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Flashcards · 4024 · Topic 3
Coordinate geometry flashcards
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Topic 3: Coordinate geometry
- Gradient (meaning)
- How much y changes for each 1 unit increase in x. Rising to the right is positive; falling to the right is negative.
- Gradient of the line through (x₁, y₁) and (x₂, y₂)
- m = (y₂ − y₁) ÷ (x₂ − x₁) Subtract in the same order on top and below.
- Length of the line segment from (x₁, y₁) to (x₂, y₂)
- √((x₂ − x₁)² + (y₂ − y₁)²)
- Midpoint of (x₁, y₁) and (x₂, y₂)
- ((x₁ + x₂)/2, (y₁ + y₂)/2): add the coordinates and halve each.
- Find the midpoint and length of the segment from (−1, −2) to (5, 6)
- Midpoint: (4/2, 4/2) = (2, 2). Length: √(6² + 8²) = √100 = 10.
- In y = mx + c, what do m and c stand for?
- m is the gradient (the number multiplying x); c is the y-intercept, where the line crosses the y-axis (x = 0).
- Find the gradient and y-intercept of 3x − 4y = 24
- Rearrange: −4y = 24 − 3x, so y = (3/4)x − 6. Gradient 3/4, y-intercept −6.
- Parallel lines and perpendicular lines: gradient rules
- Parallel: equal gradients, m₁ = m₂. Perpendicular: m₁ × m₂ = −1, so the perpendicular gradient is −1/m (flip the fraction and change the sign).
- Find the line parallel to y = 3x + 1 through (2, 5)
- Gradient 3. Substitute: 5 = 3 × 2 + c, so c = −1. y = 3x − 1
- Perpendicular bisector (meaning)
- A line that cuts a line segment in half at 90°.
- How do you find the equation of the perpendicular bisector of PQ?
- 1. Find the midpoint of PQ. 2. Find the gradient of PQ. 3. Take the perpendicular gradient −1/m. 4. Use y − y₁ = m(x − x₁) through the midpoint.
- The lines x = 3 and y = 3: how do they differ?
- x = 3 is vertical, through (3, 0); its gradient is undefined. y = 3 is horizontal, through (0, 3); its gradient is 0.