Study Guides
OCR GCSE Mathematics: Percentages and ordering fractions, decimals and percentages (J560)
Step-by-step study guide to OCR GCSE Mathematics percentages, multipliers, original-value problems, simple interest and ordering, with worked examples.
- Subject
- Mathematics
- Level
- GCSE
- Topic
- Percentages and ordering fractions, decimals and percentages
- Author
- Marlbridge Academic Team
- Updated
Aligned to OCR GCSE Mathematics (J560), Version 2.1 (August 2026), for first assessment in 2017. Official specification .
Syllabus page (what it covers and how it is assessed): OCR GCSE Mathematics.
Syllabus points this page covers
J560
- 2.03 Percentages
- 2.04 Ordering fractions, decimals and percentages
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This guide teaches sections 2.03 and 2.04 of the OCR GCSE (9-1) Mathematics (J560) specification, Version 2.1 (August 2026): percentages, percentage change and simple interest, and ordering fractions, decimals and percentages. All of it is Foundation and Higher tier content, and none of it is Higher tier only. The specification lists a Paper 2 (Foundation) and a Paper 5 (Higher) where a calculator is not permitted, so the by-hand methods below matter. Pair it with the revision notes and the practice questions. For wider fraction work see the fractions, decimals and percentages overview. The OCR GCSE Mathematics hub and the printable checklist show the rest of the course, and the free diagnostics help you find weak spots first.
What this unit covers
| Ref | What you must be able to do | Tier |
|---|---|---|
| 2.03a | Convert between fractions, decimals and percentages | Both |
| 2.03b | Know a percentage is parts per hundred; find a percentage of a quantity; write one quantity as a percentage of another | Both |
| 2.03c | Increase or decrease by a percentage using decimal or fractional multipliers; percentage change; original-value problems; simple interest | Both |
| 2.04a | Order integers, fractions, decimals and percentages | Both |
| 2.04b | Use the symbols <, >, ≤, ≥, =, ≠ | Both |
Compound interest and growth and decay sit in section 5.03a, so they are not taught here.
2.03a Converting between forms
“Percent” means “out of 100”. So 35% means 35 parts per hundred, which is 35/100 and 0.35. Every conversion moves between those three forms.
| From | To | Method |
|---|---|---|
| Percentage | Decimal | Divide by 100 |
| Decimal | Percentage | Multiply by 100 |
| Percentage | Fraction | Write over 100 and simplify |
| Fraction | Decimal | Divide the numerator by the denominator |
| Fraction | Percentage | Convert to a decimal, then multiply by 100 |
Worked example 1. Write 7/20, 3/8 and 1¾ as percentages.
7/20 = 0.35 → 35%
3/8 = 3 ÷ 8 = 0.375 → 37.5%
1¾ = 1.75 → 175%
A fraction with denominator 20 scales to hundredths: 7/20 = 35/100. A value above 1 gives a percentage above 100%.
Worked example 2. Write 45% as a fraction in its simplest form, and 0.4% as a decimal.
45% = 45/100 = 9/20 (divide top and bottom by 5)
0.4% = 0.4 ÷ 100 = 0.004
Keep the decimal point moving two places each time. A small percentage such as 0.4% is far smaller than 0.4.
2.03b Percentage of a quantity
To find a percentage of a quantity without a calculator, build it from 10%, 5% and 1%.
Worked example 3. Find 15% of £84.
10% of 84 = 8.40
5% of 84 = 4.20 (half of 10%)
15% of 84 = 8.40 + 4.20 = £12.60
Worked example 4. Find 7% of 350 kg.
1% of 350 = 3.5
7% of 350 = 7 × 3.5 = 24.5 kg
With a calculator, multiply by the decimal: 15% of 84 is 0.15 × 84.
One quantity as a percentage of another
Write a fraction “part over whole”, then multiply by 100. Both quantities need the same units.
Worked example 5. A film lasts 2 hours. Mia watches 45 minutes. What percentage is that?
2 hours = 120 minutes
45/120 × 100 = 37.5%
The whole is the quantity after “of”. Here it is 120 minutes, so 120 goes underneath.
2.03c Increase and decrease with multipliers
Adding 10% to a price keeps 100% and adds 10%, giving 110%. As a decimal that is 1.1, or 110/100. Multiplying by 1.1 does the whole job in one step.
| Change | Percentage kept | Multiplier |
|---|---|---|
| Increase by 8% | 108% | 1.08 |
| Decrease by 18% | 82% | 0.82 |
| Increase by 1/5 | 6/5 | 6/5 or 1.2 |
| Decrease by 3/8 | 5/8 | 5/8 or 0.625 |
Increase multipliers are greater than 1. Decrease multipliers are less than 1.
Worked example 6. A coat costs £720. It is reduced by 18%. Find the sale price.
multiplier = 1 − 0.18 = 0.82
720 × 0.82 = £590.40
By hand, you can find 18% as 10% + 5% + 3%, then subtract: 72 + 36 + 21.60 = 129.60, and 720 − 129.60 = 590.40. Both routes agree.
