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AP® Physics 2: Algebra-Based · Unit 9 · Topic 9.2

The Ideal Gas Law: Revision Notes (Physics 2 9.2)

One-page recap of the ideal gas model, PV = nRT = Nk_BT, factor-of-change reasoning, gas graphs and finding absolute zero by extrapolation.

Short on time? This page is the recap. For explanations, Figures 1 and 2 and the worked examples, use the full study guide.

Recap

  • The ideal gas model assumes: atomic velocities are random; the atoms’ own volume is negligible compared with the gas volume; collisions are elastic; there are no forces on the atoms except during collisions.
  • Real gases fit the model best at low pressure and well above their condensation temperature.
  • Graphs of P, V and T test the model and give properties of the gas from gradients and intercepts.
  • Absolute zero is the temperature at which an ideal gas would have zero pressure. It is found by extrapolating a P–T line, not by measurement.

Key relationships

Relationship Symbols and units Use it to
PV = nRT P in Pa, V in m³, n in mol, R = 8.31 J/(mol·K), T in K find any one variable from the other three
PV = Nk_BT N = number of atoms, k_B = 1.38 × 10⁻²³ J/K work with numbers of atoms
N = nN_A, R = N_A k_B N_A = 6.02 × 10²³ mol⁻¹ convert between moles and atoms
P₁V₁/T₁ = P₂V₂/T₂ fixed n; any consistent P and V units; T in K predict a change without finding n
Graph (fixed n) Shape Gradient or intercept tells you
P against V, constant T curve (isotherm), P ∝ 1/V further from origin = larger nRT
P against 1/V, constant T straight line through origin gradient = nRT
V against T (K), constant P straight line through origin gradient = nR/P
P against T (K), constant V straight line through origin gradient = nR/V
P or V against T (°C) straight line, not through origin T-intercept ≈ −273 °C

Assumptions behind the numbers

  • The gas is ideal and the amount of gas is fixed unless the question says otherwise.
  • “Rigid” or “sealed rigid” means constant V. “Free piston” usually means constant P.
  • Convert °C to K by adding 273; 1 L = 10⁻³ m³; 1 atm ≈ 1.0 × 10⁵ Pa.

Mistakes to avoid

  1. Celsius ratios. Heating from 20 °C to 40 °C does not double P; the factor is 313/293.
  2. Wrong units in PV = nRT. Use Pa and m³ there; L and kPa only work in the ratio form.
  3. n with k_B, or N with R. Pair n with R and N with k_B.
  4. Forgetting a second change. If T and V both change, apply both factors.
  5. Drawing a line through the first and last points only. Use a best-fit line before extrapolating.
  6. Saying ideal gas atoms never collide. They collide elastically; there are no forces between collisions.

Quick self-check

  1. How many moles of ideal gas fill 2.0 L at 1.0 × 10⁵ Pa and 300 K? (0.080 mol)
  2. A fixed amount of gas has its volume halved and its absolute temperature doubled. By what factor does its pressure change? (× 4)
  3. A P–T(°C) line for a gas meets P = 0 at −275 °C. What is this temperature called, and what is the accepted value? (Absolute zero; −273 °C, or 0 K)

Next: practice questions.

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