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AP® Calculus BC · Unit 9 · Topic 9.7

Defining Polar Coordinates and Differentiating in Polar Form: Revision Notes (Calculus BC 9.7)

One-page recap of polar coordinates: converting points and equations, the parametric form of r = f(θ), dy/dx and d²y/dx², tangents, and what dr/dθ means.

Short on time? This page is the recap. For the figure, explanations and worked examples, use the full study guide. BC-only material. Prerequisites (parametric dy/dx 9.1, parametric second derivatives 9.2, product and chain rules) are on the Calculus BC roadmap.

Recap

  • (r, θ) means: face along the ray at angle θ from the positive x-axis, then go r units. Negative r means go backwards.
  • A point has many polar names: (r, θ), (r, θ + 2π) and (−r, θ + π) are all the same point.
  • For r = f(θ), write x = f(θ) cos θ, y = f(θ) sin θ and use the parametric methods of Topics 9.1 and 9.2, with θ as the parameter.
  • Work in radians.

Key relationships

Quantity Formula Note
Conversion x = r cos θ, y = r sin θ, r² = x² + y² Check the quadrant when finding θ
dx/dθ f′(θ) cos θ − f(θ) sin θ Product rule
dy/dθ f′(θ) sin θ + f(θ) cos θ Product rule
Slope dy/dx = (dy/dθ) ÷ (dx/dθ) Needs dx/dθ ≠ 0
Second derivative d²y/dx² = [d/dθ (dy/dx)] ÷ (dx/dθ) Divide by dx/dθ again
Horizontal tangent dy/dθ = 0, dx/dθ ≠ 0 Both 0: investigate
Vertical tangent dx/dθ = 0, dy/dθ ≠ 0
Distance from pole Increasing if r and dr/dθ have the same sign Decreasing if opposite signs

Mistakes to avoid

  1. Treating dr/dθ as the slope. It measures change in r, not in y per unit x.
  2. Using tan θ as the slope. That is the slope of the ray to the point, not of the tangent.
  3. Dropping a product-rule term in dx/dθ or dy/dθ.
  4. Dividing second derivatives: d²y/dx² ≠ (d²y/dθ²) ÷ (d²x/dθ²).
  5. Reading dr/dθ > 0 as “moving away” when r < 0.
  6. Degree mode on the calculator.

Quick self-check

  1. Convert the polar point (6, 7π/6) to rectangular form. ((−3√3, −3))
  2. For r = 1 + cos θ, find dy/dx at θ = π/2. (r = 1, r′ = −1, dx/dθ = −1, dy/dθ = −1, so dy/dx = 1)
  3. For r = 5 sin θ, find dy/dx at θ = π/6. (√3)
  4. At some θ, r = −1 and dr/dθ = 2. Is the point moving towards or away from the pole? (Towards: opposite signs, so |r| is decreasing.)

Next: practice questions.

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