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AP® Chemistry · Unit 7 · Topic 7.7

Calculating Equilibrium Concentrations: Revision Notes (Chemistry 7.7)

One-page recap of Q versus K, dynamic equilibrium, ICE tables and the shortcuts for solving them, with the mistakes that cost marks in equilibrium calculations.

Short on time? This page is the recap. For explanations and worked examples, use the full study guide.

Recap

  • To predict equilibrium concentrations you need the balanced equation, the initial concentrations or partial pressures, and K.
  • Step 1: calculate Q from the starting values and compare it with K. The mixture always changes so that Q moves towards K.
  • Step 2: build an ICE table, substitute the Equilibrium row into K and solve for x.
  • At equilibrium (Q = K) the forward and reverse rates are equal. Both reactions continue, but concentrations stay constant. This is dynamic equilibrium.

Key relationships

Idea Rule Use it to
Q < K net forward reaction; reactants fall, products rise set the signs in the Change row
Q > K net reverse reaction; products fall, reactants rise set the signs in the Change row
Q = K no net change; forward rate = reverse rate recognise a mixture already at equilibrium
Change row changes in the ratio of the coefficients (−x, −2x, +3x …) write every species in terms of one unknown
c = n / V mol L⁻¹ from moles and litres get concentrations before using Kc
Small-x check x < about 5% of the starting value decide whether c − x ≈ c is acceptable

Assumptions behind the numbers

  • The temperature is constant; K only applies at the temperature it was measured at.
  • Pure solids and liquids are left out of K and out of the ICE table.
  • Kc uses concentrations; Kp uses partial pressures. Use the one the question gives. Converting between them is not assessed.
  • In the small-x shortcut, you assume very little reacts. You must check this assumption afterwards.

Mistakes to avoid

  1. Putting initial values into K. They give Q, not K.
  2. Ignoring coefficients. A coefficient of 2 gives a change of 2x, squared in K as (2x)².
  3. Assuming a forward reaction. Compare Q with K first.
  4. Using moles in Kc. Divide by the volume.
  5. Forcing the small-x shortcut. If x is more than about 5% of the starting value, solve the quadratic.
  6. Keeping a root that gives a negative concentration. Only one root makes physical sense.
  7. Thinking equilibrium means equal amounts or no reaction. It means constant amounts and equal rates.

Quick self-check

  1. For A(g) ⇌ 2 B(g), Kc = 0.10. A mixture has [A] = 0.50 mol L⁻¹ and [B] = 0.30 mol L⁻¹. Which way does it react? (Q = 0.30² ÷ 0.50 = 0.18 > 0.10, so backwards: B falls, A rises)
  2. For 2 G ⇌ H going forwards, [G] falls by 0.30 mol L⁻¹. By how much does [H] rise? (0.15 mol L⁻¹)
  3. For Z ⇌ Y, Kc = 4.0. A flask starts with [Z] = 1.00 mol L⁻¹ and no Y. Find the equilibrium concentrations. (x ÷ (1.00 − x) = 4.0, so x = 0.80: [Y] = 0.80 mol L⁻¹, [Z] = 0.20 mol L⁻¹)

Next: practice questions.

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