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Cambridge O Level Chemistry: Atoms, elements and compounds (5070)

A full study guide to elements, compounds and mixtures, atomic structure, electronic configuration and isotopes for Cambridge O Level Chemistry 5070.

Subject
Chemistry
Level
O LEVELS
Topic
Atoms, elements and compounds
Updated

Aligned to Cambridge O Level Chemistry (5070), 2026-2028. Official specification .

Syllabus page (what it covers and how it is assessed): Cambridge O Level Chemistry.

Syllabus points this page covers

5070

  • 2.1 Elements, compounds and mixtures
  • 2.2 Atomic structure and the Periodic Table
  • 2.3 Isotopes

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This study guide follows the Cambridge O Level Chemistry 5070 syllabus for examination in 2026, 2027 and 2028. It covers sections 2.1, 2.2 and 2.3 under the heading Atoms, elements and compounds: elements, compounds and mixtures; atomic structure and the Periodic Table; and isotopes. Every outcome in those three sections is taught here, in the syllabus’s own wording where possible.

Use it with the Atomic Structure revision notes, the Atomic Structure practice questions, the Cambridge O Level Chemistry hub, the printable checklist and the free 10-minute diagnostics. The examples below are new ones, so they do not repeat the examples in those pages.

What this unit covers

Section What you must be able to do
2.1 Describe the differences between elements, compounds and mixtures
2.2 (1-2) Describe the structure of the atom; state the relative charges and masses of a proton, a neutron and an electron
2.2 (3-4) Define proton number and mass number, also called atomic number and nucleon number
2.2 (5) Work out electronic configurations, for example 2,8,3, of elements and ions for proton numbers 1 to 20
2.2 (6) State three links between configuration and the Periodic Table: full outer shell in Group VIII, outer electrons equal group number (Groups I to VII), occupied shells equal period number
2.3 (1-2) Define isotopes; state why isotopes of one element have the same chemical properties
2.3 (3) Interpret and use symbols for atoms and ions
2.3 (4) Find the relative atomic mass of an element using its isotopes’ masses and abundances

2.1 Elements, compounds and mixtures

The syllabus asks you to describe the differences between the three. The useful way to learn them is to ask three questions about any sample: what is it made of, how is it joined, and how can it be split?

  • Element. Made of one kind of atom only. No chemical reaction can split it into simpler substances. Oxygen, iron and neon are elements.
  • Compound. Made of two or more different elements chemically bonded together. The atoms are present in a fixed ratio, and the compound has its own properties, which differ from those of the elements in it. Separating the elements needs a chemical reaction.
  • Mixture. Two or more substances that are not chemically bonded. The proportions can vary, each substance keeps its own properties, and the parts can be separated by physical methods.

Here is one situation that shows all three. Take iron filings and sulfur powder. Stir them together: you have a mixture. A magnet pulls the iron out, so a physical method separates it, and you can use any proportions you like. Now heat the same two elements strongly. They react to form iron(II) sulfide, a compound. The magnet no longer lifts anything out, because the iron atoms are now bonded to sulfur atoms. The ratio of iron to sulfur atoms in the compound is fixed.

Feature Element Compound Mixture
Kinds of atom One Two or more, bonded Two or more substances, not bonded
Proportions Not applicable Fixed ratio Any ratio
Properties Its own New, different from its elements Those of the parts
Separation Cannot be split chemically into simpler substances Chemical reaction needed Physical methods

Air is a good test of whether you have understood. It contains nitrogen and oxygen molecules, but they are not bonded to each other, and the proportions can change slightly from place to place. So air is a mixture, even though nitrogen and oxygen are each elements. Carbon dioxide in the same air is a compound, because its carbon and oxygen atoms are bonded in the ratio 1 to 2.

