Revision Notes
OxfordAQA A-Level Chemistry: Organic synthesis (9620) – Revision Notes
Revision notes for OxfordAQA 9620 organic synthesis: greener design, atom economy, the full reaction map and a method for routes of up to four steps.
- Subject
- Chemistry
- Level
- A LEVEL
- Topic
- Organic synthesis
- Author
- Marlbridge Academic Team
- Updated
Aligned to OxfordAQA A Level Chemistry (9620), Version 5.3 (first teaching 2019, first AS and A-level exams 2020). Official specification .
Syllabus page (what it covers and how it is assessed): OxfordAQA A Level Chemistry.
Syllabus points this page covers
9620 (A Level)
- 32 Organic synthesis (whole topic)
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Need help with this topic? Request a free trial class for A Level Chemistry (9620).
Use these condensed notes in the final run-up to your exams. The organic synthesis study guide has the full explanations and longer examples.
Their scope is section 3.3.14 Organic synthesis in the OxfordAQA International AS and A-level Chemistry (9620) specification, Version 5.3, for International AS and A-level exams from May/June 2020 onwards. Everything here is International A-level only, part of the A2 organic chemistry examined in Unit 4 (Organic 2 and Physical 2); Unit 5 (Practical and synoptic) covers all content. The atom economy formula is from 3.1.2.5.
Check yourself afterwards with the practice questions. Also see the 9620 chemistry course hub, the printable 9620 checklist and the free 10-minute diagnostics.
What 3.3.14 asks of you
| Outcome | In short |
|---|---|
| 1 | Explain the aim of processes with no solvent and non-hazardous starting materials |
| 2 | Explain the aim of fewer steps and high percentage atom economy |
| 3 | Plan a route of four steps or fewer, built only from 9620 reactions |
No required practical is listed under 3.3.14. Required practical 4 (distil a product, 3.3.5.2) and Required practical 10 (make an organic solid and check how pure it is, 3.3.9.2) are the practical skills a synthesis draws on.
Key formulas
| Quantity | Formula |
|---|---|
| % atom economy | Mr of the wanted product × 100, divided by the total Mr of all reactants |
| % yield | actual amount of product ÷ theoretical maximum × 100 |
| Overall yield | step yields as decimals multiplied together, × 100 |
Outcome 1 in bullet points
No solvent
- No energy or raw materials spent making and transporting it.
- No separation step (often distillation) to remove it from the product.
- No solvent waste and no recovery plant.
- No flammable or toxic vapour to leak.
Non-hazardous starting materials
- Less spent on sealed storage, transport rules, protective kit, training and emergency plans.
- Lower risk to workers, neighbours and the environment if something goes wrong.
- 9620 hazards to quote: KCN (very toxic; acid releases HCN gas), epoxyethane (extremely flammable, explosive with air, toxic, carcinogenic), chlorine and (chloromethyl)benzene (toxic, irritant).
- Aspirin: ethanoic anhydride is chosen over ethanoyl chloride because it is cheaper, less corrosive, less violent with water and releases no HCl.
Outcome 2 in bullet points
- Every step loses some product, so the overall yield drops with each step added.
- Every step needs its own reagents, energy, separation, time and waste disposal.
- High atom economy: most reactant atoms end up in the product, so less by-product and less waste.
- Addition = 100% atom economy. Substitution and elimination are usually below 100% (an exception: an amine plus a halogenoalkane giving a quaternary ammonium salt as the only product).
- A useful by-product (one that can be sold) softens a low atom economy.
