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Flashcards · AP® Physics C: Mechanics · Unit 7
Unit 7: Oscillations flashcards
40 cards on topics 7.1 to 7.5. Pick a topic or study the whole unit.
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7.1 Defining Simple Harmonic Motion (SHM)
- What is simple harmonic motion?
- Periodic motion in which the net restoring force is proportional to the displacement from equilibrium: F_net,x = −kx with x measured from equilibrium and k > 0 constant.
- What differential equation describes SHM?
- d²x/dt² = −(k/m)x, from Newton's second law with F_net = −kx. Any variable obeying d²q/dt² = −(constant)q is in SHM.
- What is a restoring force?
- A force pointing opposite to the displacement, back toward equilibrium. F = +kx points away and is not restoring: that equilibrium is unstable.
- Does gravity change SHM for a mass on a vertical spring?
- No. A constant force only shifts the equilibrium, to a stretch d = mg/k. Measured from the new equilibrium, the net force is −ky with the same k.
- How do you find the effective spring constant from a potential energy curve?
- Near a stable equilibrium (a minimum of U), small oscillations are approximately SHM with k_eff = d²U/dx² at the minimum. At a maximum U″ is negative and there is no oscillation.
- Why is a simple pendulum only approximately SHM?
- Its equation is d²θ/dt² = −(g/ℓ) sin θ. Only for small angles in radians does sin θ ≈ θ, giving the SHM form −(g/ℓ)θ.
- Is all periodic motion SHM?
- No. Periodic motion repeats in equal time intervals; SHM is the special case with a restoring force proportional to displacement. Test the force law.
- Where should displacement be measured from in SHM?
- From the equilibrium position, where the net force is zero, not from the relaxed spring length when a constant force also acts.
7.2 Frequency and Period of SHM
- How are period, frequency and angular frequency related?
- f = 1/T, ω = 2πf = 2π/T. Units: T in s, f in Hz, ω in rad/s.
- How do you find the period of any SHM system?
- Apply Newton's second law (or τ = Iα), reduce it to d²x/dt² = −ω²x, read off ω² as the constant multiplying x, then T = 2π/ω.
- What is the period of a mass on an ideal spring?
- T = 2π√(m/k), in any orientation. Gravity does not change it. For a vertical spring with static stretch d = mg/k, this equals T = 2π√(d/g).
- What is the period of a simple pendulum?
- T = 2π√(ℓ/g) for small angles in radians. The bob's mass cancels, and the formula fails at large angles.
- Does the period of SHM depend on amplitude?
- No, while the SHM model holds. Larger amplitude gives more energy and higher maximum speed, but the same period.
- How do you find k or g from a straight-line graph of period data?
- Plot T² against m for a spring: slope 4π²/k. Plot T² against ℓ for a pendulum: slope 4π²/g. Use the slope, not a single reading, especially if there is an intercept.
- How does T change if a spring oscillator's mass is multiplied by 9?
- T ∝ √m, so T is multiplied by √9 = 3.
- How should you time oscillations accurately in a lab?
- Time many full cycles and divide by the number of cycles. Count complete cycles, not swings past the middle.
7.3 Representing and Analyzing SHM
- What is the position function for SHM?
- x = A cos(ωt + φ₀), with ω = √(k/m) from the system and amplitude A and phase φ₀ from the initial conditions. A sine form is equivalent with a phase shift of π/2.
- What are velocity and acceleration in SHM?
- v_x = −Aω sin(ωt + φ₀) and a_x = −Aω² cos(ωt + φ₀) = −ω²x. An a_x–x graph is a straight line through the origin with slope −ω².
- Where are the maximum speed and maximum acceleration in SHM?
- v_max = Aω at equilibrium, x = 0, where a = 0. a_max = Aω² at the ends, x = ±A, where the object is momentarily at rest.
- What is the speed at any position in SHM?
- |v_x| = ω√(A² − x²).
- How do you find amplitude and phase from initial conditions?
- A = √(x₀² + (v_x0/ω)²), with cos φ₀ = x₀/A and sin φ₀ = −v_x0/(Aω). Use both signs to find the quadrant; tan alone is not enough.
- What is resonance?
- When a sinusoidal driving force acts at the natural frequency, it adds energy every cycle, so the amplitude grows.
