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AP® Physics 2: Algebra-Based · Unit 14 · Topic 14.7

Diffraction: Revision Notes (Physics 2 14.7)

One-page recap of diffraction: the gap-size rule, why a single slit gives bands, the dark-fringe condition a sin θ = mλ, y_min = mλL/a and how the pattern responds to changes.

Short on time? This page is the recap. For Figures 1 to 3 and the worked examples, use the full study guide.

Recap

  • Diffraction: a wave spreads out as it passes through an opening or around the edge of an obstacle. All waves do it.
  • Gap-size rule: spreading is strongest when the opening width a is comparable to λ. If a is much larger than λ, the wave passes nearly straight through with a sharp shadow.
  • Diffraction does not change v, f or λ. Only the direction of travel spreads.
  • Single slit: wavelets from all parts of the slit start in step and interfere on the screen. Result: a wide, bright central band, then dark fringes and dimmer side bands.
  • Whether wavelets add or cancel depends on their path length difference. Between the two edges of the slit, ΔL = a sin θ.
  • Shape matters: a narrow slit gives stripes; a round hole gives a bright disc with rings. Narrower in a direction means more spreading in that direction.

Key relationships

Relationship Symbols and units Use it to
ΔL = a sin θ a = slit width (m); θ from the normal find the edge-to-edge path difference
a sin θ = mλ, m = ±1, ±2, … λ in m find the angle of a dark fringe
y_min = mλL/a L = slit-to-screen distance (m); y from the centre (m) locate dark fringes when θ < about 10°
central band width = 2λL/a side bands are λL/a wide compare band widths
pattern width ∝ λL/a λ = v/f predict factor changes

Assumptions behind the numbers

  • The light is monochromatic (one wavelength) and reaches the whole slit in step.
  • The screen is far away: L is much larger than a, so rays to one point are nearly parallel.
  • y_min = mλL/a needs small angles. Check sin θ = mλ/a; if θ is above about 10°, use tan θ = y/L instead.
  • All lengths are in metres before substituting.

Mistakes to avoid

  1. Calling a sin θ = mλ the bright condition. For one slit it marks the dark fringes.
  2. Treating m = 0 as dark. The centre is the brightest point.
  3. Narrower slit, narrower pattern. Wrong way round: the pattern width ∝ 1/a.
  4. Forgetting the central band is double width. It spans −y₁ to +y₁.
  5. Changing f but forgetting λ changes. In the same medium, doubling f halves λ and halves the pattern.
  6. Mixing nm and mm. Convert both to metres.

Quick self-check

  1. Light of wavelength 500 nm passes through a slit 0.10 mm wide onto a screen 2.0 m away. How far is the first dark fringe from the centre, and how wide is the central band? (10 mm; 20 mm)
  2. The slit width is doubled and nothing else changes. What happens to the width of the central band? (It halves.)
  3. At a point on the screen, the edge-to-edge path difference across the slit is 2λ. Is that point bright or dark? (Dark: it is the second-order minimum.)
  4. Why does sound spread through a doorway much more than light does? (Sound wavelengths are comparable to the doorway width; light wavelengths are about a million times smaller.)

Next: practice questions.

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