Revision Notes
AQA A-Level Chemistry: Oxidation, reduction and redox equations (7405) – Revision Notes
Condensed AQA A-Level Chemistry 7405 redox notes: oxidation state rules, half-equation method, combining equations and a quick self-test with answers.
- Subject
- Chemistry
- Level
- AS LEVEL
- Topic
- Oxidation, reduction and redox equations
- Author
- Marlbridge Academic Team
- Updated
Aligned to AQA A Level Chemistry (7405), For teaching from September 2015. Official specification .
Syllabus page (what it covers and how it is assessed): AQA A Level Chemistry.
Syllabus points this page covers
7405 (AS Level)
- 7 Oxidation, reduction and redox equations (whole topic)
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These revision notes cover section 3.1.7, Oxidation, reduction and redox equations, of the AQA AS and A-level Chemistry specification (7404/7405), version 1.2, July 2026, for AS and A-level exams from June 2016 onwards. The whole section is AS content and is also part of the full A-level; none of it is marked “A-level only”. The specification places it in Paper 1 at both AS and A-level, and A-level Paper 3 can test any content.
For full explanations and step-by-step worked examples, read the study guide. When you are ready to test yourself under exam conditions, use the practice questions. The AQA A-Level Chemistry hub and printable checklist list every other section.
3.1.7 Definitions
| Term | Definition (specification wording) |
|---|---|
| Oxidation | the process of electron loss |
| Reduction | the process of electron gain |
| Oxidising agent | an electron acceptor (it is reduced) |
| Reducing agent | an electron donor (it is oxidised) |
| Redox reaction | electrons are transferred from the reducing agent to the oxidising agent |
In terms of oxidation state:
- oxidation state goes up → the element is oxidised
- oxidation state goes down → the element is reduced
Oxidation state rules
| Species or element | Oxidation state |
|---|---|
| Uncombined element | 0 |
| Neutral compound (sum) | 0 |
| Ion (sum) | charge on the ion |
| Group 1 / Group 2 / Al in compounds | +1 / +2 / +3 |
| F in compounds | −1 |
| H | +1 (−1 in metal hydrides, e.g. NaH, CaH₂) |
| O | −2 (−1 in peroxides, e.g. H₂O₂; +2 in OF₂) |
| Cl | −1 (positive when bonded to O or F) |
Roman numerals in names = oxidation state: sulfate(VI), manganate(VII), dichromate(VI), chlorate(I), iron(II), iron(III).
Writing convention: oxidation state +2; ionic charge 2+.
Oxidation states worth recognising on sight
These all follow from the rules above. Knowing them saves time, but in the exam you should still be able to show the working.
| Element | Species and oxidation state |
|---|---|
| Manganese | MnO₄⁻ +7, MnO₂ +4, Mn²⁺ +2 |
| Chromium | Cr₂O₇²⁻ +6, CrO₄²⁻ +6, Cr³⁺ +3 |
| Sulfur | SO₄²⁻ and H₂SO₄ +6, SO₂ +4, S₈ 0, H₂S −2 |
| Nitrogen | NO₃⁻ +5, NO₂ +4, NO +2, NH₃ and NH₄⁺ −3 |
| Chlorine | ClO₃⁻ +5, ClO⁻ +1, Cl₂ 0, Cl⁻ −1 |
| Iodine | IO₃⁻ +5, I₂ 0, I⁻ −1 |
| Oxygen | H₂O −2, H₂O₂ −1, O₂ 0 |
| Iron | Fe₂O₃ and Fe³⁺ +3, Fe²⁺ +2 |
Method in steps
Working out an oxidation state
- Write x for the unknown element.
- Fill in the known values from the rules.
- Set the sum equal to 0 (compound) or the ion’s charge.
- Solve. A fraction (such as +2.5 for S in S₄O₆²⁻) is an average and is acceptable.
Small reminder: Cl in ClO₃⁻ → x + 3(−2) = −1, so x = +5.
Deciding what is oxidised and reduced in an equation
- Write the oxidation state of every element on both sides.
- Cross out any element whose oxidation state does not change (spectator ions such as Na⁺, K⁺, SO₄²⁻ often fall here).
- Up = oxidised (that species is the reducing agent). Down = reduced (that species is the oxidising agent).
- Name the species, not just the element, when asked for an agent.
Small reminder: Zn + 2Fe³⁺ → Zn²⁺ + 2Fe²⁺. Zn goes 0 → +2 (oxidised, reducing agent). Fe goes +3 → +2 (reduced, so Fe³⁺ is the oxidising agent).
Writing a half-equation in acid
- Balance the element that changes oxidation state.
- Balance O with H₂O.
- Balance H with H⁺.
- Balance charge with e⁻.
- Check electrons = change in oxidation state × atoms changing.
Small reminder:
NO₃⁻ + 2H⁺ + e⁻ → NO₂ + H₂O
N goes from +5 in NO₃⁻ to +4 in NO₂: one electron gained. Reduction.
Combining two half-equations
- Scale so electrons lost = electrons gained.
- Add.
- Cancel e⁻, then any H⁺ and H₂O on both sides.
- Check atoms and total charge.
