Skip to content
Marlbridge

Revision Notes

OCR A Level Chemistry A: Acids, 2.1.4 (H432) – Revision Notes

Revision notes for OCR A Level Chemistry A 2.1.4 Acids: formulae, strong and weak acids, neutralisation equations, titration method and a self-test.

Subject
Chemistry
Level
A LEVELS
Topic
Foundations in chemistry
Updated

Aligned to OCR A Level Chemistry (H432), Version 3.1 (May 2026), for first assessment in 2017. Official specification .

Syllabus page (what it covers and how it is assessed): OCR A Level Chemistry.

Syllabus points this page covers

H432

  • 2.1.4 Acids

Found an error? Report a correction.

Need help with this topic? Request a free trial class for A Level Chemistry (H432).

For the full explanation, read the 2.1.4 Acids study guide first. These notes are for the final weeks.

They cover section 2.1.4, Acids, of the OCR A Level Chemistry A (H432) specification, Version 3.1 (May 2026), for first assessment in 2017. The section sits in Module 2, Foundations in chemistry, and has five learning outcomes, (a) to (e). The assessment overview says components 01 and 02 both assess Module 2, and component 03 assesses all six modules. H432 is the full A level.

Course hub: OCR A Level chemistry. Progress tracker: printable checklist. Gap finder: free diagnostics. Exam-style practice: 2.1.4 practice questions. The calculations rest on Amount of substance (2.1.3). Later, the quantitative side of weak acids appears in Acids, bases and buffers.

The five outcomes at a glance

Outcome What you must be able to do
(a) Give formulae of common acids and alkalis; link acids to H⁺ and alkalis to OH⁻ in aqueous solution
(b) Explain strong and weak acids qualitatively, in terms of relative dissociation
(c) Describe neutralisation as H⁺ + OH⁻ → H₂O, and as acid + base → salt, with full equations
(d) Know the techniques for making a standard solution and carrying out a titration (PAG2)
(e) Do structured and non-structured titration calculations, including unfamiliar acids and bases

(a) Formulae and ions

Acid Formula Alkali Formula
Hydrochloric HCl Sodium hydroxide NaOH
Sulfuric H₂SO₄ Potassium hydroxide KOH
Nitric HNO₃ Ammonia (aqueous) NH₃
Ethanoic CH₃COOH
  • An acid releases H⁺ ions in aqueous solution.
  • An alkali releases OH⁻ ions in aqueous solution.
  • NaOH and KOH supply OH⁻ directly. Ammonia produces it by reacting with water: NH₃ + H₂O ⇌ NH₄⁺ + OH⁻.
  • A base neutralises an acid. An alkali is a base that dissolves in water. Every alkali is a base; CuO and CaCO₃ are bases but not alkalis.
  • Salt names follow the acid: hydrochloric gives chlorides, sulfuric gives sulfates, nitric gives nitrates, ethanoic gives ethanoates.

(b) Strong and weak acids

Strong acid Weak acid
Dissociation Almost completely dissociated Partially dissociated
Arrow → ⇌
Example HCl → H⁺ + Cl⁻ CH₃COOH ⇌ CH₃COO⁻ + H⁺
Mostly present as Ions Undissociated molecules

Strength and concentration are different ideas.