- What is v_max for SHM in terms of frequency f?
- v_max = Aω = 2πfA, not Af.
- An a_x–x graph has slope −49 s⁻². What is the period?
- ω² = 49 s⁻², so ω = 7.0 rad/s and T = 2π/7.0 ≈ 0.90 s.
7.4 Energy of Simple Harmonic Oscillators
- What is the total energy of a spring–mass oscillator?
- E = ½kA² = ½mv_max², constant with no friction. At a turning point it is all potential; at equilibrium it is all kinetic. This gives v_max = A√(k/m) = Aω.
- What are K and U at any position in SHM?
- U = ½kx² and K = ½k(A² − x²), with x from equilibrium. They always add to ½kA².
- Where does K equal U in SHM?
- At x = ±A/√2. At x = A/2, U = E/4 and K = 3E/4.
- How does oscillator energy depend on amplitude?
- E ∝ A². Doubling the amplitude quadruples the energy without changing the period.
- How often do K and U repeat in SHM?
- Every T/2. For x = A cos ωt, U = ½E[1 + cos 2ωt] and K = ½E[1 − cos 2ωt].
- Does a larger mass mean more energy at the same amplitude and spring?
- No. E = ½kA² is the same; the larger mass just has a smaller v_max.
- Why must the system include the spring when analysing oscillator energy?
- The spring stores the potential energy. With the block alone as the system, the spring does work on it and the block's energy changes.
- How do you show that SHM conserves energy using calculus?
- dE/dt = d(½mv_x² + ½kx²)/dt = v_x(m dv_x/dt + kx) = 0, because Newton's second law gives m dv_x/dt = −kx.
7.5 Simple and Physical Pendulums
- What is a physical pendulum?
- A rigid body swinging about a fixed axis, with d the distance from the axis to its center of mass. Gravity's restoring torque is −mgd sin θ ≈ −mgdθ for small angles in radians.
- What is the period of a physical pendulum?
- T = 2π√(I/(mgd)), with ω = √(mgd/I), where I is about the pivot: I = I_cm + md².
- How is the simple pendulum a special case of the physical pendulum?
- For a point mass on a light string, I = ml² and d = l, so T = 2π√(ml²/(mgl)) = 2π√(l/g).
- What is a torsion pendulum?
- A body on a twisted wire with restoring torque τ = −κθ, κ in N·m/rad. T = 2π√(I/κ). Gravity plays no part.
- What is the period of a uniform rod swinging from one end?
- I = mL²/3 and d = L/2, so T = 2π√(2L/(3g)). For L = 1.5 m, T ≈ 2.0 s.
- What is the greatest angular speed of a pendulum in SHM?
- (dθ/dt)max = ωθ_max at the bottom of the swing, where ω = 2π/T is the fixed angular frequency, not the varying angular velocity.
- What is the equivalent length of a physical pendulum?
- l_eq = I/(md): a simple pendulum of this length has the same period.
- How small must the amplitude be for the small-angle formula?
- Below about 15°, the period error is under half a percent. Larger swings have slightly longer periods.
Study Unit 7 further
- 7.1 Defining Simple Harmonic Motion (SHM) Study guide: 7.1 Defining Simple Harmonic Motion (SHM)Revision notes: 7.1 Defining Simple Harmonic Motion (SHM)Practice questions: 7.1 Defining Simple Harmonic Motion (SHM)
- 7.2 Frequency and Period of SHM Study guide: 7.2 Frequency and Period of SHMRevision notes: 7.2 Frequency and Period of SHMPractice questions: 7.2 Frequency and Period of SHM
- 7.3 Representing and Analyzing SHM Study guide: 7.3 Representing and Analyzing SHMRevision notes: 7.3 Representing and Analyzing SHMPractice questions: 7.3 Representing and Analyzing SHM
- 7.4 Energy of Simple Harmonic Oscillators Study guide: 7.4 Energy of Simple Harmonic OscillatorsRevision notes: 7.4 Energy of Simple Harmonic OscillatorsPractice questions: 7.4 Energy of Simple Harmonic Oscillators
- 7.5 Simple and Physical Pendulums Study guide: 7.5 Simple and Physical PendulumsRevision notes: 7.5 Simple and Physical PendulumsPractice questions: 7.5 Simple and Physical Pendulums
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