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Flashcards · 4040 · Topic 11
Elementary ideas of probability flashcards
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Topic 11: Elementary ideas of probability
- What are the sample space and an event?
- The sample space S is the set of all possible outcomes of an experiment. An event is the set of outcomes you are interested in.
- How do you find P(A) when outcomes are equally likely?
- P(A) = n(A) ÷ n(S), and 0 ≤ P(A) ≤ 1. Example: P(more than 4 on a fair die) = 2/6 = 1/3.
- An event happens 36 times in 150 trials. Estimate its probability and the number expected in 400 trials
- Relative frequency = 36 ÷ 150 = 0.24. Expected number = probability × trials = 0.24 × 400 = 96.
- What is the complement of an event?
- A′, the event that A does not happen. P(A′) = 1 − P(A).
- What are mutually exclusive events, and what rule do they follow?
- Events that cannot both happen in one trial, so A ∩ B = Ø and P(A ∪ B) = P(A) + P(B). A full set of exclusive outcomes has probabilities adding to 1.
- P(A) = 0.6, P(B) = 0.35 and P(neither) = 0.1. Find P(A ∩ B)
- P(A ∪ B) = 1 − 0.1 = 0.9. Then P(A ∩ B) = P(A) + P(B) − P(A ∪ B) = 0.6 + 0.35 − 0.9 = 0.05.
- Could events with P(A) = 0.6 and P(B) = 0.5 be mutually exclusive?
- No. If they were, P(A ∪ B) = 0.6 + 0.5 = 1.1, which is more than 1.
- How do you test two events for independence?
- Check whether P(A ∩ B) = P(A) × P(B). Example: 50 members, 20 in choir, 10 in band, 4 in both: 20/50 × 10/50 = 0.08 = 4/50, so they are independent.
- A bag has 4 black and 5 white counters. Find P(both black) with and without replacement
- With: 4/9 × 4/9 = 16/81. Without: 4/9 × 3/8 = 12/72 = 1/6. Without replacement the total and the count of the colour taken both fall by one.
- Each component fails with probability 0.3, independently. Find P(at least one of three fails)
- P(all work) = 0.7³ = 0.343, so P(at least one fails) = 1 − 0.343 = 0.657.
- What are the rules for tree diagrams?
- Branches from one point add to 1. Multiply along a path; add the paths that make up the event, since different paths are exclusive. All path probabilities add to 1.
- How do you find the probability of dependent picks in order?
- P(X then Y) = P(X) × P(Y given X). Example: 2 red and 6 yellow, no replacement, first red on the second pick: 6/8 × 2/7 = 3/14.
Revise Elementary ideas of probability further
- Study guideCambridge O Level Statistics: Independent events and selection with or without replacement (4040)
- Revision notesCambridge O Level Statistics: Independent events and selection with or without replacement (4040) – Revision Notes
- Practice questionsCambridge O Level Statistics: Independent events and selection with or without replacement (4040) – Practice Questions