Short on time? This page is the recap. For the figures, the graph and the worked examples, use the full study guide.
Recap
- A charge moving through a potential difference ΔV changes its electric potential energy by ΔU_E = qΔV.
- Every point in a steady circuit has one value of potential. Go once round a closed loop and you return to the same potential, so the potential differences add to zero.
- That is Kirchhoff’s loop rule, and it is a statement of energy conservation: energy gained from sources equals energy transferred in the other elements.
- The rule holds for every closed loop, including loops through branches and meters.
- Only potential differences are physical. You may choose any point as V = 0.
Key relationships
| Quantity | Relationship |
|---|---|
| Energy change of a charge | ΔU_E = qΔV |
| Loop rule | ΣΔV = 0 round a closed loop |
| Single loop, real battery | I = ℰ/(r + ΣR) |
| Battery delivering current | ΔV_terminal = ℰ − Ir |
| Battery being charged | ΔV_terminal = ℰ + Ir |
| Crossing… | ΔV |
|---|---|
| resistor with the assumed current | −IR |
| resistor against the assumed current | +IR |
| battery, − to + | +ℰ |
| battery, + to − | −ℰ |
| ideal wire | 0 |
Potential-against-position graphs
- Rise of ℰ across a source (crossed − to +).
- Straight-line fall of IR across a uniform resistor, in the direction of the current.
- Flat along ideal wires.
- Ends at the level where it started.
Mistakes to avoid
- Switching walking direction half-way round a loop.
- Giving a battery −ℰ when crossing it from − to +.
- Treating a negative current as an error.
- Drawing a drop along a wire on the potential graph.
- Forgetting internal resistance when the battery is not ideal.
- A graph that does not close.
Quick self-check
- A loop has a 12 V ideal battery and resistors with 5.0 V and 4.5 V across them, plus one more resistor. What is the potential difference across the last one? (2.5 V)
- You walk through a resistor against the current I. What term do you write? (+IR)
- A loop equation gives I = −0.40 A. What does this tell you? (The current is 0.40 A in the opposite direction to the one assumed)
- On a potential graph, what does a flat section show? (An ideal wire: no potential difference)
Next: practice questions.