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AP® Chemistry · Unit 7 · Topic 7.10

Reaction Quotient and Le Châtelier's Principle: Revision Notes (Chemistry 7.10)

One-page recap of how a stress makes Q differ from K, how to predict the direction of reaction, and why only temperature changes the value of K.

Short on time? This page is the recap. For explanations, a Q–K diagram and three worked examples, use the full study guide.

Recap

  • Q has the same form as K but uses the concentrations (or partial pressures) at any moment.
  • At equilibrium Q = K. A stress makes Q ≠ K, so the system is no longer at equilibrium.
  • The system reacts until Q = K again. The new equilibrium has different concentrations.
  • Most stresses change Q. A temperature change alters K.

Key relationships

Relationship Meaning Use it to
Q < K Too few products Predict a net forward reaction
Q > K Too many products Predict a net reverse reaction
new Q = s^Δn × K Every concentration scaled by s; Δn = product coefficients − reactant coefficients (gases, or dissolved species) Handle volume changes (halve V: s = 2) and dilution (double V: s = ½)
Exothermic: T up → K down Heating favours the reverse reaction Predict the effect of temperature on K
Endothermic: T up → K up Heating favours the forward reaction

Assumptions behind the numbers

  • The system was at equilibrium before the stress, so Q = K at the start.
  • The temperature is constant unless the question changes it; K is only fixed at a fixed temperature.
  • Solids, pure liquids and solvent water are left out of Q, just as they are left out of K.

Mistakes to avoid

  1. Reversing the rule. Q > K means reverse, not forward.
  2. Changing K when you add a species. Only temperature changes K.
  3. Changing Q when you heat a rigid flask. The concentrations stay the same at that instant; K moves.
  4. Forgetting to raise terms to their coefficients when you scale concentrations.
  5. Expecting old concentrations to return. Only the ratio in Q returns to K.

Quick self-check

  1. A mixture has Q = 0.80 and K = 0.25. Which way does it react? (Reverse: Q > K.)
  2. For N₂O₄(g) ⇌ 2NO₂(g) at equilibrium, the volume is halved. What is the new Q in terms of K? (Q = 2K, so the reaction goes in reverse.)
  3. For A(aq) ⇌ 2B(aq) at equilibrium, the solution is diluted to twice its volume. What is the new Q? (Q = ½K, so the reaction goes forward.)

Next: practice questions.

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