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Flashcards · 9620 · AS Topic 24

Organic analysis (AS Level) flashcards

13 cards on AS Topic 24, subtopics 3.3.6.1 to 3.3.6.3. Pick a subtopic or study them all.

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3.3.6.1 Identification of functional groups by test tube reactions

Test for a primary or secondary alcohol
Warm with acidified potassium dichromate(VI): orange → green. A tertiary alcohol (or a ketone) leaves it orange.
Test for a carboxylic acid
Add Na₂CO₃(aq): fizzing; the CO₂ turns limewater milky.
Why must aldehydes be ruled out before using dichromate(VI) to test for an alcohol?
Aldehydes are also oxidised by dichromate(VI), so they also turn it from orange to green.
Which two compound types does no AS test-tube reaction separate?
A ketone and a tertiary alcohol: neither reacts with dichromate(VI), Fehling’s or Tollens’. Use IR (C=O vs O–H).
Required practical 5: why heat organic test mixtures in a water bath?
Most of the organic liquids are flammable, so no naked flame.

3.3.6.2 Mass spectrometry

How does high-resolution mass spectrometry identify a molecular formula?
Formulae with the same integer Mr have different precise masses. The m/z of the molecular ion to 4 decimal places is matched against the precise mass of each candidate formula.
Molecular ion at m/z 90.0678: C₄H₁₀O₂ or C₃H₆O₃? (C 12.0000, H 1.0078, O 15.9949)
C₄H₁₀O₂: 48.0000 + 10.0780 + 31.9898 = 90.0678 (match). C₃H₆O₃: 36.0000 + 6.0468 + 47.9847 = 90.0315.
What can mass spectrometry of the molecular ion not tell you?
The structure: many isomers share a molecular formula. IR, test-tube reactions or fingerprint comparison are needed to go further.

3.3.6.3 Infrared spectroscopy

IR absorptions: O–H in alcohols vs O–H in carboxylic acids
Alcohol O–H: broad, 3230–3550 cm⁻¹. Acid O–H: very broad, 2500–3000 cm⁻¹ (merges with C–H).
IR absorptions for C=O, C=C and C≡N
C=O: 1680–1750 cm⁻¹ (strong, sharp). C=C: 1620–1680 cm⁻¹. C≡N: 2220–2260 cm⁻¹.
Fingerprint region
Below about 1500 cm⁻¹. Its pattern is characteristic of the whole molecule, so comparing it with spectra of known compounds identifies the substance.
A product expected to be an aldehyde shows a very broad band at 2500–3000 cm⁻¹. What does it show?
Impurity of a carboxylic acid, from over-oxidation.
How do CO₂, methane and water vapour contribute to global warming?
Their C=O, C–H and O–H bonds absorb infrared emitted by the Earth’s surface; the energy is re-emitted in all directions, some back towards the surface.