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Flashcards · 9701 · AS Topic 4

States of matter (AS Level) flashcards

11 cards on AS Topic 4, subtopics 4.1 to 4.2. Pick a subtopic or study them all.

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4.1 The gaseous state: ideal and real gases and pV = nRT

The ideal gas equation, with units
pV = nRT p in Pa, V in m³, n in mol, T in K, R = 8.31 J K⁻¹ mol⁻¹. Convert: kPa × 1000, cm³ ÷ 10⁶, dm³ ÷ 1000, °C + 273.
Assumptions of the kinetic theory for an ideal gas
Particles have negligible volume; there are no intermolecular forces; collisions are perfectly elastic; particles are in constant random motion.
When do real gases deviate most from ideal behaviour, and why?
At high pressure (particles close together, so their own volume is no longer negligible) and low temperature (particles move slowly, so intermolecular attractions become significant).
Conditions under which a gas behaves most ideally
Low pressure and high temperature. Small non-polar molecules (He, H₂) behave more ideally than molecules with stronger intermolecular forces (NH₃, H₂O).
How do you find Mr from gas data?
M = mRT ÷ (pV), using SI units. e.g. 4.40 g in 2.24 × 10⁻³ m³ at 101 000 Pa and 273 K: n ≈ 0.0997 mol, so Mr ≈ 44.

4.2 Bonding and structure

Giant ionic structure: properties
High melting point (strong electrostatic attraction between ions). Conducts only when molten or aqueous (ions free to move). Often soluble in water.
Simple molecular structure: properties
Low melting point: only weak intermolecular forces are overcome. Does not conduct. Solubility depends on polarity (like dissolves like).
Giant covalent structure: properties
Very high melting point: many strong covalent bonds must be broken. Does not conduct (except graphite). Insoluble.
Giant metallic structure: properties
High melting point (attraction of ions to the electron sea). Conducts as a solid and when molten. Insoluble.
Diamond and graphite compared
Diamond: 4 bonds per C, tetrahedral 3D network, very hard, does not conduct. Graphite: 3 bonds per C, hexagonal layers held by weak forces (soft, layers slide), one delocalised electron per atom so it conducts.
Why does iodine melt at 114 °C but diamond needs over 3500 °C?
Iodine is simple molecular: melting overcomes only weak intermolecular forces. Diamond is giant covalent: many strong covalent bonds must break.