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AP® Calculus BC · Unit 7 · Topic 7.9

Logistic Models with Differential Equations: Revision Notes (Calculus BC 7.9)

One-page recap of logistic models: the equation and its forms, carrying capacity, long-run limits, fastest growth at half capacity, concavity, and the mistakes to avoid.

Short on time? This page is the recap. For the graphs and worked examples, use the full study guide. BC-only material. Prerequisites (Topics 7.1, 7.4 and 7.8, and concavity from Unit 5) are on the Calculus BC roadmap.

Recap

  • Logistic growth: the rate is jointly proportional to the amount y and to the room left, a − y.
  • So dy/dt = ky(a − y) with k > 0. The constant a is the carrying capacity.
  • Growth starts almost exponentially, slows down, and levels off at a.
  • You can read everything you need from the equation and the initial condition. No solving needed.

Key relationships

Feature How to find it Example: dy/dt = 0.03y(90 − y)
Carrying capacity a in ky(a − y) 90
Constant solutions y = 0 and y = a y = 0, y = 90
Long-run limit a if y(0) > 0; 0 if y(0) = 0 90
y when changing fastest a/2 45
Greatest rate ka²/4 = k(a/2)(a/2) 0.03 × 45 × 45 = 60.75
Second derivative d²y/dt² = k(a − 2y) · dy/dt Inflection at y = 45
Other form ry(1 − y/a) with r = ka 2.7y(1 − y/90)

Behaviour by starting value

y(0) What y does Concavity
0 or a Stays constant None
Between 0 and a/2 Increases to a; S-shaped Up, then down after y = a/2
Between a/2 and a Increases to a Down
Above a Decreases to a Up

Mistakes to avoid

  1. Reading a from the wrong place. Rewrite as ky(a − y) first. For 0.6y − 0.002y², factor: 0.002y(300 − y), so a = 300.
  2. “Fastest at a.” The rate is 0 at a. Fastest is at a/2.
  3. Answering with a time when the question asks for the value of y.
  4. Forgetting the chain rule in d²y/dt²: differentiate with respect to t, so dy/dt appears.
  5. Assuming growth. If y(0) > a, the quantity falls.

Quick self-check

  1. For dy/dt = 0.03y(90 − y) with y(0) = 10, find the limit as t → ∞ and the value of y when it grows fastest. (90; 45)
  2. Find the carrying capacity of dP/dt = 0.6P − 0.002P². (Factor: 0.002P(300 − P), so 300.)
  3. A logistic quantity starts at y(0) = 0. What is its limit? (0: it is a constant solution.)
  4. For dy/dt = ky(a − y) with y(0) > a, is y increasing or decreasing? (Decreasing, towards a.)

Next: practice questions.

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