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Flashcards · 7405 · A Level Topic 33
Nuclear magnetic resonance spectroscopy (A Level) flashcards
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Topic 33: Nuclear magnetic resonance spectroscopy
- Four reasons TMS is used as the standard
- 12 equivalent H atoms give one strong single peak; its peak (δ = 0) is at lower δ than almost all other protons; it is inert; it is volatile, so it is easily removed.
- Why are ¹H NMR samples dissolved in CDCl₃ or CCl₄?
- Deuterium gives no signal in a ¹H spectrum, and CCl₄ has no H atoms, so the solvent does not swamp the sample’s peaks.
- The n+1 rule
- A ¹H signal is split into n + 1 lines by n H atoms on adjacent carbon atoms.
- Splitting pattern of an ethyl group, CH₃CH₂–
- A quartet (CH₂, 2H) and a triplet (CH₃, 3H).
- What does integration of a ¹H spectrum give?
- The relative number of H atoms in each environment, as a ratio. You need the molecular formula to get actual numbers.
- How many peaks in the ¹³C NMR spectrum of methyl ethanoate, CH₃COOCH₃?
- Three: the C=O carbon, the O–CH₃ carbon and the CH₃ on the C=O.
- ¹³C vs ¹H
- ¹³C counts carbon environments and shows no splitting. ¹H counts hydrogen environments and gives integration and splitting.
- Aldehyde vs ketone
- Both show C=O near 190–220 in ¹³C. Only an aldehyde has a ¹H peak at δ 9–10.