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AP® Statistics · Unit 3 · Topic 3.2

Sampling Distributions for Sample Proportions: Revision Notes (Statistics 3.2)

One-page recap of the mean, standard deviation and shape of the sampling distribution of a sample proportion, the three conditions, normal probabilities and the mistakes that cost marks.

Short on time? This page is the recap. For explanations and worked examples, use the full study guide.

Recap

  • p̂ = X / n, where X is the number of successes in the sample. It varies from sample to sample.
  • The sampling distribution of p̂ is the distribution of p̂ over all random samples of size n.
  • Its mean is p, so p̂ is unbiased (Topic 3.1).
  • Its standard deviation shrinks as n grows; multiply n by 4 to halve it.
  • With large enough expected counts, its shape is approximately normal, so you can use z-scores.

Key relationships

Quantity Formula or rule Needs
Mean μp̂ = p Random sample
Standard deviation σp̂ = √(p(1 − p) / n) Independence: random, and n ≤ 10% of N when sampling without replacement
Shape approximately normal np ≥ 10 and n(1 − p) ≥ 10
z-score z = (p̂ − p) / σp̂ Normal shape
Sample size for σp̂ ≤ d n ≥ p(1 − p) / d², rounded up —

Interpretation templates

  • Mean: “In repeated random samples of [n] [individuals] from [population], the sample proportion who [success] averages [p].”
  • Standard deviation: “In random samples of [n] [individuals], the sample proportion who [success] typically differs from the population proportion [p] by about [σp̂].”
  • Probability: “If [p] of [population] [success], about [probability] of random samples of [n] would give a sample proportion [event].”

Mistakes to avoid

  1. Using p̂ in the formula or the large-counts check when p is given.
  2. Checking n ≥ 30 instead of the expected counts np and n(1 − p).
  3. Forgetting the 10% condition, or checking it the wrong way round (it is n ≤ 0.10N).
  4. Thinking doubling n halves σp̂ (it divides it by √2).
  5. Rounding a required sample size down.
  6. Writing “it varies less” without saying which distribution.
  7. Concluding a claim is proved false from a small probability.

Quick self-check

  1. p = 0.7 and n = 84. Find σp̂ and check large counts. (σp̂ = √(0.21 / 84) = √0.0025 = 0.05; np = 58.8 and n(1 − p) = 25.2, both ≥ 10.)
  2. A random sample of 100 is taken from a club of 600 members. Is the 10% condition met? (No: 10% of 600 is 60, and 100 > 60.)
  3. σp̂ = 0.04 when n = 150. What is σp̂ when n = 600 (same p)? (0.02: four times the sample size halves σp̂.)

Next: practice questions.

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