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AP® Calculus AB · Unit 5 · Topic 5.11

Solving Optimization Problems: Revision Notes (Calculus AB 5.11)

One-page recap of solving optimization problems: the ways to justify an absolute extremum, answering the exact question asked and writing a clear interpretation in context.

Short on time? This page is the recap. For the graphs and worked examples, use the full study guide. This topic is shared by Calculus AB and Calculus BC.

Recap

  • Start from the model built in Topic 5.10: one function of one variable, with its domain.
  • Find the critical points: where the derivative is 0 or does not exist, inside the domain.
  • Justify that your answer is the absolute maximum or minimum. The method depends on the domain (table below).
  • Give exactly what is asked: the location (an input), the extreme value (an output) or a quantity that follows from them.
  • Interpret: name the quantity, give the value with units, and say when or where it happens.

Key relationships

Situation Valid justification
Closed domain [a, b] Candidates Test: compare f at every critical point and at a and b
Open domain, only one critical point c f′ changes sign at c: − to + gives the absolute minimum, + to − the absolute maximum
Open domain, only one critical point c f″(c) > 0 gives the absolute minimum; f″(c) < 0 the absolute maximum
Any domain f″ > 0 on the whole domain: a critical point is the absolute minimum (f″ < 0: absolute maximum)
The function measures… Its maximum value means…
An amount (profit, area, volume) the most of that amount the model allows
A rate (litres per minute, cars per minute) the fastest rate, not the largest total
A cost, length or time to be minimised (its minimum) the least possible cost, length or time

Assumptions behind the method

  • The function is differentiable (or at least continuous) on the domain, so its extreme values occur at critical points or endpoints.
  • The domain matches the situation: lengths positive, times within the stated period, capacities respected.
  • The model is only a model. The answer is the best value under the model.

Mistakes to avoid

  1. Stopping at f′(x) = 0 without a justification.
  2. Forgetting endpoints on a closed interval.
  3. Using f″(c) < 0 alone for an absolute maximum.
  4. Answering “where” when the question asks “what”, or the reverse.
  5. Keeping solutions outside the domain, such as a negative length.
  6. No units, or “it” instead of the function’s name.
  7. Rounding too early on calculator questions. Give final answers to three decimal places.

Quick self-check

  1. On [0, 10], f has one critical point at x = 4 with f(4) = 7, and f(0) = 2, f(10) = 9. What is the absolute maximum value? (9, at x = 10: the endpoint wins)
  2. On x > 0, g has only one critical point, at x = 5, and g″(5) > 0. What can you conclude? (g(5) is the absolute minimum of g on x > 0)
  3. R(t) is a rate in litres per minute, and R has its maximum at t = 12. What happens at t = 12? (The liquid flows fastest: the greatest number of litres per minute. It is not when the most liquid has flowed in total.)

Next: practice questions.

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