  • Strength is the extent of dissociation. It is a property of the acid.
  • Concentration is the amount dissolved per dm³. It is a property of the solution.
  • A dilute strong acid and a concentrated weak acid can both exist. Do not call the concentrated weak acid “stronger”.
  • Equal volumes of equal-concentration HCl and CH₃COOH contain the same amount of acid. They neutralise the same amount of alkali, because the equilibrium in the weak acid shifts to release more H⁺ as H⁺ is used up.
Two grids of 100 acid particles at 0.100 M. In HCl all 100 are split into ions (pH 1.00). In ethanoic acid only 1 of 100 is split (pH 2.88).
A strong acid splits almost completely into ions; a weak acid only slightly, even at the same concentration.
A graph of pH against concentration for chloroethanoic acid shows a dashed shortcut line and a solid true line separating as the acid is diluted. At 0.0100 M the shortcut gives 2.43 but the true pH is 2.51.
At 0.0100 M chloroethanoic acid the shortcut implies about 37% dissociation, so [HA] is not unchanged and the true pH is 2.51 (OCR only).
Four computed curves of pH against base added for 25 cm3 of 0.100 M acid with 0.100 M base. Strong+strong starts at pH 1 and is equivalent at pH 7. Weak acid+strong base starts near 2.9, buffers, and is equivalent near 8.7. Strong acid+weak base is equivalent near 5.3. Weak+weak has no steep section.
Strong or weak acids and bases give curves with different start pH, steep section and equivalence pH.
A computed pH curve for ethanoic acid with NaOH shows the buffer region and equivalence at 25 cm3. At 12.5 cm3 dashed lines show pH 4.76 = pKa, because [HA] = [A-] there.
At half the equivalence volume [HA] = [A-], so pH = pKa and Ka = 10^-pH (practical in all boards).

(c) Neutralisation

Ionic equation for any acid with an alkali: H⁺(aq) + OH⁻(aq) → H₂O(l)

Reactants Products Example (full equation)
Acid + alkali Salt + water H₂SO₄ + 2KOH → K₂SO₄ + 2H₂O
Acid + metal oxide Salt + water MgO + 2HNO₃ → Mg(NO₃)₂ + H₂O
Acid + carbonate Salt + water + carbon dioxide Na₂CO₃ + H₂SO₄ → Na₂SO₄ + H₂O + CO₂
Acid + ammonia Ammonium salt only NH₃ + HCl → NH₄Cl

Method in steps for a full equation:

  1. Name the salt: metal (or NH₄⁺) from the base, anion from the acid.
  2. Write the salt formula so the charges balance, for example Mg²⁺ with NO₃⁻ gives Mg(NO₃)₂.
  3. Add the other products: H₂O for oxides and alkalis, H₂O and CO₂ for carbonates.
  4. Balance, then add state symbols if asked.

Ammonia has no water product because it adds H⁺ to form NH₄⁺ rather than removing it as H₂O.

(d) Techniques

Making a standard solution

A standard solution has an accurately known concentration. Worked reminder: 250.0 cm³ of 0.0500 mol dm⁻³ sodium carbonate, Na₂CO₃ (M = 106.0 g mol⁻¹).

n = 0.2500 dm³ × 0.0500 mol dm⁻³ = 0.01250 mol
m = 0.01250 mol × 106.0 g mol⁻¹ = 1.325 g
  1. Weigh the solid by difference, using a weighing bottle or boat on a balance.
  2. Tip it into a beaker and add distilled water, stirring until it dissolves.
  3. Transfer to a volumetric flask through a funnel. Wash the beaker and funnel into the flask with distilled water.
  4. Fill until the bottom of the meniscus touches the mark.
  5. Stopper and invert several times to mix.

Titration

  1. Rinse the burette with the solution it will hold, then fill it, including below the tap. Remove the funnel.
  2. Measure the aliquot (for example 25.0 cm³) with a pipette into a conical flask. Add a few drops of indicator.
  3. Do a rough titration first, then repeat with dropwise addition near the end point.
  4. Read the burette at the bottom of the meniscus, at eye level.
  5. Repeat until titres agree closely (concordant). Average only those.

Indicator colours: methyl orange is red in acid and yellow in alkali. Phenolphthalein is colourless in acid and pink in alkali.

For each titration type the steep section is shaded and four indicators are drawn as colour ranges. Only indicators fully inside the shaded section get a tick: all four for strong+strong, phenolphthalein for weak acid+strong base, methyl orange and methyl red for strong acid+weak base.
An indicator is suitable only if its whole colour-change range lies inside the steep section of the curve.

(e) Calculations

Method in steps:

  1. Write the balanced equation.
  2. Moles of the known solution = concentration × volume (dm³).
  3. Use the equation ratio to find moles of the unknown.
  4. Divide by its volume (dm³) for concentration. Multiply by M for g dm⁻³.
  5. If the sample was diluted or made up to a larger volume, scale up at the end.