Small reminder, copper metal with silver ions:
Cu → Cu²⁺ + 2e⁻
Ag⁺ + e⁻ → Ag (× 2)
2Ag⁺ + Cu → 2Ag + Cu²⁺
Final checks on any redox equation
- Atoms of every element balance.
- Total charge on the left equals total charge on the right.
- Electrons appear only in half-equations, never in the overall equation.
- Electrons lost in the oxidation equal electrons gained in the reduction.
- H⁺ and H₂O appear on one side only after cancelling.
- Add state symbols only if the question asks for them.
Command words for this section
- State / Give: the answer alone, such as “+6” or “Fe³⁺”. No working needed, but a sign is.
- Deduce: use the rules or the equation to reach the answer; show the step if it is not obvious.
- Show that: every step must be written, because the answer is given.
- Write a half-equation: species, H⁺, H₂O and e⁻ all balanced.
- Explain: link the change to electrons, for example “Fe²⁺ loses an electron, so its oxidation state rises from +2 to +3”.
- Identify: name or give the formula of a single species.
Must-know distinctions
| Do not confuse | With |
|---|---|
| Oxidising agent (reduced) | Species oxidised (the reducing agent) |
| Oxidation state (+3) | Ionic charge (3+) |
| Half-equation (contains e⁻) | Overall equation (no e⁻) |
| Electrons on the left = reduction | Electrons on the right = oxidation |
| Spectator ion (no change) | Reacting ion (oxidation state changes) |
| H in H₂O, HCl (+1) | H in metal hydrides (−1) |
| O in oxides (−2) | O in peroxides (−1) |
Quick self-test
Cover the answers, then try each one.
- State the oxidation state of manganese in K₂MnO₄.
- State the oxidation state of sulfur in H₂S.
- State the oxidation state of chlorine in Cl₂O₇.
- State the oxidation state of oxygen in Na₂O₂, and give a reason.
- State the oxidation state of nitrogen in NH₂OH.
- Iron(II) chloride is converted into iron(III) chloride. Has iron been oxidised or reduced? Explain in terms of electrons.
- Write a half-equation for aluminium forming aluminium ions.
- Aluminium reacts with copper(II) ions: 2Al + 3Cu²⁺ → 2Al³⁺ + 3Cu. Identify the reducing agent.
- Write a half-equation for chlorate(I) ions, ClO⁻, being reduced to chloride ions in acidic solution.
- Write a half-equation for hydrogen peroxide being oxidised to oxygen.
- Hydrogen peroxide is reduced to water in acid: H₂O₂ + 2H⁺ + 2e⁻ → 2H₂O. Combine this with the oxidation of Fe²⁺ to Fe³⁺ to give the overall equation.
- In the reaction 2Fe³⁺ + 2I⁻ → 2Fe²⁺ + I₂, identify the oxidising agent and write the half-equation for the oxidation.
Answers
- +6. 2(+1) + x + 4(−2) = 0, so x = +6.
- −2. 2(+1) + x = 0.
- +7. 2x + 7(−2) = 0, so 2x = +14.
- −1. Na₂O₂ is a peroxide; Na is +1, so 2(+1) + 2x = 0 gives x = −1.
- −1. x + 2(+1) + (−2) + (+1) = 0, so x = −1.
- Oxidised. Iron goes from +2 to +3, so each Fe²⁺ ion loses one electron.
- Al → Al³⁺ + 3e⁻
- Al (aluminium atoms donate electrons; Al goes from 0 to +3).
- ClO⁻ + 2H⁺ + 2e⁻ → Cl⁻ + H₂O (Cl goes from +1 to −1, two electrons gained).
- H₂O₂ → O₂ + 2H⁺ + 2e⁻ (O goes from −1 to 0; two O atoms, two electrons lost).
- Multiply Fe²⁺ → Fe³⁺ + e⁻ by 2, then add: H₂O₂ + 2Fe²⁺ + 2H⁺ → 2Fe³⁺ + 2H₂O. Charge: left +6, right +6.
- Fe³⁺ is the oxidising agent (Fe goes from +3 to +2). Oxidation: 2I⁻ → I₂ + 2e⁻.
Where marks are usually lost
- Describing the oxidising agent as “the substance oxidised”. It accepts electrons, so it is reduced.
- Defining oxidation only as “gain of oxygen”. The specification definition is electron loss.
- Giving an oxidation state without a sign (writing 6 instead of +6), or writing it as 6+.
- Missing a named exception, such as treating H in a metal hydride as +1.
- Giving the total for all atoms of the element instead of the value per atom, e.g. giving +14 for Cl in Cl₂O₇ instead of +7.
- In half-equations, balancing charge with extra H⁺ instead of electrons.
- Leaving electrons, or H⁺ and H₂O on both sides, in an overall equation.
- Choosing multipliers that make the electron numbers unequal, so the overall equation has the wrong ratio.
- Naming the element rather than the species, e.g. “chlorine is reduced” when the question asks which ion is the oxidising agent.
Related pages
- Study guide for this section
- Practice questions for this section
- Bonding: ions and ionic charges
- Atomic structure revision notes
- Mole revision notes, for redox titration calculations
- Free diagnostics
Official syllabus
AQA AS and A-level Chemistry specification (7404/7405), version 1.2, July 2026, for AS and A-level exams June 2016 onwards, section 3.1.7 Oxidation, reduction and redox equations. Published by AQA.
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