A mixture of iron and sulfur atoms, not bonded and in any ratio, has its iron pulled out by a magnet. After strong heating the atoms form iron(II) sulfide, FeS, each iron bonded to one sulfur in a fixed 1 to 1 ratio, and the magnet lifts nothing.
A magnet separates iron from a mixture with sulfur, but not from the compound iron(II) sulfide.
Three boxes of particles: an element has one type of atom; a compound has bonded atoms in a fixed 1:2 ratio, separable only chemically; a mixture has unbonded atoms in any ratio, separable physically.
An element, a compound and a mixture compared at particle level.

2.2 Atomic structure and the Periodic Table

The nuclear atom

At the centre of an atom is a tiny nucleus built from protons and neutrons. Surrounding it, electrons occupy shells. Almost all of the atom’s mass is in the nucleus, because electrons are so light.

Particle Charge (relative) Mass (relative)
Proton +1 1
Neutron 0 1
Electron -1 negligible

The syllabus asks you to state these values, so learn the table exactly. The charges on a proton and an electron are equal in size and opposite in sign. So an atom containing the same number of each carries no net charge.

Rows of positive protons and negative electrons for Be, Na+ and O2-. Be is balanced; Na+ has one unpaired proton (net +1); O2- has two unpaired electrons (net -2).
Ions form when electrons are lost or gained, not protons.
A carbon atom with a nucleus of 6 protons and 6 neutrons and electrons 2 and 4 in two shells. A table gives relative charge and mass: proton +1, 1; neutron 0, 1; electron -1, almost 0.
The nucleus holds protons and neutrons; electrons occupy shells around it.

Proton number and mass number

  • Proton number (atomic number): how many protons sit in an atom’s nucleus. It fixes which element the atom belongs to.
  • Mass number (nucleon number): protons plus neutrons together, counted across the whole nucleus.

From these, for an atom: electrons = protons, and neutrons = mass number - proton number.

When an atom becomes an ion, its nucleus stays the same and only the electron count changes. Losing electrons gives a positive ion; gaining them gives a negative ion.

Worked example 1. Work out how many protons, neutrons and electrons each of these particles contains.

Particle Protons Neutrons Electrons
beryllium atom, mass number 9, proton number 4 4 9 - 4 = 5 4
sodium ion Na⁺, mass number 23, proton number 11 11 23 - 11 = 12 11 - 1 = 10
oxide ion O²⁻, mass number 16, proton number 8 8 16 - 8 = 8 8 + 2 = 10

Check the charge each time: the sodium ion has 11 positive charges and 10 negative ones, a net +1. The oxide ion has 8 positive and 10 negative, a net -2.

The sodium-23 symbol: 23 on top is the mass number (protons plus neutrons) and 11 below is the proton number. Rows of particles show 11 protons, 12 neutrons and 11 electrons.
Mass number minus proton number gives neutrons; electrons equal protons in an atom.
A sodium atom loses one electron to become Na+ (2,8, 10 electrons); a chlorine atom gains one to become Cl- (2,8,8, 18 electrons). The nucleus (11 or 17 protons) is unchanged.
Removing or adding electrons changes the configuration and charge, never the protons.

Electronic configuration, proton numbers 1 to 20

Electrons fill the shell closest to the nucleus first. For proton numbers 1 to 20, the pattern is:

  • the first shell holds a maximum of 2
  • the second holds a maximum of 8
  • the third also holds 8 here, and after that the next electrons start the fourth shell
  • potassium and calcium put their last 1 or 2 electrons in the fourth shell

The syllabus writes configurations as a list of numbers, for example 2,8,3. Work along the shells, giving each its maximum before starting the next.

Worked example 2. Write the configuration of an atom of phosphorus (proton number 15).

Shell 1 takes 2    ->  13 electrons left
Shell 2 takes 8    ->   5 electrons left
Shell 3 takes 5    ->   0 left

The configuration is 2,8,5.

Worked example 3 (ions). Write the configuration of the calcium ion Ca²⁺ and the sulfide ion S²⁻.

