How do you carry out a chi-square test on a genetic cross?
- χ² = Σ (o − e)² ÷ e using counts, df = categories − 1, compare with the critical value at p = 0.05. 290 : 110 against 3 : 1 (expected 300 : 100): χ² = 1.33, below 3.84, so fail to reject the null hypothesis.
- What pedigree clues tell dominant from recessive inheritance?
- Two unaffected parents with an affected child: recessive. Two affected parents with an unaffected child: dominant. A recessive trait in a daughter whose father is unaffected: autosomal, not X-linked.
- Why is a test cross made with a homozygous recessive?
- It gives only recessive alleles, so each offspring's phenotype reveals the allele from the unknown parent.
5.4 Non-Mendelian Genetics
- How do incomplete dominance and codominance differ?
- Incomplete dominance: the heterozygote is a blend (red × white → pink). Codominance: the heterozygote shows both phenotypes fully (blood group AB, IᴬIᴮ). Both give 1 : 2 : 1 phenotypes from a heterozygote cross.
- How do you detect linked genes in a test cross?
- Instead of 1 : 1 : 1 : 1, there are two large (parental) classes and two small (recombinant) classes. Linked genes are on the same chromosome and tend to be inherited together.
- How do you calculate recombination frequency and map distance?
- Recombination frequency (%) = recombinants ÷ total offspring × 100; 1% = 1 map unit. 45 recombinants among 300: 15 map units. Divide by the total, not by parental types.
- What are the clues for X-linked recessive inheritance?
- More affected males; never passed father to son; can skip a generation through carrier daughters. Males (XY) have one X, so one recessive allele shows. Fathers pass X to every daughter and Y to every son.
- Why are Z-linked recessive traits more common in female birds?
- Birds are ZW (female) and ZZ (male), so females have one Z and a single recessive allele on it is expressed.
- What is pleiotropy?
- One gene with several effects, such as the sickle-cell allele causing anaemia, organ damage and malaria resistance in heterozygotes. The traits always appear together, with no recombinants.
- How are mitochondrial and chloroplast genes inherited?
- Organelles are randomly shared out at division and usually come from the egg or ovule, so traits are typically maternal. Reciprocal crosses differ and offspring match the mother.
- How do you test whether data deviate from Mendelian ratios?
- Use chi-square to compare observed counts with the Mendelian prediction. If χ² exceeds the critical value, reject the Mendelian null hypothesis and look for a biological cause such as linkage or sex linkage.
5.5 Environmental Effects on Phenotype
- How does the environment affect phenotype?
- Environmental signals (temperature, day length, light, diet, soil chemistry, other organisms) change which genes are expressed and how much, or how well a gene product works. The DNA sequence is not changed.
- What is phenotypic plasticity?
- The ability of one genotype to produce different phenotypes in different environments. The responses are not inherited as such; offspring inherit the alleles, including the ability to respond.
- How does temperature determine sex in many reptiles?
- In most such turtles, warm incubation raises aromatase expression, converting more testosterone to oestrogen, so ovaries develop (females). Cool eggs give males.
- Why do Siamese cats have dark paws?
- Their tyrosinase is heat-sensitive and only makes melanin in the cooler skin of the extremities.
- Why does hydrangea flower colour vary?
- In acidic soil, aluminium is taken up and flowers are blue; in alkaline soil they are pink. Same genotype, different environment.
- How do you show a trait difference is environmental?
- Hold genotype constant with clones, inbred lines or identical twins, and control other variables. Using seedlings of different genotypes does not isolate the environment.
- How do you read a reaction norm graph?
- Flat line: trait not plastic for that factor. Steep line: very plastic. Parallel lines: genotypes differ by a constant amount. Crossing lines: genotype-by-environment interaction, so the "better" genotype depends on the environment.
- How can diet change the phenotype of phenylketonuria?
- A low-phenylalanine diet prevents brain damage in people with two recessive alleles; the genotype is unchanged.
Study Unit 5 further
- 5.1 Meiosis Study guide: 5.1 MeiosisRevision notes: 5.1 MeiosisPractice questions: 5.1 Meiosis
- 5.2 Meiosis and Genetic Diversity Study guide: 5.2 Meiosis and Genetic DiversityRevision notes: 5.2 Meiosis and Genetic DiversityPractice questions: 5.2 Meiosis and Genetic Diversity
- 5.3 Mendelian Genetics Study guide: 5.3 Mendelian GeneticsRevision notes: 5.3 Mendelian GeneticsPractice questions: 5.3 Mendelian Genetics
- 5.4 Non-Mendelian Genetics Study guide: 5.4 Non-Mendelian GeneticsRevision notes: 5.4 Non-Mendelian GeneticsPractice questions: 5.4 Non-Mendelian Genetics
- 5.5 Environmental Effects on Phenotype Study guide: 5.5 Environmental Effects on PhenotypeRevision notes: 5.5 Environmental Effects on PhenotypePractice questions: 5.5 Environmental Effects on Phenotype
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