Revision Notes
OCR GCSE Physics A: Dissipation, efficiency and reducing energy loss (J249) – Revision Notes
Condensed revision notes on dissipation, power ratings, efficiency and insulation for OCR GCSE (9-1) Physics A (J249), with a self-test and answers.
- Subject
- Physics
- Level
- GCSE
- Topic
- Dissipation, efficiency and reducing energy loss
- Author
- Marlbridge Academic Team
- Updated
Aligned to OCR GCSE Physics (J249), Version 5.0 (July 2026), for first assessment in 2018. Official specification .
Syllabus page (what it covers and how it is assessed): OCR GCSE Physics.
Syllabus points this page covers
J249
- P7.2 Power and efficiency
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These notes condense statements P7.2a to P7.2g, Power and efficiency, from the OCR GCSE (9-1) Gateway Science Physics A (J249) specification, Version 5.0 (July 2026). They are for the final weeks of revision and are assessed in both tiers. For full explanations and worked examples, read the study guide. When you are ready to test yourself, use the practice questions, the course hub and the printable checklist. Earlier ideas on work and power from forces are in work done, stored energy and power from forces. The free 10-minute diagnostics show which parts to revise first.
Key ideas in one place
| Statement | Key point |
|---|---|
| P7.2a | Dissipation: energy spreads out and ends up stored in less useful ways, mostly the thermal store of the surroundings |
| P7.2b | Batteries start with a chemical store. The a.c. mains supplies energy electrically. Motors and heating devices waste some on the way in and inside |
| P7.2c | Power rating = energy transferred per second. A higher rating means stores change faster, not that the device is more efficient |
| P7.2d | efficiency = useful output energy transfer / input energy transfer |
| P7.2e | Increase efficiency by reducing the unwanted stores that fill |
| P7.2f | Lubrication cuts friction. Thermal insulation slows energy escaping |
| P7.2g | Thicker walls and lower thermal conductivity both slow the cooling of a building (qualitative) |
Dissipation (P7.2a)
- Total energy stays the same. It does not get used up.
- Dissipated energy is thinly spread through the surroundings, so it cannot be gathered and used again.
- Typical wording: “The kinetic store of the car decreases and the thermal stores of the brakes, tyres, road and air increase.”
- Examples: warm charger, braking, a bouncing ball that settles, a rung bell going quiet, a light bulb that gets hot.
Energy in domestic devices (P7.2b)
| Device type | Source | Useful store | Common wasted stores |
|---|---|---|---|
| Battery motor (toy, drill) | Chemical store of battery | Kinetic store of moving parts | Thermal in wires and windings, thermal from friction, sound |
| Mains motor (fan, washing machine) | a.c. mains | Kinetic store | Same three as above |
| Mains heater (kettle, toaster) | a.c. mains | Thermal store of water, bread or room | Thermal store of casing, nearby air and table, steam |
| Battery lamp or torch | Chemical store | Light | Thermal store of the lamp and its case |
Must-know distinction: “wasted” means stored somewhere you did not want, not destroyed.
Power and energy (P7.2c)
| Quantity | Symbol | Unit |
|---|---|---|
| Energy transferred | E | joule (J) or kilowatt-hour (kW h) |
| Power | P | watt (W) or kilowatt (kW) |
| Time | t | second (s) or hour (h) |
- E = P t. P = E / t. t = E / P.
- 1 W = 1 J per second. 1 kW = 1000 W.
- 1 kW h = 3 600 000 J (1000 W for 3600 s).
- Pair kW with hours, W with seconds.
- A 3 kW heater changes its stores three times as fast as a 1 kW heater. It is not three times as efficient.
- Joulemeters measure the energy transferred electrically. Divide by time to get power.
Method in steps: energy from a power rating
- Write the power in W (or kW).
- Write the time in s (or h) to match.
- Multiply: E = P t.
- Give the unit: J (or kW h).
Reminder: a 0.9 kW toaster on for 2 minutes is 900 W × 120 s = 108 000 J.
Efficiency (P7.2d)
efficiency = useful output energy transfer (J) / input energy transfer (J)
- Percentage = efficiency × 100.
- Efficiency is always above 0 and below 1 (below 100%) for real devices.
- Input = useful output + wasted energy.
- Rearrangements: useful output = efficiency × input. Input = useful output / efficiency.
- With steady power, you may use useful power output / total power input.
Method in steps
- Identify the useful output and the total input, in the same unit.
- If only the wasted energy is given, subtract it from the input to find the useful output.
- Divide useful by input.
- Write as a decimal or percentage as asked, with a sensible number of significant figures.
Worked reminder. A fan takes 640 J and wastes 160 J. Useful = 640 − 160 = 480 J. Efficiency = 480 / 640 = 0.75 = 75%.
