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AP® Physics C: Mechanics · Unit 2 · Topic 2.3

Newton’s Third Law: Revision Notes (Physics C: Mechanics 2.3)

One-page recap of Newton’s third law: the pair test, internal forces and the centre of mass, ideal strings and pulleys, and how tension varies in a hanging string with mass.

Short on time? This page is the recap for the calculus-based course. For diagrams and worked examples, use the full study guide.

Recap

  • Every force is one half of an interaction between two objects.
  • If A pushes or pulls on B, then B pushes or pulls on A at the same instant, with equal size and opposite direction.
  • The pair is always the same type of force and acts on two different objects.
  • Show a pair on two separate free-body diagrams, with equal-length arrows and matching labels.
  • Internal forces (between parts of your chosen system) cancel in pairs. They cannot change how the system’s centre of mass moves.
  • Tension is the combined effect of string segments pulling on their neighbours.

Key relationships

Idea Statement Notes
Third law F_B on A = −F_A on B names swapped, same type, same instant
System of particles ΣF (all parts) = ΣF_ext internal pairs add to zero
Hanging string at rest dT/dy = λg y measured up from the bottom; λ in kg/m
Tension along a hanging string T(y) = T(0) + ∫₀ʸ λg dy′ largest at the top
Ideal string λ → 0, so T is the same everywhere also does not stretch
Ideal pulley same T on both sides massless, frictionless axle

Assumptions behind the numbers

  • g = 9.8 m/s² near Earth’s surface.
  • “Light”, “massless” or “ideal” string: ignore its mass and stretch.
  • dT/dy = λg holds for a string hanging at rest; other situations need the second law (Topic 2.5).

Mistakes to avoid

  1. Pairing weight with normal force. Same object, different types: not a pair.
  2. Bigger mass, bigger force. The two forces in an interaction are always equal in size.
  3. Cancelling partners on one diagram. They belong on different diagrams.
  4. Forgetting the system choice. A force is internal or external only relative to the system you chose.
  5. Assuming equal tension in a heavy rope. Only an ideal string has the same tension throughout.
  6. Putting the hand’s push on the far block. A force appears only on the object it touches (or attracts).

Quick self-check

  1. A cyclist’s tyre pushes backwards on the road. What is the partner force? (The road pushes forwards on the tyre, same size, friction.)
  2. A uniform 4.0 m rope of mass 2.0 kg hangs at rest from a beam. What is the tension 1.0 m below the top? (It supports the 3.0 m below, mass 1.5 kg: T = 1.5 × 9.8 ≈ 15 N.)
  3. Two skaters, at rest together on smooth ice, push apart. Does their centre of mass move? (No. The pushes are internal and nothing else acts horizontally.)

Next: practice questions.

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