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AP® Calculus BC · Unit 10 · Topic 10.3

The nth Term Test for Divergence: Revision Notes (Calculus BC 10.3)

One-page recap of the nth term test: why convergent series have terms that approach 0, how to write the divergence justification, and the inconclusive case.

Short on time? This page is the recap. For the proof, the graph and worked examples, use the full study guide. BC-only material. Prerequisites (limits at infinity 1.15, L’Hospital’s Rule 4.7, partial sums 10.1, geometric series 10.2) are on the Calculus BC roadmap.

Recap

  • A series has a sequence of terms aₙ and a sequence of partial sums Sₙ = a₁ + … + aₙ. It converges when Sₙ has a finite limit.
  • Since aₙ = Sₙ − Sₙ₋₁, a convergent series must have aₙ → S − S = 0.
  • So if aₙ does not approach 0, the series diverges. This is the nth term test.
  • The test never proves convergence.
  • Used forwards: if you know ∑ aₙ converges, you may use aₙ → 0 in a limit.

Key relationships

Limit of the terms Conclusion Example
Non-zero number L Diverges ∑ 3n/(4n + 1): aₙ → 3/4
±∞ Diverges ∑ (1.02)ⁿ: aₙ → ∞
Does not exist (oscillates) Diverges ∑ (−1)ⁿ n/(3n + 2): aₙ swings between about ±1/3
0 No conclusion; use another method 1 + ½ + ½ + ⅓ + ⅓ + ⅓ + …: terms → 0, but each block adds 1, so it diverges

Model justification: “lim (n → ∞) of aₙ = … ≠ 0, so by the nth term test, ∑ aₙ diverges.”

Finding the limit

  • Rational terms: compare the highest powers (equal powers → ratio of leading coefficients).
  • 1^∞, ∞ · 0, 0/0 forms: rewrite with a continuous x and use logarithms or L’Hospital’s Rule. Example: (1 + 2/n)ⁿ → e².
  • Terms with a factor (−1)ⁿ: check the size first. If the size approaches a non-zero number, the terms swing and the limit does not exist.
  • The starting index and the first few terms never affect the limit.

Mistakes to avoid

  1. Writing “converges” because aₙ → 0.
  2. Saying the series “converges to L” because the terms approach L.
  3. Calling an oscillating limit “inconclusive”. If the limit does not exist, it is not 0: diverges.
  4. Treating (1 + k/n)ⁿ as → 1. It tends to eᵏ.
  5. Leaving out the limit value or the name of the test in a justification.

Quick self-check

  1. ∑ (4n + 1)/(9n − 2)? (aₙ → 4/9 ≠ 0, diverges)
  2. ∑ n²/(n³ + 1)? (aₙ → 0, nth term test inconclusive)
  3. ∑ cos(1/n)? (aₙ → cos 0 = 1 ≠ 0, diverges)

Next: practice questions.

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