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AP® Physics C: Electricity and Magnetism · Unit 8 · Topic 8.3

Electric Fields: Revision Notes (Physics C: E&M 8.3)

One-page recap of electric fields for the calculus-based course: E = F/q, point-charge fields, vector addition, field lines, and conductors versus insulators.

Short on time? This page is the recap. For the explanations, the figures and the worked examples, use the full study guide.

Recap

  • A charged object (the source) sets up an electric field in the space around it. The field is a vector at every point.
  • Measure it with a test charge q₀: a charge small enough not to disturb the source charges. E = F/q₀, in N/C.
  • E has the direction of the force on a positive charge. A negative charge feels a force opposite to E.
  • E points away from isolated positive charges and towards isolated negative charges.
  • Superposition: the net field is the vector sum of the fields of each source.
  • Vector field maps draw arrows on a grid (length = magnitude). Field lines are tangent to E, start on + and end on −, are denser where E is stronger, and never cross.
  • k = 1/(4πε₀) = 8.99 × 10⁹ N·m²/C²; e = 1.60 × 10⁻¹⁹ C.

Key relationships

Situation Relationship Notes
Definition E = F/q₀ q₀ small; E does not depend on q₀
Force on a charge q F = qE Opposite to E if q < 0
Point charge q E = kq/r² = q/(4πε₀r²) E ∝ q and E ∝ 1/r²
Several point charges E_net = E₁ + E₂ + … Add x- and y-components
Conductor in equilibrium E = 0 inside; E ⊥ surface just outside Excess charge on the surface
Insulator E inside can be non-zero Charge can sit inside and on the surface
Outside a spherically symmetric sphere E = kQ/r² (r ≥ R) As if Q were a point charge at the centre

Assumptions behind the results

  • Source charges are at rest (electrostatics).
  • Point charges have negligible size compared with the distances involved.
  • The test charge is small enough not to move the source charges.

Mistakes to avoid

  1. Adding magnitudes. Fields are vectors: resolve, then add.
  2. Wrong distance. Use the distance from each source to the point.
  3. Wrong direction for a negative source. E points towards it.
  4. Forgetting the sign of q in F = qE. A negative charge is pushed against E.
  5. Treating field lines as paths. They show the force direction, not the velocity.
  6. “E = 0 inside any charged sphere.” Only for a conductor in equilibrium.

Quick self-check

  1. What is E at 0.30 m from a +1.0 nC point charge? (99.9 N/C, about 100 N/C, away from the charge)
  2. You move three times farther from a point charge. What happens to E? (It becomes 1/9 as large)
  3. Find the force on a −3.0 nC charge in a field of 2.0 × 10⁴ N/C pointing east. (6.0 × 10⁻⁵ N, west)
  4. Where is the excess charge on a charged metal block in equilibrium? (On its surface; E = 0 inside the metal)
  5. On a field-line diagram, lines are twice as close together at point X as at point Y. Where is E stronger, and which way does it point at X? (At X; along the tangent to the line through X, in the arrow direction)

Next: practice questions.

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