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AP® Chemistry · Unit 5 · Topic 5.4

Elementary Reactions: Revision Notes (Chemistry 5.4)

One-page recap of elementary reactions, writing their rate laws from coefficients, molecularity and why three-particle collisions are rare, with the mistakes that cost marks.

Short on time? This page is the recap. For explanations and worked examples, use the full study guide.

Recap

  • An elementary reaction is one event: one particle reacts on its own, or two (rarely three) particles collide and react in that collision.
  • An overall reaction is the sum of one or more elementary steps.
  • A step’s rate depends on how often the right particles meet, which is proportional to the product of their concentrations.
  • So, for an elementary step only, each reactant’s coefficient is its order in the rate law. Products do not appear.
  • Molecularity is the number of reactant particles in the step.
  • Termolecular steps are rare: three particles must meet at the same instant with the right energy and orientation.

Key relationships

Elementary step Molecularity Rate law Units of k
A → products unimolecular k[A] s⁻¹
A + B → products bimolecular k[A][B] M⁻¹ s⁻¹
2A → products bimolecular k[A]² M⁻¹ s⁻¹
2A + B → products termolecular k[A]²[B] M⁻² s⁻¹

Testing an overall reaction:

Experimental rate law vs rate law from coefficients Conclusion
Different Not a single elementary step
Same One step is possible, but not proved
Four or more reactant particles Cannot be one step

Assumptions

  • You have been told the step is elementary. You cannot tell from the equation alone.
  • Temperature is constant, so k is constant.
  • The rate law is for the forward step only.

Mistakes to avoid

  1. Writing a rate law from the coefficients of an overall equation.
  2. Calling 2A → products unimolecular. Count particles, not substances.
  3. Putting products in the rate law.
  4. Saying termolecular steps are impossible (they are rare).
  5. Treating a matching rate law as proof of a single step.

Quick self-check

  1. Write the rate law for the elementary step NO + NO₃ → 2 NO₂. (rate = k[NO][NO₃]; bimolecular)
  2. For the elementary step A + 2B → products, by what factor does the rate change if [B] doubles? (× 4)
  3. And if [A] and [B] both double? (× 8)
  4. What are the units of k for a termolecular step? (M⁻² s⁻¹)
  5. An overall reaction 2X + Y → Z has rate = k[X][Y]. Can it be one step? (No: one step would give k[X]²[Y].)

Next: practice questions.

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