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Flashcards · 7408 · Topic 7
Fields and their consequences flashcards
32 cards on Topic 7, subtopics 3.7.1 to 3.7.5. Pick a subtopic or study them all.
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3.7.1 Fields
- Force field
- A region in which a body experiences a non-contact force.
- What produces gravitational, electric and magnetic fields?
- Gravitational: mass. Electric: static charge. Magnetic: moving charge.
- Gravitational vs electrostatic fields: one similarity and one difference
- Similar: both obey inverse-square laws and use field lines, potential and equipotential surfaces. Different: masses always attract; charges can attract or repel.
3.7.2 Gravitational fields
- Newton's law of gravitation and field strength in a radial field
- F = Gm₁m₂/r². g = F/m; for a radial field g = GM/r², with r measured from the centre of mass.
- Gravitational potential: definition, and why it is negative
- The work done per unit mass in bringing a mass from infinity to that point. V = −GM/r. It is zero at infinity and negative elsewhere because the force is attractive.
- Equipotential surfaces
- No work is done moving along them; they are perpendicular to field lines.
- Derive T² ∝ r³ for a circular orbit
- GMm/r² = mv²/r. Substitute v = 2πr/T and rearrange: T² = (4π²/GM)r³. 4π²/GM is constant for one central mass.
- Kinetic, potential and total energy of an orbiting satellite
- Ek = GMm/2r, Ep = −GMm/r, total = −GMm/2r.
- Geostationary orbit
- Earth-synchronous (24 h period), in the equatorial plane, moving west to east, radius about 4.2 × 10⁷ m. Fixed dishes can point at it.
- Escape velocity
- v = √(2GM/R), from ½mv² = GMm/R: the kinetic energy equals the energy needed to reach infinity.
- Link between g and the V–r graph
- g = −ΔV/Δr: g is minus the gradient of the V–r graph. The area under a g–r graph gives the potential difference.
3.7.3 Electric fields
- Coulomb's law
- F = (1/4πε₀) Q₁Q₂/r², for point charges in a vacuum (air counts as a vacuum). A charged sphere acts as if its charge were at its centre.
- Electric field strength: definition, radial field and uniform field
- E = F/Q. Radial: E = (1/4πε₀) Q/r². Uniform (parallel plates): E = V/d.
- Absolute electric potential
- Work done per unit positive charge in bringing it from infinity. Positive near a positive charge, negative near a negative one. Radial: V = (1/4πε₀) Q/r.
- Path of a charged particle entering a uniform electric field at right angles
- A parabola: constant velocity along the plates, constant acceleration (a = QE/m) across them.
- Gravitational vs electrostatic force between a proton and an electron
- The gravitational force is negligible: smaller by a factor of order 10³⁹.
3.7.4 Capacitance
- Capacitance, and capacitance of a parallel-plate capacitor
- C = Q/V (farads). C = Aε₀εᵣ/d, where εᵣ is the relative permittivity (dielectric constant).
- Dielectric action
- Polar molecules rotate to line up with the field. Their own field opposes the applied field, so the pd falls for a given charge and C rises.
- Energy stored by a capacitor
- The area under the charge–pd graph: E = ½QV = ½CV² = ½Q²/C.
- Time constant: what fraction remains after one RC on discharge, and is reached after one RC on charge?
- Discharge: about 37% left. Charge: about 63% reached.
- Time constant vs half-time
- Time constant = RC. Half-time = 0.69RC.
- Required practical 9: the graph for a capacitor discharge
- Plot ln V against t. Gradient = −1/RC.
- Discharge equation, and R = 10 kΩ, C = 100 μF: find RC
- Q = Q₀e^(−t/RC) (V and I follow the same form). RC = 10 × 10³ × 100 × 10⁻⁶ = 1.0 s.
3.7.5 Magnetic fields
- The tesla
- 1 T gives a force of 1 N on 1 m of wire carrying 1 A perpendicular to the field (F = BIl).
- Charged particle moving at right angles to a magnetic field
- F = BQv, perpendicular to the velocity, so no work is done: constant speed in a circle of radius r = mv/BQ.
- Why can a cyclotron use a fixed-frequency alternating pd?
- The time per orbit, 2πm/BQ, does not depend on speed.
- Magnetic flux and flux linkage
- Φ = BA (webers). Flux linkage NΦ = BAN cos θ, where θ is the angle between the field and the normal to the coil.
- Faraday's law and Lenz's law
- Faraday: induced emf = rate of change of flux linkage (ε = NΔΦ/Δt). Lenz: the induced current opposes the change producing it.
- Emf of a rotating coil, and when it is greatest
- ε = BANω sin ωt. It is maximum when the plane of the coil is parallel to B (flux linkage zero).
- Peak 325 V sinusoidal supply: find the rms voltage
- V_rms = V₀/√2 = 325 ÷ 1.41 ≈ 230 V. (Sinusoidal waveforms only.)
- Transformer equation and causes of energy loss
- Nₛ/Nₚ = Vₛ/Vₚ. Losses: eddy currents (reduced by a laminated core), coil resistance, magnetising the core, flux leakage.
- Why is electricity transmitted at high voltage?
- For the same power, high voltage means low current, so the I²R loss in the cables is low.