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AP® Physics C: Mechanics · Unit 6 · Topic 6.3

Angular Momentum and Angular Impulse: Revision Notes (Physics C: Mechanics 6.3)

One-page calculus recap of angular momentum and angular impulse: L = Iω, L = r × p about a chosen point, ∫τ dt as a signed area, and τ_net = dL/dt.

Short on time? This page is the recap for the calculus-based course (separate from Physics 1, which does not use r × p or integrate time-dependent torques). For the derivations, graphs and worked examples, use the full study guide.

Recap

  • A rigid body on a fixed axis has L = Iω, with I about that axis. L takes the sign of ω.
  • A point object has L = r × p about a chosen point O. Its size is rmv sin φ = mvd, where d is the perpendicular distance from O to the line of motion. In the plane, L_z = x p_y − y p_x.
  • An object moving in a straight line has L about any point not on its path. About a point on its path, L = 0.
  • Angular impulse = ∫τ dt. It points the same way as the torque.
  • From τ_net = Iα with constant I: τ_net = dL/dt. For a point object, d(r × p)/dt = r × F_net gives the same result.

Key relationships

Relationship When to use it Graph meaning
L = Iω Rigid body, fixed axis —
L = r × p; L = mvd Point object, chosen point d is the perpendicular distance to the path
angular impulse = ∫τ dt Any torque Signed area under τ–t graph
angular impulse = τΔt Constant torque only Rectangle
τ_net = dL/dt Always (fixed axis or point) Slope of L–t graph
∫τ_net dt = L₂ − L₁ Rotational impulse–momentum theorem Area under τ_net–t equals ΔL

Units: kg·m²/s = N·m·s.

Assumptions behind the numbers

  • One fixed axis or reference point, used for every quantity in the problem.
  • The body is rigid (constant I) when you use τ_net = Iα to derive the theorem.
  • An inertial reference frame; axles frictionless unless a friction torque is given.

Mistakes to avoid

  1. Not stating the axis or point. L has no meaning without it.
  2. “Straight-line motion has no angular momentum.”
  3. Constant-torque formula τΔt for a torque that changes with time.
  4. Area under τ–θ (work) mistaken for area under τ–t (angular impulse).
  5. Losing the sign of L₀ when the body reverses.
  6. Reading L = 0 from τ = 0. Zero torque means zero slope.
  7. Using only one torque in ∫τ dt = ΔL. The theorem needs the net torque.

Quick self-check

  1. A flywheel with I = 0.050 kg·m² turns at 40 rad/s. What is L? (2.0 kg·m²/s)
  2. A 0.30 kg ball moves at 5.0 m/s along a line 0.60 m from point O. Its L about O? (0.30 × 5.0 × 0.60 = 0.90 kg·m²/s)
  3. A net torque τ = 2.0t (N·m) acts from t = 0 to 3.0 s on a wheel. Change in L? (∫₀³ 2.0t dt = 9.0 N·m·s)

Next: practice questions.

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