Worked example 7. A mass of 35 kg is increased by 1/5. Find the new mass.
multiplier = 1 + 1/5 = 6/5
35 × 6/5 = 42 kg
Percentage change
Percentage change compares the change with the original value.
percentage change = (new − original) ÷ original × 100
Worked example 8. A bus fare rises from £48 to £60. Find the percentage increase.
change = 60 − 48 = 12
12/48 × 100 = 25% increase
The multiplier route gives the same result: 60 ÷ 48 = 1.25, which is a 25% increase.
Worked example 9. The price of a bag falls from £80 to £68.
change = 68 − 80 = −12
−12/80 × 100 = −15%
State the direction: a 15% decrease.
Original-value (reverse percentage) problems
Here you know the value after a change and must work back to the start. Treat the original as 100%, find the percentage the new value represents, and divide by the multiplier.
Worked example 10. After a 20% rise, a gym fee is £90. Find the original fee.
new = 120% of original → multiplier 1.2
original = 90 ÷ 1.2 = £75
Worked example 11. A population of 2,800 is 1.4 times last year’s. Find last year’s population.
2800 ÷ 1.4 = 2000
Check by going forwards. £75 × 1.2 = £90. Always do this check. Taking 20% off £90 gives £72, which is not £75, so that tempting shortcut is wrong.
Simple interest
Simple interest is a fixed sum added each year, always calculated on the original deposit.
interest per year = amount × rate ÷ 100
total interest = interest per year × number of years
Worked example 12. Find the simple interest on £1,500 at 3% per year for 4 years, and the total amount.
per year: 1500 × 3/100 = £45
4 years: 4 × 45 = £180
total = 1500 + 180 = £1,680
Worked example 13. £800 earns £96 simple interest in 3 years. Find the yearly rate.
per year = 96 ÷ 3 = £32
rate = 32/800 × 100 = 4%
2.04a Ordering fractions, decimals and percentages
Convert everything to one form, usually decimals. Then compare digit by digit after writing the same number of decimal places. Finally, write the answer in the original forms.
Worked example 14. Put 13/20, 0.66, 64%, 2/3 and −0.7 in order, smallest first.
13/20 = 0.65
0.66 = 0.66
64% = 0.64
2/3 = 0.6667 (to 4 d.p.)
−0.7 = −0.70
Negatives are smaller than positives, so −0.7 is first. Then 0.64 < 0.65 < 0.66 < 0.6667.
Answer: −0.7, 64%, 13/20, 0.66, 2/3.
When fractions are compared directly, use a common denominator. For 3/4, 5/7 and 7/10, use 140:
3/4 = 105/140 5/7 = 100/140 7/10 = 98/140
Smallest first: 7/10, 5/7, 3/4.
For negatives, a larger digit means a smaller number. So −2.5 is smaller than −2.05.
2.04b Inequality symbols
| Symbol | Meaning |
|---|---|
| < | is less than |
| > | is greater than |
| ≤ | is less than or equal to |
| ≥ | is greater than or equal to |
| = | is equal to |
| ≠ | is not equal to |
The small end of < and > points at the smaller number.
Worked example 15. Insert a symbol.
3/8 ... 0.4 3/8 = 0.375, so 3/8 < 0.4
45% ... 9/20 both are 0.45, so 45% = 9/20
−2.5 ... −2.05 −2.5 is further below zero, so −2.5 < −2.05
Worked example 16. List the integers n with −2 ≤ n < 3.
The ≤ includes −2. The < excludes 3. So n is −2, −1, 0, 1, 2.
Common errors
- Writing 0.4% as 0.4 or 40%. Divide by 100 to get 0.004.
- Using the wrong whole in “a as a percentage of b”. The whole goes underneath.
- Using 0.18 as the multiplier for an 18% decrease. That finds 18% of the amount, not the new price.
- Working backwards by subtracting the percentage from the final figure. The correct step is to divide the final figure by its multiplier.
- Treating 20% off and 20% on as cancelling. The second change works on a different amount.
- Comparing 0.5 with 0.45 by thinking 45 is bigger than 5. Pad both to two decimal places first.
- Ordering negatives as if the larger digit were larger.
A mixed example
A shop buys a chair for £60 and sells it for £81. Find the percentage profit, then find the sale price if the chair is later reduced by 20% from £81.
profit = 81 − 60 = £21
percentage profit = 21/60 × 100 = 35%
reduced price = 81 × 0.8 = £64.80
The profit is compared with the buying price, because that is the original value. The reduction is compared with the selling price, because that is the value being changed. Always ask which amount the percentage belongs to before you divide or multiply.
Exam skills
Write the multiplier you use, as this shows your method even if the arithmetic slips. Give money to two decimal places. Write “increase” or “decrease” after a percentage change. In a “show that” question, show every step.
Official syllabus
OCR GCSE (9-1) Mathematics (J560), Version 2.1 (August 2026), first assessment 2017, published by OCR. Sections 2.03a-2.03c and 2.04a-2.04b.
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