The 9620 reaction map
| Start | Reagent and conditions | Product | Section |
|---|---|---|---|
| Alkene | HBr | Bromoalkane; the major isomer comes from the more stable carbocation | 3.3.4.2 |
| Alkene | Br₂ | Dibromoalkane | 3.3.4.2 |
| Alkene | Concentrated H₂SO₄ | Alkyl hydrogensulfate | 3.3.4.2 |
| Alkene | Addition polymerisation | Poly(alkene) | 3.3.4.3 |
| Ethene | O₂, silver catalyst (partial oxidation) | Epoxyethane | 3.3.4.4 |
| Epoxyethane | Water; or an alcohol | Ethane-1,2-diol; or an ether-alcohol | 3.3.4.4 |
| Halogenoalkane | NaOH(aq), warm | Alcohol | 3.3.3.1 |
| Halogenoalkane | KCN in aqueous ethanol, reflux | Nitrile (+1 C) | 3.3.3.1 |
| Halogenoalkane | Excess NH₃ in ethanol, heat, sealed | Primary amine | 3.3.3.1, 3.3.11.1 |
| Halogenoalkane | KOH in ethanol, hot | Alkene | 3.3.3.2 |
| Halogenoalkane | Amine | 2° or 3° amine, quaternary ammonium salt | 3.3.11.3 |
| Alcohol | Concentrated H₂SO₄ or H₃PO₄, heat | Alkene | 3.3.5.2 |
| Primary alcohol | Acidified K₂Cr₂O₇, distil as formed / excess, reflux | Aldehyde / carboxylic acid | 3.3.5.1 |
| Secondary alcohol | Acidified K₂Cr₂O₇, reflux | Ketone | 3.3.5.1 |
| Aldehyde or ketone | NaBH₄(aq) | Primary or secondary alcohol | 3.3.8.1 |
| Aldehyde or ketone | KCN, then dilute acid | Hydroxynitrile (+1 C) | 3.3.8.1 |
| Carboxylic acid + alcohol | Acid catalyst, heat | Ester | 3.3.9.1 |
| Ester | Acid or alkali, heat | Acid (or its salt) + alcohol | 3.3.9.1 |
| Vegetable oil | Methanol, catalyst | Biodiesel (methyl esters) + glycerol | 3.3.9.1 |
| Acyl chloride or anhydride | Water / alcohol / NH₃ / primary amine | Acid / ester / amide / N-substituted amide | 3.3.9.2 |
| Benzene | Conc. HNO₃ + conc. H₂SO₄ | Nitrobenzene | 3.3.10.2 |
| Benzene | Fuming or conc. H₂SO₄ | Benzenesulfonic acid | 3.3.10.2 |
| Benzene | Acyl chloride, AlCl₃ | Phenyl ketone | 3.3.10.2 |
| Benzene | Chloroalkane, AlCl₃ | Alkylbenzene | 3.3.10.2 |
| Benzene | Cl₂, UV light | C₆H₆Cl₆ (ring addition) | 3.3.10.2 |
| Methylbenzene | Cl₂, UV light | (Chloromethyl)benzene (side chain) | 3.3.10.2 |
| Nitrile | Reduction (H₂/Ni or LiAlH₄) | Primary amine | 3.3.11.1 |
| Nitro compound | Reduction (Sn + conc. HCl, then NaOH) | Aromatic amine | 3.3.11.1 |
| Diacid + diol or diamine | Condensation | Polyester or polyamide | 3.3.12.1 |
Reagents in brackets for the two reductions, and the silver catalyst, are standard choices; 9620 itself leaves them unnamed.
Must-know distinctions
| Pair | The difference |
|---|---|
| Atom economy vs yield | Atom economy is calculated from the equation; yield from the mass you collect |
| Cl₂ + UV on benzene vs on methylbenzene | Benzene: addition to the ring. Methylbenzene: substitution on the side chain |
| Ring Cl vs side-chain Cl | Ring Cl is not replaced by nucleophiles; side-chain Cl reacts like a halogenoalkane |
| NaOH(aq) vs KOH in ethanol | Aqueous favours substitution (alcohol); ethanolic favours elimination (alkene) |
| Excess NH₃ vs excess halogenoalkane | Excess NH₃ gives mainly the primary amine; otherwise further substitution follows |
| Nitrile reduction vs NH₃ route to an amine | Nitrile route adds a carbon and gives one amine only |
Carbon–carbon bond forming steps
Outside polymerisation, four reactions in 9620 join carbon to carbon:
- Halogenoalkane + KCN (nitrile).
- Aldehyde or ketone + KCN, then dilute acid (hydroxynitrile).
- Friedel–Crafts acylation (acyl chloride + AlCl₃).
- Friedel–Crafts alkylation (chloroalkane + AlCl₃).
Not in the 9620 content
- Steam hydration of an alkene.
- Turning an alcohol directly into a halogenoalkane.
- Making an acyl chloride or an acid anhydride.
- Electrophilic substitution beyond a single substituent (the specification limits this to monosubstitution).
A route that needs one of these is not acceptable as a 9620 synthesis.