Common ratios:

Reaction Ratio
HCl or HNO₃ with NaOH or KOH 1 : 1
H₂SO₄ with NaOH or KOH 1 : 2
2HCl with Ca(OH)₂ 2 : 1
H₂SO₄ with NH₃ 1 : 2
2HCl with Na₂CO₃ 2 : 1

Worked reminder: an alkali that releases two OH⁻

Ca(OH)₂ + 2HNO₃ → Ca(NO₃)₂ + 2H₂O. A 25.0 cm³ sample of limewater is titrated with 0.0500 mol dm⁻³ HNO₃. Titres: 19.10 (rough), 18.45, 18.35 and 18.40 cm³.

mean of concordant titres = (18.45 + 18.35 + 18.40) / 3 = 18.40 cm³
n(HNO₃) = 0.01840 dm³ × 0.0500 = 9.20 × 10⁻⁴ mol
n(Ca(OH)₂) = 9.20 × 10⁻⁴ / 2 = 4.60 × 10⁻⁴ mol
c = 4.60 × 10⁻⁴ / 0.0250 dm³ = 0.0184 mol dm⁻³
g dm⁻³ = 0.0184 × 74.1 = 1.36 g dm⁻³

Back titration (non-structured style)

Use it when a base is insoluble or reacts slowly.

  1. Add a known excess of acid to the sample.
  2. Titrate the leftover acid with standard alkali.
  3. Moles reacted with the sample = moles added minus moles left over.
  4. Convert to the sample using the equation ratio.

Unfamiliar acids and bases

You will not be given the method. Write the equation from the information in the question: a dibasic acid H₂X releases two H⁺, so it reacts 1 : 2 with NaOH. Treat it like any other ratio.

Water (acid, two H) and ammonia (base, three H) are shown with a gold arrow carrying one proton from water to ammonia. The products are hydroxide (conjugate base, one H) and ammonium (conjugate acid, four H). Members of each conjugate pair differ by exactly one H.
In NH3 + H2O the acid H2O gives a proton to the base NH3; each acid and its conjugate base differ by one H+.

Must-know distinctions

  • Base and alkali: all alkalis are bases, not all bases are alkalis.
  • Strong and concentrated: strength is extent of dissociation; concentration is amount per dm³.
  • Rough and accurate titres: the rough titre guides you but is not averaged.
  • Moles of acid and moles of H⁺: H₂SO₄ gives up to two H⁺ per molecule, so the ratio changes.

Quick self-test

  1. Give the formula of nitric acid and the ion that makes it an acid in water.
  2. Why is aqueous ammonia classed as an alkali?
  3. In one sentence, what makes an acid weak?
  4. Write the full equation for magnesium oxide with nitric acid.
  5. Write the full equation for sodium carbonate with sulfuric acid.
  6. Write the equation for ammonia with hydrochloric acid and name the product.
  7. What mass of Na₂CO₃ (M = 106.0) is needed for 500.0 cm³ of 0.0200 mol dm⁻³ solution?
  8. What volume of 0.125 mol dm⁻³ H₂SO₄ neutralises 20.0 cm³ of 0.250 mol dm⁻³ KOH?
  9. Titres of 13.10 (rough), 12.20 and 12.30 cm³ are recorded. What is the mean titre to use?
  10. What volume of 0.0500 mol dm⁻³ HCl neutralises 25.0 cm³ of 0.0300 mol dm⁻³ Ba(OH)₂?
  11. A student says a 0.001 mol dm⁻³ solution of HCl is a weaker acid than 1 mol dm⁻³ ethanoic acid. Is the wording correct?

