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AP® Chemistry · Unit 6 · Topic 6.4

Heat Capacity and Calorimetry: Revision Notes (Chemistry 6.4)

One-page recap of q = mcΔT, specific, molar and object heat capacities, and calorimetry by conservation of energy, with the assumptions and mistakes that cost marks.

Short on time? This page is the recap. For explanations, diagrams and worked examples, use the full study guide.

Recap

  • q is the energy transferred as heat, in J or kJ. Positive q: the system absorbs heat (its energy rises). Negative q: it releases heat (its energy falls).
  • Specific heat capacity, c, is the energy to warm 1 g by 1 °C. Water: 4.18 J g⁻¹ °C⁻¹, unusually large.
  • The same energy given to equal masses of different substances gives different temperature changes: the smaller c, the larger ΔT.
  • Molar heat capacity is per mole; the heat capacity of an object is for the whole object.
  • First law of thermodynamics: energy is conserved. In an insulated calorimeter, energy released by one part is absorbed by the rest.
  • A system changes its energy by heating/cooling, phase changes (Topic 6.5) and reactions (Topic 6.6 on).
  • Dissolution calorimeter: mixture warms → dissolving is exothermic; mixture cools → dissolving is endothermic.

Key relationships

Relationship Units Use it to
q = mcΔT q in J, m in g, c in J g⁻¹ °C⁻¹, ΔT in °C (or K) heat for a mass of one substance
q = nC_mΔT, with C_m = c × M C_m in J mol⁻¹ °C⁻¹ heat for an amount in moles
q = CΔT, with C = mc C in J °C⁻¹ heat for a whole object or a calorimeter
ΔT = T(final) − T(initial) °C or K (same size) gives q its sign
q(lost) + q(gained) = 0 J any insulated calorimeter
q(process) = −q(solution) J energy of dissolving or a reaction in solution

Assumptions behind the numbers

  • No energy is exchanged with the air or bench (perfect insulation).
  • The calorimeter absorbs negligible energy, unless its heat capacity is given.
  • A dilute solution has c = 4.18 J g⁻¹ °C⁻¹; its mass is water plus solute.
  • The final reading is the thermal-equilibrium temperature, after stirring.

Mistakes to avoid

  1. Sign of ΔT. Always final minus initial.
  2. Sign of q(process). It is opposite to q(solution).
  3. “High c heats fast.” High c heats slowly.
  4. Wrong mass. Use the mass of the substance whose temperature changes (for a solution, water + solute).
  5. Per gram vs per mole. Match c with grams and C_m with moles.
  6. Too many significant figures. ΔT, found by subtraction, often has fewer than the readings.
  7. Halfway final temperature. Only when the two heat capacities (mc) are equal.

Quick self-check

  1. Energy to warm 10.0 g of water by 5.0 °C? (209 J)
  2. 100.0 g of water and 100.0 g of copper each absorb 2.00 kJ. Which warms more? (Copper: about 52 °C against 4.78 °C.)
  3. In a calorimeter the solution’s q is −850 J. What is q for the process? Exothermic or endothermic? (+850 J; endothermic: the solution cooled.)

Next: practice questions.

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