  1. A calcium atom (proton number 20) is 2,8,8,2. The 2+ ion has lost two electrons, so it has 18: 2,8,8.
  2. A sulfur atom (proton number 16) is 2,8,6. The 2- ion has gained two electrons, so it has 18: 2,8,8.

Two different ions end up with the same arrangement as the noble gas argon (proton number 18, configuration 2,8,8). Their proton numbers differ, so they are still different particles. Always fill in the shells for the actual number of electrons the particle has, not the proton number of the element.

Calcium ion Ca2+ (20 protons), sulfide ion S2- (16 protons) and argon atom (18 protons) are drawn with the same 18 electrons in shells 2,8,8. Different proton numbers make them different particles, and Group VIII rules apply to atoms only.
Ca2+, S2- and Ar all have 2,8,8 but are different particles.
Phosphorus has 15 electrons filling shells 2, 8, 5. Five outer electrons give Group V and three shells give Period 3.
Filling shells for phosphorus gives 2,8,5.

Linking configuration to the Periodic Table

Three facts link configuration to position.

  1. The noble gases in Group VIII have a complete outer shell. Neon is 2,8 and argon is 2,8,8. Helium, 2, is also full because the first shell holds only 2.
  2. Outer-shell electrons match the group number, for Groups I to VII. Phosphorus, 2,8,5, has 5 outer electrons, so it is in Group V.
  3. Occupied shells match the period number. Phosphorus has three occupied shells, so it is in Period 3.
Atom Configuration Group Period
Lithium 2,1 I 2
Oxygen 2,6 VI 2
Aluminium 2,8,3 III 3
Argon 2,8,8 VIII 3
Calcium 2,8,8,2 II 4

These rules apply to atoms, not ions. The Ca²⁺ ion has configuration 2,8,8 but it is not in Group VIII. A common slip is to read the group of an ion from its charged configuration.

The first 20 elements drawn as shell diagrams in group columns and period rows, each labelled with symbol and configuration. Outer-shell electrons are gold and equal the group number; occupied shells equal the period number; Group VIII has full outer shells.
Electronic configurations 1-20 and how to read group and period from them.

2.3 Isotopes

Definition

Isotopes are atoms of one element that share a proton number but differ in neutron number. Same protons means same element. Different neutrons means different mass numbers.

Boron has two common isotopes. Both have 5 protons. One has 5 neutrons (mass number 10) and the other has 6 neutrons (mass number 11).

Why the chemistry is the same

State the reason in full. Every isotope of an element behaves the same chemically because each has an identical electron count, so the electronic configuration is identical. Chemical reactions involve electrons, and neutrons play no part. A good answer names all three links: protons are equal, so electrons are equal, so configuration is equal.

Symbols for atoms and ions

The syllabus asks you to interpret and use symbols such as the one for carbon-12 and the chloride ion. The mass number goes at the top left, the proton number at the bottom left and the charge, if any, at the top right.

Symbol Meaning Protons Neutrons Electrons
¹⁰₅B boron atom, mass number 10 5 5 5
¹¹₅B boron atom, mass number 11 5 6 5
¹⁹₉F⁻ fluoride ion 9 10 10
²⁴₁₂Mg²⁺ magnesium ion 12 12 10

Read a symbol in this order: bottom number gives protons, top minus bottom gives neutrons, then the charge tells you how far the electron count moves from the proton count.

To write a symbol from a description, check you have the numbers the right way round. “An atom with 8 protons and 10 neutrons” has proton number 8 and mass number 8 + 10 = 18, so the symbol is ¹⁸₈O.

Fluoride 19/9 F minus: 9 protons, 10 neutrons, 10 electrons. Magnesium 24/12 Mg 2 plus: 12 protons, 12 neutrons, 10 electrons.
Read the bottom number, then top minus bottom, then the charge.

Calculating relative atomic mass from isotopes

The relative atomic mass, Ar, of an element is a weighted average of the relative masses of its isotopes, using their abundances as weights. The syllabus outcome is to calculate it from the relative masses and abundances.

