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IB DP Mathematics: Applications and Interpretation – Geometry and Trigonometry Strand Revision Notes

Condensed revision notes on the Geometry and trigonometry strand of IB Diploma Programme Mathematics: Applications and Interpretation – real-world spatial problems, vectors, and technology-driven modelling – with worked reminders and self-test questions.

Level
IB
Topic
Geometry and trigonometry
Updated

Aligned to International Baccalaureate IB Diploma Programme Mathematics: Applications and Interpretation (DP Mathematics: Applications and Interpretation), First assessment 2021. Official specification .

Syllabus page (what it covers and how it is assessed): IB Diploma Programme Mathematics: Applications and Interpretation.

Syllabus points this page covers

DP Mathematics: Applications and Interpretation

  • 3 Geometry and trigonometry (whole topic)

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Geometry and trigonometry carries 18 hours at SL and jumps to 46 at HL – the largest proportional SL-to-HL increase of the five strands, as the full syllabus guide sets out. The additional higher level content behind that jump is radians and circular functions, matrix transformations, vectors and graph theory (AHL 3.7-3.16). These notes work through the strand’s applied, technology-driven approach, alongside the strand revision notes for Statistics and probability and the subject overview already on the site.

What makes this strand distinctive in Applications and Interpretation

Unlike Analysis and Approaches’ more abstract, proof-oriented treatment of the same strand name, this course frames geometry and trigonometry around real-world spatial problems – navigation, design, and physical measurement contexts – and every external paper allows technology throughout, so questions routinely expect a graphical display calculator to be used, not avoided.

Core content

  • Geometry – properties of shapes in two and three dimensions, surface area and volume of compound solids, and geometric reasoning applied to real contexts such as construction or design.
  • Trigonometry – right-angled and non-right-angled triangle trigonometry (sine rule, cosine rule, area of a triangle formula), angles of elevation and depression, and bearings – the classic navigation-style application this course favours.
  • Radians and circular functions (HL only, AHL 3.7-3.8) – the definition of a radian, and the definitions of cosine and sine as circular functions.
  • Matrix transformations (HL only, AHL 3.9) – geometric transformations using matrices.
  • Vectors (HL only, AHL 3.10-3.13) – position and displacement vectors, the vector equation of a line, vector applications to kinematics (problems of motion) and intersection, and the scalar and vector products.
  • Graph theory (HL only, AHL 3.14-3.16) – graphs, vertices and edges; adjacency matrices and walks; tree and cycle algorithms.

Worked example: bearings and the cosine rule

A ship sails from port A on a bearing of $070°$ for 40 km to point B, then changes course to a bearing of $150°$ and sails a further 25 km to point C. Find the distance AC.

This is a two-sides-and-the-included-angle (SAS) setup, so the cosine rule applies – not the sine rule, per the table above.

Back-bearing
at B:            the bearing from B back to A is the bearing A-to-B
                 (070 deg) plus 180 deg, i.e. 250 deg -- this is the
                 step most students lose marks on, since it must be
                 found before the interior angle can be
Angle at B:      interior angle ABC = back-bearing (250 deg) minus the
                 onward bearing (150 deg) = 100 deg
Apply cosine
rule:            AC^2 = AB^2 + BC^2 - 2(AB)(BC)cos(angle ABC)
Substitute:      AC^2 = 40^2 + 25^2 - 2(40)(25)cos(100 deg)
                 Because angle ABC = 100 deg is obtuse, cos(100 deg) is
                 NEGATIVE (approx -0.1736), which makes the whole
                 "-2(40)(25)cos(100 deg)" term ADDITIVE, not
                 subtractive:
                 AC^2 = 1600 + 625 - 2000(-0.1736) = 2225 + 347.3 = 2572.3
Solve:           AC = sqrt(2572.3) = 50.7 km (3 sig figs)

The mathematics (cosine rule) is routine once the angle is correctly identified – the applied skill this course specifically tests is converting bearings into an interior angle correctly, which is why bearings problems reward a clear diagram before any calculation begins. A student who mis-derives the angle as 80° instead of 100° (by forgetting the back-bearing step) would get AC = 43.3 km instead – exactly the kind of error this worked example is designed to defuse.

Sine rule vs cosine rule – which to use

Given Use
Two sides and the angle between them (SAS), or three sides (SSS) Cosine rule
Two angles and a side, or two sides and a non-included angle Sine rule

Always sketch the triangle first and label knowns before choosing a rule – misapplying the sine rule to an SAS triangle is one of the most common technique errors in this strand.

Surface area and volume of compound solids

Because this course frames geometry around real-world design and construction contexts, questions frequently present a compound solid — for example a cylinder topped with a hemisphere, or a pyramid combined with a cuboid — rather than a single standard shape. The reliable method is to split the compound solid into its recognisable component shapes, calculate each one’s surface area or volume separately using the standard formulae, then add or subtract components as the shape requires (subtracting, for instance, where one solid has a cavity removed from another). Sketching the solid and labelling which faces are “internal” (and therefore excluded from a surface area total) before calculating is the single most effective way to avoid the most common error in this content: including or excluding the wrong faces from a compound surface area.

Exam traps

  • Converting a bearing into an interior triangle angle incorrectly, especially when the bearing at the vertex is a “reverse” bearing (add or subtract 180°) rather than the forward one.
  • Choosing the sine rule for an SAS or SSS triangle where the cosine rule is required.
  • Forgetting that HL vector questions on lines and intersection require setting the parametric forms of two lines equal and solving simultaneously, not just comparing direction vectors alone.
  • Not using the graphical display calculator to sanity-check an answer, when every paper in this course permits technology throughout.

Quick revision checklist

  • Practise converting a bearing into an interior triangle angle correctly before attempting the cosine or sine rule calculation.
  • Memorise which rule (sine or cosine) applies to SAS, SSS, ASA and SSA triangle information.
  • Split at least three different compound-solid shapes into components and practise both surface area and volume calculations for each.
  • For HL vectors, practise setting two lines’ parametric equations equal to test for intersection.

Self-test

  1. Which rule should be used when given two sides and the included angle?
  2. What is the first practical step recommended for any bearings problem?
  3. Which parts of this strand are HL-only?
  4. How does this strand’s framing differ from Analysis and Approaches’ treatment of the same strand name?
  5. Why is checking with a graphical display calculator especially relevant in this course?

Answers: 1. The cosine rule (SAS). 2. Sketching the triangle and clearly labelling the known sides, angles and bearings before starting any calculation. 3. Radians and circular functions, matrix transformations, vectors, and graph theory (AHL 3.7-3.16). 4. Applications and Interpretation frames geometry and trigonometry around real-world spatial problems (navigation, design) with heavy technology use, whereas Analysis and Approaches treats the same strand more abstractly with less emphasis on applied context. 5. Because every external paper in this course allows technology throughout, so using the calculator to verify an algebraic or trigonometric answer is both permitted and expected, unlike Analysis and Approaches’ no-technology Paper 1.

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