Revision Notes
Edexcel A Level Chemistry: Structure, Bonding and Introductory Organic Chemistry — Revision Notes
Condensed recall notes on bonding, shapes, intermolecular forces, organic nomenclature and mechanisms for Pearson Edexcel International A-Level Chemistry (YCH11).
- Subject
- Chemistry
- Level
- AS LEVEL
- Topic
- Unit 1 – Structure, Bonding and Introduction to Organic Chemistry
- Author
- Marlbridge Academic Team
- Updated
- Reviewed by
- Nouman Ahmed (what this means)
Aligned to Pearson Edexcel A Level Chemistry (YCH11), Issue 1, September 2017. Official specification .
Syllabus page (what it covers and how it is assessed): Pearson Edexcel A Level Chemistry.
Syllabus points this page covers
YCH11 (AS Level)
- 1 Unit 1 – Structure, Bonding and Introduction to Organic Chemistry (whole topic)
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Condensed for the final weeks. For the full explanation, use the Structure, Bonding and Organic Chemistry study guide.
Bonding
| Bond | Held by |
|---|---|
| Ionic | Electrostatic attraction between oppositely charged ions |
| Covalent | Shared pair attracted to both nuclei |
| Dative covalent | Both electrons from the same atom |
| Metallic | Positive ions and delocalised electrons |
Every definition needs electrostatic attraction.
Polarisation: a small, highly charged cation distorts a large anion’s electron cloud, giving an ionic compound covalent character. Polarising power rises with higher charge and smaller radius; polarisability rises with larger anion radius. This is why AlCl₃ behaves covalently while NaCl does not.
Comparing theoretical and experimental lattice energies measures this: a large discrepancy indicates significant covalent character. (This comparison itself is Unit 4, topic 12 content – Unit 1 goes no further than recognising covalent character from polarisation.)
Shapes — VSEPR
Electron pairs repel and get as far apart as possible; lone pairs repel more strongly than bonding pairs, reducing bond angles by about 2.5° each.
| Bond pairs | Lone pairs | Shape | Angle |
|---|---|---|---|
| 2 | 0 | Linear | 180° |
| 3 | 0 | Trigonal planar | 120° |
| 4 | 0 | Tetrahedral | 109.5° |
| 3 | 1 | Trigonal pyramidal | 107° |
| 2 | 2 | Bent | 104.5° |
| 5 | 0 | Trigonal bipyramidal | 120° / 90° |
| 6 | 0 | Octahedral | 90° |
CH₄ → NH₃ → H₂O (109.5 → 107 → 104.5) is examined constantly, and the explanation — one then two lone pairs — is what scores.
Polarity and intermolecular forces
A molecule is polar only if the bond dipoles do not cancel. CO₂ has polar bonds but is linear and symmetrical, so it is non-polar; H₂O is bent, so it is polar. Symmetry decides it.
| Force | Present in | Strength |
|---|---|---|
| London (induced dipole) | All molecules | Weakest, grows with electron number |
| Permanent dipole–dipole | Polar molecules | Intermediate |
| Hydrogen bonding | H bonded to N, O or F plus an acceptor lone pair | Strongest |
Hydrogen bonding needs both conditions. HCl does not hydrogen bond.
Ice is less dense than water because each molecule forms four hydrogen bonds in a tetrahedral arrangement, creating an open lattice with holes; melting partly collapses it, so the liquid is denser.
Simple molecular substances melt at low temperatures because the weak intermolecular forces break, not the covalent bonds. That is the most penalised sentence in the topic.
Organic nomenclature and isomerism
Root by longest carbon chain, suffix by functional group, prefix by substituents, numbered to give the lowest locants.
- Structural isomerism — chain, position, functional group.
- Stereoisomerism — same structural formula, different spatial arrangement:
- E/Z (geometric) — requires a C=C double bond (restricted rotation) and two different groups on each carbon. Both conditions are needed.
- Optical (Unit 4, topic 15 content) — requires a chiral centre: a carbon with four different groups. The two enantiomers are non-superimposable mirror images and rotate plane-polarised light in opposite directions.
A racemic mixture rotates light not at all, because equal amounts of the two enantiomers cancel. This matters mechanistically: a reaction proceeding through a planar carbocation or planar intermediate produces a racemic mixture, because attack is equally likely from either face. That is direct evidence for the mechanism.
Mechanisms
(The halogenoalkane hydrolysis content below – the mechanism table’s Nucleophilic substitution/Elimination rows, the aqueous-vs-ethanolic KOH rule, and the C-I to C-F rate trend – is Unit 2, topic 10 content, examined after Unit 1.)
Curly arrows show a pair of electrons moving, starting from a bond or lone pair — never from an atom or a positive charge.
| Mechanism | Substrate |
|---|---|
| Free radical substitution | Alkanes + halogen, UV |
| Electrophilic addition | Alkenes |
| Nucleophilic substitution | Halogenoalkanes |
| Elimination | Halogenoalkanes with ethanolic KOH |
Aqueous KOH gives substitution to an alcohol; ethanolic KOH gives elimination to an alkene. The solvent decides the product.
Rate of hydrolysis: C–I > C–Br > C–Cl > C–F. This follows bond enthalpy, not electronegativity — C–F is the most polar bond but by far the strongest, so fluoroalkanes are least reactive. That is the standard trap.
Markovnikov addition should be explained through carbocation stability (tertiary > secondary > primary), not stated as a rule about hydrogen.
Exam traps
- Saying covalent bonds break on melting a molecular solid.
- Explaining C–X reactivity by electronegativity.
- Giving only one condition for E/Z isomerism.
- Forgetting that a racemic mixture is optically inactive.
- Arrows starting at an atom or a charge.
- Saying a molecule is polar because its bonds are polar, ignoring symmetry.
Self-test
- Give the two conditions for E/Z isomerism.
- What is a chiral centre, and why is a racemic mixture optically inactive?
- Why does a planar intermediate produce a racemic mixture?
- Which halogenoalkane hydrolyses fastest and why?
- Why is ice less dense than water?
Answers: 1. A C=C double bond preventing rotation, and two different groups attached to each of the double-bonded carbons. 2. A carbon atom bonded to four different groups; a racemic mixture contains equal amounts of the two enantiomers, whose equal and opposite rotations cancel. 3. The intermediate is flat, so the nucleophile can attack from either face with equal probability, producing equal amounts of both enantiomers. 4. The iodoalkane — the C–I bond has the lowest bond enthalpy and so breaks most readily; polarity is not the deciding factor. 5. Each water molecule forms four hydrogen bonds in a tetrahedral arrangement, producing an open lattice containing holes, which partly collapses on melting.
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