Skip to content
Marlbridge

Practice Questions

Sequences and Proportion: Practice Questions

Original exam-style practice questions with full worked answers on arithmetic and geometric sequences, nth terms, direct and inverse proportion.

Subject
Mathematics
Level
O LEVELS
Topic
Algebra and graphs
Updated

Aligned to Cambridge O Level Mathematics (4024), 2025-2027. Official specification .

Syllabus page (what it covers and how it is assessed): Cambridge O Level Mathematics.

Syllabus points this page covers

4024

  • 2.7 Sequences
  • 2.8 Proportion

Found an error? Report a correction.

Need help with this topic? Request a free trial class for O Level Mathematics (4024).

These are original questions written for Marlbridge, for revision and practice on this content. They are not reproduced past-paper questions, and they do not replicate the exam’s exact structure, question count or mark tariffs — examination boards hold copyright in their own papers. Use these alongside the official past papers available free from your board.

Related: Sequences and Proportion revision notes, covering subtopics 2.7 Sequences and 2.8 Proportion for Cambridge O Level Mathematics (Syllabus D) 4024.


Section A

1. Find the nth term of the sequence 5, 9, 13, 17, … [2]

2. Find the next two terms of the sequence 3, 6, 12, 24, … and state its type. [2]

Section B

3. A sequence has nth term 3n² − 1.

(a) Find the first four terms. [2] (b) Determine whether 107 is a term of the sequence. [3]

4. Find the nth term of the quadratic sequence 4, 11, 22, 37, 56, … [4]

5. y is directly proportional to x. When x = 8, y = 20.

(a) Find the equation connecting y and x. [3] (b) Find y when x = 14. [1] (c) Find x when y = 42.5. [2]

6. p is inversely proportional to the square of q. When q = 3, p = 8.

(a) Find the equation connecting p and q. [3] (b) Find p when q = 6. [2] (c) Explain what happens to p when q is doubled. [2]

7. Find the nth term of the geometric sequence 6, 3, 1.5, 0.75, … [2]

8. y is directly proportional to x³. When x = 2, y = 40.

(a) Find the equation connecting y and x. [3] (b) Find y when x = 5. [1]

9. Find the nth term of the cubic sequence 1, 8, 27, 64, … and hence state its 7th term. [3]

10. y is directly proportional to the square root of x. When x = 16, y = 12.

(a) Find the equation connecting y and x. [3] (b) Find y when x = 25. [1]


Answers

1. The common difference is 4 [1]; nth term = 4n + 1 [1].

2. 48 and 96 [1]; it is a geometric sequence with common ratio 2 [1].

3. (a) 2, 11, 26, 47 [1] [1]. (b) 3n² − 1 = 107, so 3n² = 108 [1] and n² = 36, giving n = 6 [1]. Since n is a positive integer, 107 is the 6th term [1].

4. First differences: 7, 11, 15, 19 [1]. Second differences: 4, so the coefficient of n² is 4 ÷ 2 = 2 [1]. Subtracting 2n² (2, 8, 18, 32, 50) gives 2, 3, 4, 5, 6, whose nth term is n + 1 [1]. So the nth term is 2n² + n + 1 [1].

5. (a) y = kx [1]; 20 = 8k so k = 2.5 [1]; y = 2.5x [1]. (b) y = 2.5 × 14 = 35 [1]. (c) 42.5 = 2.5x [1]; x = 17 [1].

6. (a) p = k ÷ q² [1]; 8 = k ÷ 9 so k = 72 [1]; p = 72 ÷ q² [1]. (b) p = 72 ÷ 36 [1] = 2 [1]. (c) q² becomes four times larger [1], so p becomes one quarter of its original value [1].

7. First term a = 6, common ratio r = 0.5 [1]; nth term = a × rⁿ⁻¹ = 6 × 0.5ⁿ⁻¹ [1].

8. (a) y = kx³ [1]; 40 = k(2³) = 8k, so k = 5 [1]; y = 5x³ [1]. (b) y = 5 × 5³ = 5 × 125 = 625 [1].

9. These are the cube numbers, so the nth term is n³ [1]. Checking: 1³=1, 2³=8, 3³=27, 4³=64 ✓ [1]. The 7th term is 7³ = 343 [1].

10. (a) y = k√x [1]; 12 = k√16 = 4k, so k = 3 [1]; y = 3√x [1]. (b) y = 3 × √25 = 3 × 5 = 15 [1].


Where marks are usually lost

  • Writing the nth term as “4n” without the constant.
  • Forgetting to halve the second difference for the n² coefficient.
  • Not finding k before substituting in proportion questions.
  • Forgetting that inverse square proportion means quartering, not halving.
  • Confusing y ∝ x³ with y ∝ 3x — cube proportion means the equation contains x³, not a coefficient of 3.
  • Not recognising a cubic sequence (1, 8, 27, 64, …) as the cube numbers, and instead trying to force a quadratic nth-term method onto it.

Recognising a sequence type quickly

Sequence type Signal nth term form
Linear Constant first difference an + b
Quadratic Constant second difference an² + bn + c
Cubic Terms match n³, 2n³, etc. (check against cube numbers) an³ + …
Exponential (geometric) Constant ratio between terms a × rⁿ⁻¹

Always write out the differences (and, if those aren’t constant, the ratios) underneath the sequence before deciding which type you are dealing with — committing to the wrong method part-way through a question is one of the most time-costly mistakes in this topic. For the full method for each sequence type and further worked examples of non-linear proportion, see the Sequences and Proportion revision notes and the linked study guide.

Get free revision emails (optional)

Occasional emails with practice questions, worked explanations and links to free resources for the qualification and subjects you choose. No spam, and you can unsubscribe from any email. The free tools on this site never need an email.

Subjects (optional, up to 6)

Choose a qualification to see its subjects.

Related resources

Related articles

Studying this with a teacher

Working through Mathematics O LEVELS?

This page is free and stays free. If you would rather be taught it, Marlbridge runs Mathematics classes one-to-one and in small groups of up to 15, online in your own time zone. The first trial class is free. WhatsApp replies within an hour (8am–11pm Pakistan time, every day); email the same day.