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Flashcards · 9620 · A Level Topic 33
Nuclear magnetic resonance spectroscopy (A Level) flashcards
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3.3.15.1 Nuclear magnetic resonance spectroscopy
- Why is TMS, Si(CH₃)₄, used as the standard in NMR?
- It gives one intense signal (12 equivalent H, 4 equivalent C) at the low-δ end, clear of nearly all organic signals. It is inert and volatile, so it can be removed and the sample recovered.
- Why are ¹H NMR samples dissolved in CDCl₃ or CCl₄, not CHCl₃?
- CDCl₃ (deuterium, ²H) and CCl₄ (no H) give no ¹H signal. The ¹H in CHCl₃ would give a huge signal that swamps the sample’s.
- What does an integrated ¹H NMR spectrum show?
- The relative areas of the signals: the ratio of H atoms in each environment. Scale the simplest ratio to the molecular formula.
- The n+1 rule
- A ¹H signal is split into n + 1 peaks by n non-equivalent H on the adjacent carbon(s): 0 → singlet, 1 → doublet, 2 → triplet, 3 → quartet.
- 2H quartet + 3H triplet (¹H NMR)
- An ethyl group, CH₃CH₂–.
- 9H singlet (¹H NMR)
- (CH₃)₃C–.
- ¹³C vs ¹H NMR
- ¹³C shows carbon environments with no splitting; ¹H gives integration and splitting.
- What affects chemical shift (δ)?
- The molecular environment: an electronegative atom (O, Cl, Br) or a C=O group close to the nucleus gives a larger δ. Splitting, by contrast, counts H on the neighbouring carbons.
- How many ¹³C lines and ¹H signals does butanedione, CH₃COCOCH₃, give?
- 2 ¹³C lines (C=O and CH₃, by symmetry) and 1 ¹H signal (a singlet: all 6 H equivalent).
Revise Nuclear magnetic resonance spectroscopy further
- Study guideOxfordAQA A-Level Chemistry: Nuclear magnetic resonance spectroscopy (9620)
- Revision notesOxfordAQA A-Level Chemistry: Nuclear magnetic resonance spectroscopy (9620) – Revision Notes
- Practice questionsOxfordAQA A-Level Chemistry: Nuclear magnetic resonance spectroscopy (9620) – Practice Questions