Ar = (mass1 x abundance1 + mass2 x abundance2 + ...) / total abundance

If abundances are given as percentages, the abundances add up to 100.

Worked example 4 (two isotopes). Boron is 19.9% ¹⁰B and 80.1% ¹¹B.

Ar = (10 x 19.9 + 11 x 80.1) / 100
   = (199 + 881.1) / 100
   = 1080.1 / 100
   = 10.801

To one decimal place, Ar = 10.8. The answer sits close to 11 because most atoms are the heavier isotope.

Worked example 5 (three isotopes). An element Z has isotopes of mass 28, 29 and 30 with abundances 92.0%, 5.0% and 3.0%.

Check: 92.0 + 5.0 + 3.0 = 100.0
Ar = (28 x 92.0 + 29 x 5.0 + 30 x 3.0) / 100
   = (2576 + 145 + 90) / 100
   = 2811 / 100
   = 28.11

Ar = 28.1 (to one decimal place). Always check the abundances add to 100 before you start. If a question gives one abundance missing, subtract from 100 first.

Quick sense check. Ar must lie between the lightest and heaviest isotope masses, and it moves towards the more abundant one. If your answer is outside that range, you have divided or weighted incorrectly. A simple average of the masses is only right when the abundances are equal.

Bar charts of isotope abundance for boron (10 and 11, 19.9% and 80.1%) and element Z (28, 29, 30 at 92.0, 5.0 and 3.0%). A triangle marks Ar = 10.8 for boron and 28.1 for Z.
Ar is the weighted balance point of isotope masses.
Chlorine-35 and chlorine-37 nuclei: both 17 protons, with 18 and 20 neutrons. Below, two identical electron arrangements, 2,8,7, show why isotopes have the same chemical properties.
Isotopes differ in neutrons and mass number but share electrons and chemistry.
100 chlorine atoms: 75 chlorine-35 and 25 chlorine-37. The weighted calculation gives 3550 / 100 = 35.5, marked on a number line nearer 35 than the plain average of 36, which is wrong.
Relative atomic mass is a weighted average of isotope masses.

Common errors

  • Mixing up the two numbers. Proton number is the smaller number at the bottom of the symbol. Mass number is the larger number at the top.
  • Using the proton number to fill shells for an ion. Fill shells with the number of electrons the ion has.
  • Calling air or seawater a compound. If the proportions can vary and the parts are not bonded, it is a mixture.
  • Reading a group number from an ion. Group and period rules refer to the neutral atom.
  • Forgetting that Group VIII includes helium, 2. A full outer shell for helium means 2 electrons, not 8.
  • Writing “different number of protons” in an isotope definition. Isotopes differ in neutrons only.
  • Not weighting by abundance. A plain average is wrong unless the isotopes are equally abundant.
  • Dividing by the number of isotopes instead of 100. With percentages, divide by 100.

Next steps

Work through the Atomic Structure practice questions, then use the revision notes for recall. Check the printable checklist and the Cambridge O Level Chemistry hub. To see where you stand, try the free 10-minute diagnostics.

Frequently asked questions

Which syllabus sections does this Cambridge O Level 5070 guide cover? It covers sections 2.1, 2.2 and 2.3 of the Cambridge O Level Chemistry 5070 syllabus for examination in 2026, 2027 and 2028: elements, compounds and mixtures, atomic structure, and isotopes.

Is air a compound or a mixture? Air is a mixture. Its proportions can vary and its parts are not chemically bonded together, so it is not a compound; the same applies to seawater.

How many electrons are in the outer shell of helium? Helium is in Group VIII but has only 2 electrons, which is a full outer shell for the first shell. It does not have 8 outer electrons.

How do you fill electron shells for an ion? Use the number of electrons the ion actually has, not the proton number. Group and period rules refer to the neutral atom, not the ion.

Official syllabus

Cambridge O Level Chemistry 5070 syllabus for examination in 2026, 2027 and 2028, published by Cambridge International. Sections 2.1, 2.2 and 2.3.

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