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AP® Physics 2: Algebra-Based · Unit 14 · Topic 14.9

Thin-Film Interference: Revision Notes (Physics 2 14.9)

One-page recap of thin-film interference: reflection phase changes, wavelength in the film, bright and dark conditions at normal incidence and quarter-wave coatings.

Short on time? This page is the recap. For explanations, Figure 1 and the worked examples, use the full study guide.

Recap

  • At a boundary, light is partly reflected, partly transmitted and partly absorbed.
  • A thin film reflects from its top and bottom surfaces. The two reflected waves overlap and interfere.
  • The effect shows when the thickness is comparable to the wavelength (hundreds of nm).
  • Interference depends on film thickness, wavelength, reflection phase changes and viewing angle. Calculations use normal incidence only.
  • Soap and oil films show colour bands because their thickness varies. A film much thinner than λ with one phase change looks black.
  • An antireflection coating makes the two reflections cancel, so more light is transmitted.

Key relationships

Relationship Meaning Use it to
reflection from higher n → 180°; from lower n → 0° phase change on reflection count phase changes (0, 1 or 2)
λ_film = λ / n_film wavelength inside the film; f unchanged compare the path with the right wavelength
extra path = 2t normal incidence, down and back find the path difference
0 or 2 changes: bright 2n t = mλ, dark 2n t = (m + ½)λ m = 0, 1, 2, … predict reflection colours
1 change: bright 2n t = (m + ½)λ, dark 2n t = mλ conditions swap predict reflection colours
t_min = λ / (4n_coating) quarter-wave antireflection coating, n_air < n_coating < n_lens design a coating

Assumptions behind the numbers

  • Light hits the film at normal incidence.
  • λ without a label is the wavelength in air (n = 1.00).
  • Visible light runs from about 400 nm to 700 nm.
  • Absorption in the film is small enough to ignore in the interference conditions.

Mistakes to avoid

  1. Flipping every reflection. Only reflection from a higher n gives 180°.
  2. Adding a phase change for refraction. Refraction never changes the phase.
  3. Using t instead of 2t.
  4. Using λ in air inside the film. Divide by n_film, or write 2n t.
  5. Using one formula for all films. One phase change swaps bright and dark.
  6. Choosing a coating index above the lens index. That gives one phase change and makes reflection stronger.

Quick self-check

  1. What is the wavelength of 520 nm light inside a film with n = 1.30? (400 nm)
  2. Light in glass reflects from the glass–air surface. Is there a phase change? (No: air has the lower n)
  3. Minimum thickness of a coating (n = 1.25) on glass (n = 1.52) that cancels 600 nm reflection? (120 nm)
  4. Why does a soap film look black just before it bursts? (t ≪ λ and one phase change, so the reflections cancel for every colour)

Next: practice questions.

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