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AP® Physics C: Mechanics · Unit 3 · Topic 3.1

Translational Kinetic Energy: Revision Notes (Physics C: Mechanics 3.1)

One-page recap of translational kinetic energy for the calculus-based course: K = ½mv² from components, factor-of-change rules, dK/dt = m v_x a_x, graph shapes and frame dependence.

Short on time? This page is the recap for the calculus-based course (separate from Physics 1). For explanations, a graph and worked examples, use the full study guide.

Recap

  • Translational kinetic energy is the energy of motion from place to place: K = ½mv². For a system, use the speed of its centre of mass.
  • Unit: the joule, 1 J = 1 kg·m²/s². Mass in kg, speed in m/s.
  • K is a scalar. It depends on speed only, never on direction. K ≥ 0; ΔK can have either sign.
  • K depends on the reference frame: observers moving relative to each other measure different speeds, so different K.

Key relationships

Relationship Meaning
K = ½mv² definition; v is speed
v² = v_x² + v_y² + v_z² square components, then add
v = √(2K/m) speed from K
K ∝ m (fixed v); K ∝ v² (fixed m) factor-of-change rules
dK/dt = m v_x a_x (1D); m v · a in general sign tells whether K rises or falls
K′ = ½m|v − u|² K seen from a frame moving at u

Graph shapes. K–v: parabola through the origin. K–v²: straight line, slope ½m. K–m at fixed v: straight line, slope ½v². K–t for a projectile: U-shape with a minimum of ½mv_x² at the top, not zero.

Assumptions behind the numbers

  • The object is modelled as a point (or a system’s centre of mass); rotation is ignored until Unit 6.
  • One inertial frame for the whole problem unless the question compares frames.
  • Free fall: a_y = −g with g = 9.8 m/s² (+y upward), air resistance ignored.

Mistakes to avoid

  1. K with a sign or direction. It has neither.
  2. Doubling v doubles K. It quadruples K.
  3. ΔK = ½m(Δv)². Compute K_f − K_i.
  4. Adding velocity components as numbers. Use v² = v_x² + v_y².
  5. K = 0 at the top of a projectile path. K_top = ½mv_x².
  6. Mass in grams. Convert to kg.
  7. Mixing frames. Measure every speed relative to the same observer.

Quick self-check

  1. What is K for a 0.060 kg ball at 25 m/s? (½ × 0.060 × 625 = 19 J; 18.75 J)
  2. A 2.0 kg object has v = (3.0, −4.0, 12) m/s. Find K. (v² = 9 + 16 + 144 = 169 m²/s², so K = 169 J ≈ 170 J)
  3. K of a cart is multiplied by 4 at the same mass. By what factor did its speed change? (× 2)
  4. A 1.5 kg cart has v_x = +4.0 m/s and a_x = −2.0 m/s². Find dK/dt. (1.5 × 4.0 × (−2.0) = −12 J/s; K is falling)

Next: practice questions.

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