Answers

  1. HNO₃; it releases H⁺.
  2. It produces OH⁻ by reacting with water: NH₃ + H₂O ⇌ NH₄⁺ + OH⁻.
  3. It is only partially dissociated in aqueous solution.
  4. MgO + 2HNO₃ → Mg(NO₃)₂ + H₂O
  5. Na₂CO₃ + H₂SO₄ → Na₂SO₄ + H₂O + CO₂
  6. NH₃ + HCl → NH₄Cl; ammonium chloride.
  7. n = 0.5000 × 0.0200 = 0.0100 mol; m = 0.0100 × 106.0 = 1.06 g.
  8. n(KOH) = 0.0200 × 0.250 = 5.00 × 10⁻³ mol; n(H₂SO₄) = 2.50 × 10⁻³ mol; V = 2.50 × 10⁻³ / 0.125 = 0.0200 dm³ = 20.0 cm³.
  9. Mean of 12.20 and 12.30 = 12.25 cm³; the rough titre is excluded.
  10. n(OH⁻) = 2 × 0.0300 × 0.0250 = 1.50 × 10⁻³ mol; n(HCl) is the same; V = 1.50 × 10⁻³ / 0.0500 = 0.0300 dm³ = 30.0 cm³.
  11. No. HCl is a strong acid; the solution is dilute. Strength is about dissociation, and the comparison should be of concentration.
Two panels show equal bars of H+ and OH- in pure water. At 25 C each is 1.00e-7 and pH is 7.00; at 50 C each is 2.35e-7 and pH is 6.63. The bars are equal in both, so the water is neutral.
Kw rises with temperature, lowering the pH of pure water, but [H+] = [OH-] so it stays neutral.

Where marks are usually lost

  • Writing “weak acid = low pH” or “less acidic” instead of “partially dissociated”.
  • Writing a single arrow for a weak acid, or an equilibrium arrow for HCl.
  • Omitting CO₂ or H₂O from a carbonate equation, or writing H₂O as a product of ammonia with an acid.
  • Forgetting that H₂SO₄ reacts 1 : 2 with a monohydroxide, so the answer is out by a factor of two.
  • Averaging the rough titre, or titres that do not agree closely.
  • Using cm³ in n = c × V without dividing by 1000.
  • Describing a standard solution made by adding water to a measuring cylinder or by filling to the mark in the beaker.
  • Calling every base an alkali.
  • Forgetting to scale up when only an aliquot of a made-up solution was titrated.
A beaker holds eight HA and six A- particles (0.200 mol HA, 0.150 mol A-, pH 4.63). Adding a little H+ turns A- into HA and moves pH to 4.58; adding a little OH- turns HA into A- and moves pH to 4.68. Water would fall from 7 to 2.00.
Both HA and A- are plentiful, so adding a little acid or alkali barely changes their ratio or the pH.

Frequently asked questions

What is the difference between a base and an alkali in OCR A Level Chemistry? A base neutralises an acid, and an alkali is a base that dissolves in water to release OH⁻ ions. Every alkali is a base, but copper(II) oxide and calcium carbonate are bases that are not alkalis.

What is the difference between a strong acid and a concentrated acid? Strength is the extent of dissociation and is a property of the acid. Concentration is the amount dissolved per dm³ and is a property of the solution.

Do HCl and CH₃COOH of the same concentration neutralise the same amount of alkali? Yes. Equal volumes of equal-concentration HCl and CH₃COOH contain the same amount of acid, so they neutralise the same amount of alkali even though their strengths differ.

What ratio does sulfuric acid react in with sodium hydroxide? H₂SO₄ reacts 1 : 2 with a monohydroxide such as NaOH, because it gives up to two H⁺ ions per molecule. Missing this puts the answer out by a factor of two.

Official syllabus

OCR A Level Chemistry A (H432) specification, Version 3.1 (May 2026), for first assessment in 2017, section 2.1.4 Acids, learning outcomes (a) to (e), with additional guidance PAG2 and HSW4. Published by OCR.

Get free revision emails (optional)

Occasional emails with practice questions, worked explanations and links to free resources for the qualification and subjects you choose. No spam, and you can unsubscribe from any email. The free tools on this site never need an email.

Subjects (optional, up to 6)

Choose a qualification to see its subjects.

Related resources

Related articles

Studying this with a teacher

Working through Chemistry A LEVELS?

This page is free and stays free. If you would rather be taught it, Marlbridge runs Chemistry classes one-to-one, online in your own time zone. One-to-one only for this course: Rs 6,000 per class in Pakistan, with other currencies on the fees page. The first trial class is free. WhatsApp replies within an hour (8am–11pm Pakistan time, every day); email the same day.