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AP® Physics 1: Algebra-Based · Unit 1 · Topic 1.2

Displacement, Velocity, and Acceleration: Revision Notes (Physics 1 1.2)

One-page recap of displacement, average and instantaneous velocity, and acceleration for the algebra-based course, with sign rules, assumptions and the mistakes that cost marks.

Short on time? This page is the recap. For explanations, graphs and worked examples, use the full study guide. This is the algebra-based course: no calculus is needed.

Recap

  • Treat the moving thing as a point object. Choose an origin and a positive direction, and write them down.
  • Position x says where the object is. Displacement Δx is the change in position. Distance travelled is the total path length and is never negative.
  • Average velocity uses only the start and end of an interval. Average speed uses the whole path.
  • An object accelerates whenever its velocity changes: faster, slower, or reversing direction.
  • Instantaneous velocity (or acceleration) is the average over a very short interval. On a graph, it is the slope of the tangent line.

Key relationships

Relationship Symbols and units Use it to
Δx = x − x₀ x, x₀ in m find displacement (signed)
v_avg = Δx / Δt m/s find average velocity over an interval
average speed = distance / Δt m/s, never negative describe the whole path, including turn-arounds
a_avg = Δv_x / Δt = (v_x − v_x0) / Δt m/s² find average acceleration
slope of x–t graph m/s velocity (tangent slope = instantaneous)
slope of v_x–t graph m/s² acceleration
area under v_x–t graph m displacement (area below the axis is negative)

Assumptions behind the numbers

  • The object is a point: rotation and size are ignored.
  • Motion is along one straight line, so a sign fully describes direction.
  • The reference frame is at rest relative to the ground (inertial) unless stated.
  • Near Earth’s surface, free-fall acceleration has size g = 9.8 m/s² downward (air resistance ignored). The course also accepts 10 m/s² where stated.

Mistakes to avoid

  1. No axis stated. A sign means nothing without one.
  2. Negative a = slowing down. Wrong. Compare the signs of v_x and a_x.
  3. Dropping signs in Δv_x. A ball that rebounds changes velocity by more than the change in speed.
  4. Mean of two velocities as average velocity. Use total Δx ÷ total Δt.
  5. Secant slope used as the instantaneous value. Use a tangent, or shrink the interval.
  6. v = 0 so a = 0. Not at the top of a throw.
  7. Distance and displacement swapped. Check whether the object turned around.

Quick self-check

  1. With +x to the right, a cart goes from x = +2.0 m to x = −4.0 m in 3.0 s. What is its average velocity? (−2.0 m/s)
  2. v_x = −5.0 m/s and a_x = −2.0 m/s². Speeding up or slowing down? (Speeding up: same signs.)
  3. A ball hits a wall at +3.0 m/s and rebounds at −2.0 m/s after 0.10 s of contact. What is its average acceleration? (−50 m/s²)

Next: practice questions.

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