Revision Notes
Forces and Motion: Revision Notes
Condensed recall notes on Newton’s laws, F = ma, friction, terminal velocity and stopping distance for Cambridge O Level Physics 5054.
- Subject
- Physics
- Level
- O LEVELS
- Topic
- Motion, forces and energy
- Author
- Iftikhar Azeemi
- Updated
- Reviewed by
- Hassan (what this means)
Aligned to Cambridge O Level Physics (5054), 2026-2028. Official specification .
Syllabus page (what it covers and how it is assessed): Cambridge O Level Physics.
Syllabus points this page covers
5054
- 1.5 Forces
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Need help with this topic? Request a free trial class for O Level Physics (5054).
Condensed for the final weeks. For the full explanation, use the Forces and Motion study guide, and for exam-style practice with mark-scheme answers see the Forces and Motion practice questions.
Types of force
The syllabus names nine forces you should be able to recognise: weight, friction, drag, air resistance, tension, electrostatic force, magnetic force, thrust, and contact force. A free-body diagram shows only the object of interest, with one arrow per force acting on it — arrow length roughly shows size, arrow direction shows direction. Draw one before calculating anything; it is the fastest way to spot the resultant.
Newton’s three laws
| Law | Statement | What it means in practice |
|---|---|---|
| First | An object stays at rest or at constant velocity unless acted on by a resultant force | Constant velocity ⇒ zero resultant force |
| Second | Resultant force produces acceleration in its direction | F = m a |
| Third | If object A exerts a force on object B, then object B exerts an equal and opposite force on object A (“action and reaction”) | The pair acts on two different objects |
The equation
F = m a F in newtons, m in kg, a in m/s2
weight: W = m g (g ≈ 9.8 N/kg on Earth)
Mass is the amount of matter in kg and never changes. Weight is a force in newtons and changes with gravitational field strength.
Worked example. A resultant force of 15 N acts on a 3 kg object.
a = F / m = 15 / 3 = 5 m/s2
Resultant force
Forces along one line add algebraically. Direction matters — forces are vectors.
Driving force 4000 N forward, drag 1500 N backward
Resultant = 4000 - 1500 = 2500 N forward
The driving force is not the resultant — the resultant is what remains after drag and friction. This is the single most common error in the topic.
Circular motion (qualitative)
A resultant force acting perpendicular to an object’s motion changes its direction without (necessarily) changing its speed — this is how circular motion works. With everything else held constant:
- Speed increases if force increases.
- Radius decreases if force increases — a tighter circle needs a bigger force at the same speed.
- A bigger mass needs a bigger force to keep speed and radius the same.
F = mv2/r is not required at this level — give the qualitative
relationships only, never the equation.
Terminal velocity
- Object falls; only weight acts → maximum acceleration.
- Speed rises → drag increases.
- Drag grows until drag = weight → resultant = 0.
- Acceleration = 0 → constant terminal velocity.
On a velocity–time graph the line flattens — the object does not slow down.
Stopping distance
stopping distance = thinking distance + braking distance
| Increased by | |
|---|---|
| Thinking distance | Speed (∝ v), tiredness, alcohol, drugs, distraction |
| Braking distance | Speed (∝ v²), wet or icy roads, worn tyres, worn brakes, heavy load |
Doubling speed doubles thinking distance but quadruples braking distance.
Third-law pairs — how to check
A genuine pair: same type of force · equal size · opposite direction · acting on two different bodies. Same type of force is the check most students skip — a weight force can only pair with another weight force, never with a contact force, even if the sizes happen to match.
A book on a table: weight (Earth on book) and normal contact force (table on book) both act on the book, so they are a first-law balance, not a third-law pair.
Exam traps
- Confusing mass with weight, or their units.
- Treating the driving force as the resultant.
- Saying an object at terminal velocity “has no forces on it” — it has no resultant force.
- Naming a third-law pair that acts on the same object.
- Forgetting braking distance scales with v², not v.
- Trying to use
F = mv2/r— it is explicitly excluded from this syllabus; answer circular-motion questions with the qualitative trends only. - Skipping the free-body diagram and guessing the resultant — draw the arrows first.
Self-test
- A 1500 kg car accelerates at 2 m/s². Find the resultant force.
- If drag on that car is 600 N, what is the driving force?
- Explain terminal velocity in three steps.
- Why is the weight of a book and the table’s push on it not a third-law pair?
- A car doubles its speed. What happens to thinking and braking distance?
- Name the nine force types the syllabus expects you to recognise.
- A ball on a string is swung in a horizontal circle at constant speed. If the string is shortened while the speed stays the same, what happens to the force needed, and why?
Answers: 1. F = 1500 × 2 = 3000 N. 2. 3000 + 600 = 3600 N. 3. Weight causes acceleration; drag increases with speed; when drag equals weight the resultant is zero and velocity becomes constant. 4. Both forces act on the same object (the book); a third-law pair must act on two different bodies. 5. Thinking distance doubles; braking distance quadruples. 6. Weight, friction, drag, air resistance, tension, electrostatic force, magnetic force, thrust, contact force. 7. The force needed increases — with speed and mass unchanged, a smaller radius needs a bigger centre-seeking force to keep the ball on its (now tighter) circular path.
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