Revision Notes
OxfordAQA International GCSE Physics: Wave properties, sound and ultrasound (9203) – Revision Notes
Condensed revision notes on wave properties, sound and ultrasound for OxfordAQA International GCSE Physics, with formulas, methods and a self-test.
- Subject
- Physics
- Level
- IGCSE
- Topic
- Wave properties, sound and ultrasound
- Author
- Marlbridge Academic Team
- Updated
Aligned to OxfordAQA IGCSE Physics (9203), For exams May/June 2018 onwards. Official specification .
Syllabus page (what it covers and how it is assessed): OxfordAQA IGCSE Physics.
Syllabus points this page covers
9203
- 3.3.1 General properties of waves
- 3.3.3 Sound and ultrasound
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These notes condense sections 3.3.1 (general properties of waves) and 3.3.3 (sound and ultrasound) of the OxfordAQA International GCSE Physics (9203) specification, for exams May/June 2018 onwards. Parts 3.3.3 d to h are marked “P” in the specification, for full Physics. For full explanations read the study guide, then test yourself with the practice questions.
Other useful pages: the course hub, the printable checklist, the 10-minute diagnostics and the exam preparation page.
Definitions to learn word for word
| Term | Definition |
|---|---|
| Wave | A disturbance from a vibrating source that carries energy and information along its path while the material itself is not carried along |
| Transverse wave | Oscillations at right angles to the direction energy moves |
| Longitudinal wave | Vibrations along the line of energy travel |
| Compression | Region where the particles or coils are squashed together |
| Rarefaction | Region where the particles or coils are spread apart |
| Amplitude | Largest displacement of a point from its undisturbed position |
| Wavelength, λ | Span of one full wave, matching point to matching point |
| Frequency, f | Waves going past a point each second (hertz) |
| Period, T | Time taken by one complete wave (seconds) |
| Wavefront | Line joining points at the same stage of oscillation |
| Ultrasound | Sound at frequencies higher than humans can hear (above 20 000 Hz) |
Wave types and examples
| Type | Examples |
|---|---|
| Transverse | Electromagnetic waves, water waves, a rope shaken sideways |
| Longitudinal | Sound waves, a pushed and pulled spring |
- Mechanical waves can be transverse or longitudinal.
- Sound needs a medium and cannot cross a vacuum.
- A floating cork bobs up and down but does not travel with the ripples. Energy moves, matter does not.
Behaviour at a boundary
A wave meeting a boundary between two materials can be reflected, transmitted, absorbed, or any combination of these.
| Effect | What happens |
|---|---|
| Reflection | Wave bounces back into the first material |
| Transmission | Wave passes into the second material |
| Absorption | Wave energy is transferred to the material |
| Refraction | Wave speed changes, so wavelength changes and direction can change. Frequency stays the same |
| Diffraction | Waves spread through a narrow gap or round an edge |
Diffraction rule: it is appreciable only when the wavelength is comparable to the size of the gap or obstacle.
| Gap compared with wavelength | Result |
|---|---|
| Much wider | Very little spreading |
| About the same | Strong spreading |
| Much narrower | Weak waves emerge, spreading widely |
Applications named in the specification: reducing diffraction in optical instruments, ultrasound in medicine, radio wave reception.
Key equations
| Quantity | Rule | Unit of each symbol |
|---|---|---|
| Wave speed | v = fλ | speed m/s, frequency Hz, wavelength m |
| Period | T = 1/f | s, Hz |
| Distance | s = vt | m, m/s, s |
Rearrangements: f = v/λ, λ = v/f, t = s/v.
Method for v = fλ
- Write the known values with units.
- Convert units first (kHz to Hz, cm to m, ms to s).
- Rearrange for the unknown, then substitute.
- Give the answer with a unit and sensible significant figures.
Reminder. A wave of frequency 1200 Hz has a wavelength of 0.28 m. The speed is 1200 x 0.28 = 336 m/s, which is close to the speed of sound in air.
Reminder. A mains-frequency vibration of 50 Hz has a period T = 1/50 = 0.020 s. A period of 0.004 s means a frequency of 1/0.004 = 250 Hz.
Sound
- Sound is a longitudinal wave. The source vibrates, making compressions and rarefactions in the medium.
- Human hearing: about 20 Hz to 20 000 Hz.
- The structure of the ear is not required.
- Pitch depends on the frequency of the source. Loudness is related to the amplitude.
- Sound can be reflected (echoes) and diffracted.
| Change to the source | Oscilloscope trace |
|---|---|
| Louder | Taller wave, same number of cycles |
| Quieter | Smaller wave |
| Higher pitch | More cycles across the screen, shorter period |
| Lower pitch | Fewer cycles, longer period |
Method for a frequency from a trace
- Count how many divisions one complete cycle takes.
- Multiply by the time base to get T in seconds.
- Use f = 1/T.
Reminder. If 4 divisions at 0.5 ms per division make one cycle, T is 2.0 ms and f is 500 Hz.
