Skip to content
Marlbridge

AP® Calculus AB · Unit 2 · Topic 2.4

Connecting Differentiability and Continuity: Revision Notes (Calculus AB 2.4)

One-page recap of how differentiability and continuity are linked, the four ways a derivative fails to exist, and how to justify it with one-sided difference quotients.

Short on time? This page is the recap. For explanations, Figure 1 and worked examples, use the full study guide. This topic is shared by Calculus AB and Calculus BC.

Notation: f′(a) = lim (h → 0) (f(a + h) − f(a))/h; h → 0⁻ means from the left, h → 0⁺ from the right.

Recap

  • f′(a) exists only if both one-sided limits of the difference quotient exist, are finite and are equal.
  • Differentiable at a ⇒ continuous at a. Reason: f(x) − f(a) = [difference quotient] × (x − a) → f′(a) × 0 = 0.
  • Contrapositive: a hole, jump or asymptote at a means f′(a) does not exist.
  • Domain: if f(a) is undefined, f′(a) is undefined, even if the graph “looks” like a line through the hole.
  • Converse is false: a continuous function can have a corner, cusp or vertical tangent.

Key relationships

Feature at x = a Continuous? Difference quotient f′(a)?
Smooth graph Yes One finite limit Exists
Corner Yes Finite one-sided limits that differ Does not exist
Cusp Yes −∞ on one side, +∞ on the other Does not exist
Vertical tangent Yes Unbounded, same sign both sides Does not exist
Hole, jump or asymptote No Not needed: use the theorem Does not exist

Assumptions behind the method

  • One-sided quotients must use the actual f(a), from whichever piece includes a.
  • For a piecewise function, check continuity first, then compare the one-sided limits.
  • Absolute values only cause corners where the inside changes sign.

Mistakes to avoid

  1. Reversing the theorem: “continuous, so differentiable” or “not differentiable, so not continuous”.
  2. Matching slopes but ignoring a jump between the pieces.
  3. Writing f′(a) = ∞ for a vertical tangent. Say it does not exist.
  4. “It’s sharp” with no limits. Give the two one-sided values.
  5. Trusting a calculator’s numerical derivative at a corner; it averages the two sides.
  6. Assuming a formula with |x| has a corner. Check: x|x| is differentiable at 0.

Quick self-check

  1. f′(5) exists. Must f be continuous at 5? (Yes: differentiability implies continuity.)
  2. f is continuous at 0. Must f′(0) exist? (No: for example, a corner.)
  3. Is |2x − 6| differentiable at x = 3? (No: the one-sided limits of the quotient are −2 and 2.)

Next: practice questions.

AP® and Advanced Placement® are trademarks registered by the College Board, which is not affiliated with, and does not endorse, this website. Marlbridge is an independent tuition provider. It is not an authorized AP course provider, an AP school or an exam centre, and these resources are not official College Board materials. Reading them or doing simulations does not meet the laboratory requirement of an AP science course.