Skip to content
Marlbridge

AP® Physics C: Electricity and Magnetism · Unit 13 · Topic 13.4

Inductance: Revision Notes (Physics C: E&M 13.4)

One-page recap of inductance for the calculus-based course: L = NΦ/I, the solenoid formula and its core, ℰ = −L dI/dt, stored energy ½LI² and where that energy goes.

Short on time? This page is the recap. For the derivations, Figure 1 and the worked examples, use the full study guide. This topic is in the calculus-based course.

Recap

  • Inductance is a conductor’s tendency to oppose a change in its own current (self-induction, from Faraday’s and Lenz’s laws).
  • It depends on the conductor’s physical form. Straight wires are modelled as having zero inductance; a solenoid is an inductor.
  • A solenoid’s inductance depends on the number of turns, the length, the cross-sectional area and the permeability of the core.
  • The self-induced emf depends on the rate of change of current, not on the current.
  • An inductor stores energy in its magnetic field. The energy can later be dissipated in a resistor or passed to a capacitor, with total energy conserved.
  • μ₀ = 4π × 10⁻⁷ T·m/A; 1 H = 1 V·s/A = 1 Wb/A = 1 Ω·s.

Key relationships

Quantity Expression Notes
Definition of inductance L = NΦ_B/I flux linkage per ampere
Long solenoid L = μ_core N²A/ℓ μ_core = μ₀ for air; L ∝ N²
Self-induced emf ℰ = −L dI/dt minus sign = Lenz’s law
Power into the inductor P = LI dI/dt positive while the current rises
Stored energy U = ½LI² from integrating P dt
Energy released, I₁ → I₂ ½L(I₁² − I₂²) not ½L(I₁ − I₂)²

Assumptions behind the results

  • The solenoid is long compared with its radius, so the field inside is uniform and the field outside is negligible.
  • The core’s permeability is constant (L does not depend on I).
  • An “ideal” inductor has no resistance.

Mistakes to avoid

  1. “An inductor opposes current.” It opposes a change in current.
  2. Using I instead of dI/dt for the emf.
  3. Forgetting N² in the solenoid formula.
  4. Energy released as ½L(ΔI)². Subtract the two energies instead.
  5. Wrong emf direction. Against the current while it rises; along it while it falls.

Quick self-check

  1. The current in a 2.0 H inductor rises at 5.0 A/s. What is the size of the self-induced emf? (10 V, opposing the current)
  2. How much energy does a 0.50 H inductor store at 4.0 A? (4.0 J)
  3. A solenoid’s turns are tripled with nothing else changed. By what factor does L change? (× 9)

Next: practice questions.

AP® and Advanced Placement® are trademarks registered by the College Board, which is not affiliated with, and does not endorse, this website. Marlbridge is an independent tuition provider. It is not an authorized AP course provider, an AP school or an exam centre, and these resources are not official College Board materials. Reading them or doing simulations does not meet the laboratory requirement of an AP science course.