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AP® Physics 1: Algebra-Based · Unit 5 · Topic 5.3

Torque: Revision Notes (Physics 1 5.3)

One-page recap of torque for the algebra-based course: τ = rF sin θ, perpendicular components, lever arms, force diagrams and the mistakes that cost marks.

Short on time? This page is the recap. For explanations, diagrams and worked examples, use the full study guide. This is the algebra-based course: no calculus is needed.

Recap

  • Model the object as a rigid system: its shape does not change, so one angle describes its rotation.
  • Choose and state the axis of rotation. Every torque is measured about that axis.
  • Torque measures how strongly a force tends to turn the object. It depends on the size of the force, where it acts and its direction.
  • Only the force component perpendicular to r (the line from the axis to the point of application) causes turning. The component along r does nothing to the rotation.
  • The lever arm is the perpendicular distance from the axis to the force’s line of action.
  • A force diagram is a free-body diagram in which each force is drawn at the point where it acts. Weight acts at the centre of mass.
  • Label each torque clockwise or counterclockwise for bookkeeping. The vector direction of torque is not part of this course.

Key relationships

Relationship Symbols and units Use it when
τ = rF sin θ r in m, F in N, θ between r and F; τ in N·m you know r, F and the angle
τ = rF⊥, with F⊥ = F sin θ F⊥ in N the force is already split into components
τ = r⊥F, with r⊥ = r sin θ r⊥ in m the line of action is easy to draw
τ = 0 the force acts at the axis, or its line of action passes through it
τ_new / τ_old = (F ratio)(r ratio)(sin θ ratio) a factor-of-change question

Assumptions behind the numbers

  • The object is rigid: forces do not bend or stretch it.
  • Each force acts at a single point. Gravity on a rigid object acts at its centre of mass; for a uniform rod, its middle.
  • Near Earth’s surface, g = 9.8 m/s².
  • The angle θ is measured between the vectors r and F placed tail to tail.

Mistakes to avoid

  1. No axis stated. The same force has different torques about different axes.
  2. Using r instead of the lever arm when the force is not at 90° to r.
  3. Using the wrong angle. Convert any angle “to the surface” or “to the vertical” into the angle between r and F.
  4. Ignoring forces at the axis. They are on the force diagram, but their torque about that axis is zero.
  5. Drawing all forces from the centre. For torque, draw each force where it acts.
  6. Writing joules instead of N·m.
  7. Calculator in radians when the angle is in degrees.

Quick self-check

  1. A 25 N force acts at right angles to a rod, 0.40 m from the axis. Find the torque. (10 N·m)
  2. A 30 N force acts 0.50 m from the axis at 30° to r. Find the torque. (7.5 N·m)
  3. A rope pulls on a pole with its line of action passing straight through the pivot. What torque does it exert about the pivot? (Zero: the lever arm is zero.)

Next: practice questions.

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