Method in steps
1 Draw start and target; mark groups; count carbons.
2 More carbons in the target? Choose a C–C step from the list.
3 Work back from the target one reaction at a time.
4 Check the position of each group (major product, ring vs side chain).
5 Each step: reagent + conditions + product name or structure.
6 Count steps (no more than four) and check every reaction is in 9620.
Worked reminders
Atom economy of a cyanide step. Relative atomic masses: C = 12.0, H = 1.0, K = 39.1, N = 14.0, Cl = 35.5.
C₆H₅CH₂Cl + KCN → C₆H₅CH₂CN + KCl
Sum of reactants = 126.5 + 65.1 = 191.6
% atom economy = 117.0 ÷ 191.6 × 100 = 61.1%
Spot the broken route. A student plans: benzene + Cl₂ in UV light → chlorobenzene → warm NaOH(aq) → an alcohol. Both steps fail. UV light makes chlorine add to benzene, giving C₆H₆Cl₆, not chlorobenzene. And even if chlorobenzene were available, the ring C–Cl bond is strengthened by overlap of a chlorine lone pair with the delocalised ring, so hydroxide does not substitute it. A workable 9620 alternative to put an OH group near a ring is methylbenzene + Cl₂ (UV), then NaOH(aq), which gives phenylmethanol, C₆H₅CH₂OH.
Related topics
Revise the single reactions in halogenoalkanes, alkenes, alcohols and aromatic chemistry. Confirm a product with organic analysis.
Quick self-test
- State two benefits of a process that uses no solvent.
- Give one reason for avoiding hazardous starting materials, with a 9620 example of such a material.
- Calculate the % atom economy for making ethylamine: CH₃CH₂Cl + 2NH₃ → CH₃CH₂NH₂ + NH₄Cl. (Relative atomic masses: C = 12.0, H = 1.0, N = 14.0, Cl = 35.5)
- A route has three steps with yields of 92%, 88% and 61%. Calculate the overall yield.
- Route P has two steps (80% and 55%). Route Q has one step (50%). Which gives more product?
- Name the four reactions in 9620, other than polymerisation, that form a new C–C bond.
- Give the reagent and condition to convert methylbenzene into (chloromethyl)benzene.
- Give the reagent and catalyst to make ethylbenzene from benzene.
- State the reagent that converts epoxyethane into ethane-1,2-diol.
- Give the reagent that converts a ketone into a secondary alcohol.
Answers
- Any two: no energy to make, transport or remove it; no solvent waste; no flammable or toxic vapour.
- Hazardous materials need costly controls and put people at risk; for example KCN, which is very toxic.
- Sum = 64.5 + 2(17.0) = 98.5; % atom economy = 45.0 ÷ 98.5 × 100 = 45.7%.
- 0.92 × 0.88 × 0.61 = 0.4939, so 49.4%.
- Route P: 0.80 × 0.55 = 0.44, so 44%. Route Q (50%) gives more, and with fewer steps.
- Halogenoalkane + KCN; aldehyde or ketone + KCN then dilute acid; Friedel–Crafts acylation; Friedel–Crafts alkylation.
- Chlorine, in UV light.
- Chloroethane, with an AlCl₃ catalyst.
- Water.
- NaBH₄ in aqueous solution.
Where marks are usually lost
- Using a reaction that is not in 9620, such as steam hydration or alcohol to halogenoalkane.
- Writing AlCl₃ when the side chain of methylbenzene is to be chlorinated; UV light is needed.
- Planning substitution of a chlorine atom attached directly to a benzene ring.
- Multiplying step yields as percentages (80 × 55) instead of decimals, or adding them.
- Dropping a coefficient from the atom economy denominator, such as the 2 in 2NH₃.
- Reagent with no condition: “KOH” alone does not show whether substitution or elimination is wanted.
- Ignoring the major product: HBr on propene gives mainly 2-bromopropane, not 1-bromopropane.
- Giving “safer” and “less dangerous” as two separate reasons; they make one point.
- Forgetting that KCN with an aldehyde or unsymmetrical ketone gives a racemic mixture.
Official syllabus
OxfordAQA International AS and A-level Chemistry (9620) specification, Version 5.3, for International AS and A-level exams May/June 2020 onwards: section 3.3.14 Organic synthesis (International A-level only), with percentage atom economy from 3.1.2.5.
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