Check that useful and wasted energies add up to the input.
Increasing efficiency and reducing waste (P7.2e, P7.2f)
| Method | How it helps |
|---|---|
| Lubrication (oil, grease) | Layer of liquid separates the surfaces, friction falls, less thermal energy produced |
| Streamlining | Less air resistance, less work against drag |
| Thicker or lower-resistance wires | Less thermal energy stored in the wires |
| Loft insulation | Trapped air is a poor conductor and cannot circulate, so conduction and convection are reduced |
| Cavity wall filling | Foam or trapped air slows conduction through the wall |
| Double glazing | Layer of trapped air or gas slows conduction and convection across the window |
| Draught-proofing | Stops warm air leaking out |
| Switching off standby | No energy transferred when the device is not needed |
Insulation slows energy transfer. It never stops it.
Cooling of a building (P7.2g)
- Thicker walls: lower rate of cooling.
- Lower thermal conductivity material: lower rate of cooling.
- Higher thermal conductivity or thinner walls: faster cooling.
- A bigger temperature difference between inside and outside makes cooling faster.
- Investigation: two copper cans, one insulated. Keep volume, starting temperature, lid and room the same, and record the temperature at regular times.
- Thermograms show hot areas of a house where energy leaves fastest.
Must-know distinctions
| Often confused | Difference |
|---|---|
| Power and energy | Power is how fast energy is transferred (W). Energy is the amount transferred (J or kW h) |
| Power rating and efficiency | The rating gives the rate of transfer. Efficiency gives the fraction that is useful |
| Wasted and destroyed | Wasted energy still exists, stored in the surroundings. Nothing is destroyed |
| Slowing and stopping | Insulation and lubrication reduce unwanted transfers, they do not remove them |
| Thickness and conductivity | Thickness changes the path length. Conductivity is a property of the material. Both change the cooling rate |
Worked reminder with a rating and efficiency together. A 500 W motor runs for 40 s and is 80% efficient. Input = 500 × 40 = 20 000 J. Useful = 0.80 × 20 000 = 16 000 J. Wasted = 4000 J.
Quick self-test
- What does it mean when we say energy is dissipated?
- Give two ways a motor wastes energy.
- A heater takes 120 J and gives 84 J of useful thermal energy. Calculate the efficiency as a percentage.
- Convert 0.5 kW h to joules.
- A device transfers 7200 J in 60 s. What is its power?
- A device is 30% efficient and gives 90 J of useful output. What is the input energy?
- Define 1 watt.
- Explain how oil in a hinge makes a device more efficient.
- Why is a layer of trapped air a good insulator?
- How does doubling the thickness of a wall affect the rate at which a building cools?
- A 3 kW heater and a 1 kW heater are on for the same time. A friend says the 3 kW heater is more efficient. Is this correct?
- A device takes 200 J and gives 50 J of useful output. What energy is wasted, and what is the efficiency?
Answers
- It spreads out to the surroundings and is stored in less useful ways, mainly the thermal store of the surroundings.
- Any two of: resistance heating the wires and windings, friction in bearings or gears, sound from vibrating parts.
- 84 / 120 = 0.70, which is 70%.
- 0.5 × 3 600 000 = 1 800 000 J.
- 7200 / 60 = 120 W.
- Input = 90 / 0.30 = 300 J.
- A rate of energy transfer of 1 joule per second.
- The oil separates the surfaces, which reduces friction. Less work is done against friction, so less energy is stored thermally and more goes into the useful motion.
- Air is a poor conductor, and in small pockets it cannot circulate, so convection is limited too.
- It slows the cooling, because energy has a longer path to travel through the wall.
- No. The rating gives the rate of energy transfer, not the fraction that is useful. Nothing is said about efficiency.
- Wasted = 200 − 50 = 150 J. Efficiency = 50 / 200 = 0.25, or 25%.
Where marks are usually lost
- Writing “energy is lost” or “used up” instead of “dissipated to the surroundings” or “stored thermally”.
- Saying a higher power rating means higher efficiency.
- Dividing the wasted energy by the input instead of dividing the useful energy by the input.
- Giving an efficiency over 100%, or leaving it as a fraction when a percentage was asked.
- Mixing kW with seconds or W with hours.
- Saying insulation “stops” or “traps” energy rather than slowing the transfer.
- Naming only “heat” for the wasted store, without saying where it ends up (wires, casing, air).
- Describing the cooling investigation without saying what is kept the same.
Official syllabus
OCR, GCSE (9-1) Gateway Science Physics A (J249), Version 5.0 (July 2026), for first assessment in 2018. Topic P7.2, Power and efficiency, statements P7.2a to P7.2g.
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