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AP® Physics C: Mechanics · Unit 6 · Topic 6.2

Torque and Work: Revision Notes (Physics C: Mechanics 6.2)

One-page calculus recap of torque and work: W = ∫τ dθ, signs of work, signed areas on torque–angle graphs, the rotational work–energy theorem and the usual errors.

Short on time? This page is the recap for the calculus-based course (separate from Physics 1, which does not integrate angle-dependent torques). For the derivations, graphs and worked examples, use the full study guide.

Recap

  • A torque transfers energy into or out of a rigid body only if the body turns while the torque acts.
  • When the body turns through dθ, the point where a force acts moves ds = r dθ along the tangent. Only F sin φ does work, so dW = rF sin φ dθ = τ dθ.
  • State a positive sense of rotation. Torque with the rotation: positive work. Against it: negative work. τ = 0 or Δθ = 0: no work.
  • Every point of a rigid body turns through the same dθ, so the works of several torques add to ∫τ_net dθ.
  • With α = ω dω/dθ, τ_net = Iα integrates to W_net = ½Iω² − ½Iω₀².

Key relationships

Relationship When to use it Graph meaning
W = ∫τ dθ Any torque, θ in rad Signed area under τ–θ graph
W = τΔθ Constant torque only Rectangle
W_net = ∫τ_net dθ = ΣWᵢ Several torques Add signed areas
W_net = ½Iω² − ½Iω₀² Rigid body, fixed axis —
α = ω dω/dθ Chain rule step —
ω greatest where τ_net = 0 Torque changes sign Where τ_net graph crosses the axis

Assumptions behind the numbers

  • The body is rigid and turns about a fixed axis, so I is constant.
  • Angles are in radians; 1 rev = 2π rad.
  • Axles are frictionless unless a friction torque is given.

Mistakes to avoid

  1. Work from a torque that does not turn anything.
  2. Revolutions or degrees in W = τΔθ.
  3. W = τΔθ for a torque that changes with angle.
  4. Adding sizes of areas above and below the axis.
  5. Leaving out friction’s negative work.
  6. Writing a torque in J or work in N·m.
  7. Equal work means equal ω. Equal work means equal ΔK.

Quick self-check

  1. A constant 5.0 N·m torque turns a wheel through 4.0 rad in its direction of rotation. Work? (20 J)
  2. A friction torque of 0.30 N·m acts while a wheel turns 10 rev. Work by friction? (−0.30 × 20π = −19 J)
  3. τ(θ) = 6.0 − 2.0θ from 0 to 3.0 rad, in the direction of rotation. Work? (18 − 9.0 = 9.0 J)

Next: practice questions.

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