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Practice Questions

Edexcel IGCSE Physics: Astrophysics — Practice Questions

Original exam-style practice questions with full worked answers on the solar system, orbits, stellar life cycles, red shift and the Big Bang.

Subject
Physics
Level
IGCSE
Topic
Astrophysics
Updated

Aligned to Pearson Edexcel IGCSE Physics (4PH1), Issue 4. Official specification .

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These are original questions written for Marlbridge, in the style and at the standard of the examination. They are not reproduced past-paper questions — examination boards hold copyright in their own papers. Use these alongside the official past papers available free from your board.

Related: Astrophysics revision notes


Section A

1. Place these in order of increasing size: galaxy, planet, solar system, universe, star. [2]

2. Explain why a planet in a circular orbit is accelerating even though its speed is constant. [2]

Section B

3. A satellite orbits at radius r with speed v.

(a) State the equation linking orbital speed, radius and period. [1] (b) Explain what happens to the orbital speed as the orbital radius increases. [2] (c) Explain why gravity causes a satellite to move in a circular orbit, and use the equation v = 2πr ÷ T together with g = v² ÷ r to explain why a satellite’s orbital period increases as its orbital radius increases. [3]

4. Describe the life cycle of a star with a mass similar to the Sun, from nebula to its final state. [5]

5. Describe how the life cycle differs for a star much more massive than the Sun. [4]

6. Light from distant galaxies is red-shifted.

(a) Explain what red shift means and what causes it. [3] (b) State the relationship between a galaxy’s distance and its speed of recession. [2] (c) Explain how red shift and CMB radiation support the Big Bang theory. [4]


Section C

7. A satellite orbits at radius 4.2 × 10⁷ m with a period of 8.64 × 10⁴ s (24 hours).

(a) Calculate its orbital speed. [2] (b) State one way in which a comet’s orbit typically differs from a planet’s orbit. [1]

8. A galaxy’s light shows a wavelength shift of 15 nm from a reference (laboratory) wavelength of 500 nm.

(a) Calculate the galaxy’s recession speed as a fraction of the speed of light, and as a value in m s⁻¹. [2] (b) A second galaxy is twice as far away. State, with a reason, what this implies about its red shift. [1]

9. Two stars appear equally bright when observed from Earth, but one is much further away than the other.

(a) Distinguish between absolute magnitude and apparent brightness. [2] (b) State what is plotted on each axis of a Hertzsprung-Russell (HR) diagram. [2] (c) Explain why comparing the two stars’ apparent brightness alone would not fairly compare their true luminosities. [2]


Answers

1. Planet, star, solar system, galaxy, universe [2 — 1 mark if one is misplaced].

2. Its direction is constantly changing, so its velocity changes even though the speed does not [1]; acceleration is the rate of change of velocity, and the gravitational force provides a centripetal acceleration towards the centre [1].

3. (a) v = 2πr ÷ T [1]. (b) The orbital speed decreases [1], because the gravitational field strength is weaker further out, so a smaller centripetal force and a slower speed are needed to maintain the orbit [1]. (c) Gravity provides the centripetal force needed to keep the satellite moving in a circle rather than travelling in a straight line [1]; combining v = 2πr ÷ T with g = v² ÷ r gives g = 4π²r ÷ T², so at a larger orbital radius the gravitational field strength g is smaller, meaning a lower orbital speed is needed to maintain the orbit [1]; since a larger r is now paired with a smaller v in v = 2πr ÷ T, the period T must be longer — more distant satellites take longer to orbit [1].

4. A nebula of dust and gas is pulled together by gravity [1]; as it contracts it heats up and nuclear fusion of hydrogen begins, forming a main sequence star, stable while the outward pressure from fusion balances gravity [1]. When the hydrogen in the core runs out it expands into a red giant [1]. The outer layers are then shed as a planetary nebula [1], leaving a hot dense core — a white dwarf — which cools to a black dwarf [1].

5. A massive star becomes a red supergiant rather than a red giant [1]. It then explodes as a supernova [1], during which the elements heavier than iron are formed and scattered into space [1]. The remnant core becomes a neutron star, or a black hole if the star is massive enough [1].

6. (a) The wavelength of light received from the galaxy is longer than the wavelength it was emitted at, shifted towards the red end of the spectrum [1]; this occurs because the galaxy is moving away from us [1]; the greater the recession speed, the greater the shift [1]. (b) The further away a galaxy is, the greater its red shift and so the faster it is moving away [1] — the speed is proportional to the distance [1]. (c) Red shift shows that all distant galaxies are receding and that the universe is expanding [1]; running the expansion backwards implies everything began from a single point [1]. The cosmic microwave background radiation fills the whole sky uniformly [1] and is the cooled remnant of the intense radiation from that early hot dense state — something the steady state theory cannot explain [1].

7. (a) v = 2πr ÷ T = 2π × 4.2 × 10⁷ ÷ 8.64 × 10⁴ [1] ≈ 3,050 m s⁻¹ [1]. (b) A comet’s orbit is typically much more elongated (elliptical) than the roughly circular orbits of planets and moons [1].

8. (a) v ÷ c = Δλ ÷ λ₀ = 15 ÷ 500 = 0.03 [1], so v = 0.03 × 3.00 × 10⁸ = 9.0 × 10⁶ m s⁻¹ [1]. (b) Because recession speed (and hence red shift) is proportional to distance, a galaxy twice as far away would show roughly twice the red shift [1].

9. (a) Absolute magnitude is how bright a star would appear at a fixed standard distance, allowing fair brightness comparisons [1]; apparent brightness is how bright it actually appears as observed from Earth, which depends on its real distance [1]. (b) Temperature (or colour) on one axis and luminosity (or absolute magnitude) on the other [2]. (c) Two stars can appear equally bright from Earth even with very different true luminosities, simply because the more luminous one is much further away [1]; only correcting for distance, as absolute magnitude does, allows their true luminosities to be compared fairly [1].


Where marks are usually lost

  • Saying an orbiting body is not accelerating because its speed is constant.
  • Confusing the fates of low-mass and high-mass stars.
  • Thinking red shift shows galaxies moving away from a fixed centre (with Earth at that centre) — in fact, space itself is expanding, so every observer sees the same pattern with no privileged centre.
  • Forgetting the CMB as separate evidence from red shift.
  • Confusing absolute magnitude (standard-distance brightness) with apparent brightness (brightness as observed).
  • Forgetting that Δλ/λ₀ = v/c requires the reference (laboratory) wavelength, not the observed wavelength, as the denominator.

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