Ultrasound (P)
- Frequency above 20 000 Hz, beyond the range of human hearing.
- Produced by electronic systems: an electrical signal makes a transducer vibrate at high frequency. The same device can detect returning pulses.
- At a boundary between two media it is partially reflected. Some carries on, some returns.
- The time for a reflection to reach the detector gives the distance to the boundary.
Method for echo and ultrasound distances
- Read the round-trip time from the question or trace.
- Convert to seconds (1 µs = 10^-6 s, 1 ms = 10^-3 s).
- Halve it, because the pulse travels there and back.
- Use s = vt.
- For the gap between two boundaries, find each distance and subtract, or halve the difference in echo times first.
Reminder. An echo from a wall returns after 0.50 s in air at 340 m/s. The wall is 340 x 0.25 = 85 m away.
Reminder. A pulse in tissue (1500 m/s) returns 50 µs after being sent. The one-way time is 25 µs, so s = 1500 x 25 x 10^-6 = 0.0375 m, about 3.8 cm.
Reminder. Wavelength of 2.0 MHz ultrasound in tissue at 1500 m/s: 1500 / 2 000 000 = 0.00075 m (0.75 mm). A wavelength this small means very little diffraction, so the beam stays narrow.
Medical uses of ultrasound (P)
| Use | Key points |
|---|---|
| Prenatal scanning | Pulses reflect from boundaries between tissues and fluid. Reflection times build an image. Non-ionising |
| Kidney stones | Focused, high-intensity ultrasound breaks the stone into small pieces that pass out in urine |
Exam wording to practise
- “Explain why an echo is heard”: sound is reflected by a hard surface and arrives later than the original sound because it has travelled further.
- “Explain what happens to a wave entering a different medium”: the speed changes, so the wavelength changes, the frequency stays the same, and the direction can change if the wave arrives at an angle.
- “Describe how ultrasound finds a boundary”: a pulse is sent, part of it reflects at the boundary, the detector records the time, and the distance is found from s = vt using half the time.
- “Compare two traces”: say which has the larger amplitude (louder) and which has the higher frequency (higher pitch), and give the reason for each.
Must-know distinctions
- Pitch vs loudness: pitch is frequency, loudness is amplitude.
- Frequency vs period: one is the reciprocal of the other.
- Reflection vs refraction: reflection sends the wave back, refraction changes its speed.
- Reflection vs absorption: reflected energy stays in the wave, absorbed energy goes into the material.
- Sound vs ultrasound: same type of wave, but ultrasound is above the hearing range.
- Wavelength vs amplitude: wavelength is along the direction of travel, amplitude is the size of the oscillation.
Quick self-test
- Say how the oscillation direction differs between transverse and longitudinal waves.
- Name one example of each.
- A wave has a frequency of 150 Hz and a wavelength of 2.2 m. Find its speed.
- What is the period of a 250 Hz sound?
- A note is played louder but at the same pitch. What changes on the oscilloscope trace?
- A sound takes 0.60 s to travel to a wall and back at 340 m/s. Find the distance to the wall.
- Why does a 0.25 m wavelength sound diffract strongly through a 0.30 m gap but a 0.5 mm ultrasound wave does not?
- Calculate the wavelength of a 40 kHz ultrasound wave in air at 340 m/s.
- State what happens to the frequency and wavelength when a wave slows down on entering shallow water.
- Give two reasons ultrasound suits prenatal scanning.
Answers
- Transverse: the oscillation is at right angles to the energy flow. Longitudinal: it is along the energy flow.
- Transverse: light or water waves. Longitudinal: sound.
- v = 150 x 2.2 = 330 m/s.
- T = 1/250 = 0.0040 s.
- The amplitude (height) increases. The period stays the same.
- One-way time 0.30 s, so s = 340 x 0.30 = 102 m, about 100 m.
- Diffraction is appreciable when the wavelength is comparable to the gap. 0.25 m is close to 0.30 m. 0.5 mm is far smaller than 0.30 m.
- λ = 340 / 40 000 = 0.0085 m (8.5 mm).
- Frequency is unchanged. Wavelength decreases (the speed decreases).
- It is non-ionising, and tissue boundaries partially reflect it, so reflections can build an image.
Where marks are usually lost
- Writing “the wave carries the particles along” instead of “transfers energy without transferring matter”.
- Using the full echo time in s = vt.
- Mixing up pitch and loudness, or writing “volume” and “pitch” without the matching physical quantity (amplitude, frequency).
- Not converting µs, ms, kHz or MHz.
- Saying diffraction depends only on the gap size, with no comparison to the wavelength.
- Saying refraction changes frequency.
- Describing a longitudinal wave without naming compressions and rarefactions.
- Giving an answer with no unit, or with far too many significant figures.
- Writing “sound bounces off” when asked to explain partial reflection at a boundary: say some is reflected and some transmitted.
Official syllabus
OxfordAQA International GCSE Physics (9203) specification, for exams May/June 2018 onwards, published by OxfordAQA. Sections 3.3.1 and 3.3.3.
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