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AP® Physics 2: Algebra-Based · Unit 15 · Topic 15.2

The Bohr Model of Atomic Structure: Revision Notes (Physics 2 15.2)

One-page recap of atomic structure, nuclear notation, isotopes and ions, the Bohr orbit force condition and the standing-wave rule 2πr = nλ for allowed orbits.

Short on time? This page is the recap. For explanations, Figures 1 and 2 and the worked examples, use the full study guide.

Recap

  • An atom has a tiny, positive nucleus of protons and neutrons, surrounded by negative electrons. Most of the atom is empty space.
  • The mass of an atom is almost all in the nucleus: an electron is about 1/1800 of the mass of a proton.
  • Each element has its own atomic number Z (number of protons). Different isotopes of an element have different numbers of neutrons, so different mass numbers A.
  • An ion has a nonzero net charge because its numbers of protons and electrons differ. The electrons decide how an atom interacts with other atoms.
  • The Bohr model treats the electron as orbiting the nucleus in a circle, held by the Coulomb force. It is a historical model that led to the idea of discrete energy states.
  • Only orbits whose circumference holds a whole number of de Broglie wavelengths are allowed, so only certain energies are allowed.
  • In this course, describe electron structure only by energy levels. Orbitals and their shapes are not needed.

Key relationships

Relationship Symbols and units Use it to
Notation such as ⁵⁶₂₆Fe: N = A − Z A = mass number, Z = atomic number, N = neutrons count nucleons
net charge = (Z − number of electrons)e e = 1.60 × 10⁻¹⁹ C find an ion’s charge
k|q₁q₂|/r² = mv²/r k = 9.0 × 10⁹ N·m²/C² link speed and radius of an orbit
2πr = nλ, λ = h/(mv) n = 1, 2, 3, … pick out the allowed orbits
r = n²r₁, v = v₁/n, λ = nλ₁ hydrogen: r₁ = 5.29 × 10⁻¹¹ m compare orbits
E = −ke²/(2r) = −13.6 eV/n² zero energy at infinite separation find the energy of a hydrogen state

Assumptions behind the numbers

  • One electron only (H, He⁺, Li²⁺). For a nucleus of charge +Ze, use kZe²/r².
  • The nucleus is treated as fixed because it is so much heavier than the electron.
  • Speeds are much less than c.

Mistakes to avoid

  1. Mixing up A and Z. Z is the smaller number (bottom left); A is the larger (top left).
  2. Getting the electron count wrong for an ion. A 2+ ion has 2 fewer electrons than protons; a 1− ion has 1 more.
  3. Thinking ions or isotopes change the element. Only Z does.
  4. Expecting faster electrons in bigger orbits. v = √(ke²/(mr)) falls as r grows.
  5. Allowing any radius. The standing-wave condition allows only r = n²r₁.
  6. Giving the ground state zero energy. It is the most negative level.

Quick self-check

  1. How many protons, neutrons and electrons are in ¹⁸₈O²⁻? (8, 10, 10)
  2. For hydrogen, how do r and v in the n = 2 orbit compare with n = 1? (r is 4 times larger, 2.12 × 10⁻¹⁰ m; v is half, 1.09 × 10⁶ m/s)
  3. How many de Broglie wavelengths fit around the n = 2 orbit? (Two)

Next: practice questions.

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